NCERT Solutions for Class 10 Maths Chapter 1 Real Numbers Exercise 1.4

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Jasmine Grover

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NCERT Solutions for Class 10 Maths Chapter 1 Real Numbers Exercise 1.4 deals with the concepts of rational numbers and their decimal expansions. The exercise has 3 short questions of the exercise discussing when the decimal expansion of a rational number is terminating and when it is non-terminating.

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CBSE X Related Questions

  • 1.
    A bag contains 25 balls. Some of them are yellow and others are green. One ball is drawn at random. If probability of getting a green ball is \(3/5\), then find the number of yellow balls.


      • 2.
        There are two sections A and B of Grade X. There are 28 students in Section A and 30 students in Section B. What is the minimum number of books you will acquire for the class library so that they can be distributed equally among students of Section A or Section B ?

          • 144
          • 2
          • 420
          • 272

        • 3.
          \(ABCD\) is a parallelogram such that \(AF = 7 \text{ cm}\), \(FB = 3 \text{ cm}\) and \(EF = 4 \text{ cm}\), length \(FD\) equals

            • \(\frac{21}{4} \text{ cm}\)
            • \(\frac{28}{3} \text{ cm}\)
            • \(\frac{12}{7} \text{ cm}\)
            • \(5.5 \text{ cm}\)

          • 4.
            If \( \alpha, \beta \) are the zeroes of the quadratic polynomial \( px^2 + qx + r \), then find the value of \( \alpha^3\beta + \beta^3\alpha \).


              • 5.
                If the pair of linear equations : \( a_1x + b_1y + c_1 = 0 \) and \( a_2x + b_2y + c_2 = 0 \) is consistent and dependent, then

                  • \( \frac{a_1}{a_2} \neq \frac{b_1}{b_2} \)
                  • \( \frac{a_1}{a_2} = \frac{b_1}{b_2} = \frac{c_1}{c_2} \)
                  • \( \frac{a_1}{a_2} = \frac{b_1}{b_2} \neq \frac{c_1}{c_2} \)
                  • \( \frac{a_1}{a_2} = \frac{b_1}{b_2} = \frac{c_1}{c_2} \)

                • 6.
                  If the quadratic equation \(9x^2 + 8kx + 16 = 0\) has real and equal roots, then the value of k is

                    • 3
                    • –3
                    • –4
                    • \(\pm 3\)

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