NCERT Solutions for Class 10 Maths Chapter 1 Real Numbers Exercise 1.1

Jasmine Grover logo

Jasmine Grover

Education Journalist | Study Abroad Lead

NCERT Solutions for Class 10 Maths Chapter 1 Real Numbers Exercise 1.1 is covered in this article with a step by step explanation. Chapter 1 Real Numbers Exercise 1.1 covers basic concepts of divisibility of integers using Euclid’s division algorithm. Euclid’s division algorithm says that any positive integer a can be divided by another positive integer b in a way that the remainder will be smaller than b.

Download PDF: NCERT Solutions for Class 10 Maths Chapter 1 Exercise 1.1

Check out the solutions of Class 10 Maths NCERT solutions chapter 1 Real Numbers Exercise 1.1:

Read More: NCERT Solutions For Class 10 Maths Real Numbers

Check out other exercise solutions of Class 10 Maths Chapter 1 Real Numbers

Also Read:

Also Read:

CBSE X Related Questions

  • 1.
    A circle centered at (2, 1) passes through the points A(5, 6) and B(-3, K). Find the value(s) of K. Hence find length of chord AB.


      • 2.
        The HCF of 960 and 432 is :

          • 48
          • 54
          • 72
          • 36

        • 3.
          A bag contains 25 balls. Some of them are yellow and others are green. One ball is drawn at random. If probability of getting a green ball is \(3/5\), then find the number of yellow balls.


            • 4.
              The value of \(p\) for which roots of the quadratic equation \(x^{2} - px + 6 = 0\) are rational, is

                • \(1\)
                • \(-5\)
                • \(25\)
                • \(\sqrt{5}\)

              • 5.
                In a class test, the sum of Anamika's marks obtained in Maths and Science is 30. Had she got 2 marks more in Maths and 3 marks less in Science, the product of the marks would have been 210. Find the marks she got in the two subjects.


                  • 6.
                    If \(PQ\) and \(PR\) are tangents to the circle with centre \(O\) and radius \(4 \text{ cm}\) such that \(\angle QPR = 90^{\circ}\), then the length \(OP\) is

                      • \(4 \text{ cm}\)
                      • \(4\sqrt{2} \text{ cm}\)
                      • \(8 \text{ cm}\)
                      • \(2\sqrt{2} \text{ cm}\)

                    Comments


                    No Comments To Show