NCERT Solutions for Class 10 Maths Chapter 4 Exercise 4.3

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Jasmine Grover

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NCERT Solutions for Class 10 Maths Chapter 4 Quadratic Equations Exercise 4.3 is given in this article with step by step explanation. Class 10 Maths Chapter 4 Exercise 4.3 has eleven questions on the different ways to calculate the unknown values of x.

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Check out the solutions of Class 10 Maths NCERT solutions chapter 4 Quadratic Equations 4.3

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Class 10 Chapter 4 Topics:

CBSE Class 10 Maths Study Guides:

CBSE X Related Questions

  • 1.
    Assertion (A) : H.C.F. \((36 m^{2}, 18 m) = 18 m\), where \(m\) is a prime number.
    Reason (R) : H.C.F. of two numbers is always less than or equal to the smaller number.

      • Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of the Assertion (A).
      • Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of the Assertion (A).
      • Assertion (A) is true, but Reason (R) is false.
      • Assertion (A) is false, but Reason (R) is true.

    • 2.
      There are two sections A and B of Grade X. There are 28 students in Section A and 30 students in Section B. What is the minimum number of books you will acquire for the class library so that they can be distributed equally among students of Section A or Section B ?

        • 144
        • 2
        • 420
        • 272

      • 3.
        In the given figure, $PQ$ is tangent to the circle with centre $O$. $S$ is a point on the circle such that $\angle SQT = 55^\circ$. The $m\angle QPS$ is

          • $55^\circ$
          • $20^\circ$
          • $35^\circ$
          • $70^\circ$

        • 4.
          The value of k for which sum of the zeroes of the polynomial \(p(x) = 3x^2 - kx + 6\) is 2, is

            • 2
            • \(-6\)
            • \(-2\)
            • 6

          • 5.
            In an A.P., if $a_{14} - a_8 = 24$, then the common difference of the A.P. is

              • $6$
              • $4$
              • $\pm 4$
              • $3$

            • 6.
              If \(PQ\) and \(PR\) are tangents to the circle with centre \(O\) and radius \(4 \text{ cm}\) such that \(\angle QPR = 90^{\circ}\), then the length \(OP\) is

                • \(4 \text{ cm}\)
                • \(4\sqrt{2} \text{ cm}\)
                • \(8 \text{ cm}\)
                • \(2\sqrt{2} \text{ cm}\)

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