NCERT Solutions for Class 10 Maths Chapter 12 Exercise 12.1

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NCERT Solutions for Class 10 Maths Chapter 12 Areas Related to Circles Exercise 12.1 Solutions are based on Perimeter And Area Of A Circle.

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Exercise Solutions of Class 10 Maths Chapter 12 Areas Related to Circles

Also check other Exercise Solutions of Class 10 Maths Chapter 12 Areas Related to Circles

NCERT Solutions For Class 10 Maths Chapter 12 Exercise 12.2 Solutions

NCERT Solutions For Class 10 Maths Chapter 12 Exercise 12.3 Solutions

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Chapter Related Topics
Circumference of Circle	Areas Related to Circles Formula	Areas Related to Circles Revision Notes
Area of Sector	Sector Of A Circle	Area of Segment of a Circle
Circle Formula	Area of a Circle Formula	Arc Length Formula
Mathematics diameter formula	Central Angle of a Circle Formula	Radius of a Circle

Also Check:

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Math Formula	NCERT Solutions for Class 10 Maths	Algebra

CBSE X Related Questions

1.
\(ABCD\) is a parallelogram such that \(AF = 7 \text{ cm}\), \(FB = 3 \text{ cm}\) and \(EF = 4 \text{ cm}\), length \(FD\) equals
- \(\frac{21}{4} \text{ cm}\)
- \(\frac{28}{3} \text{ cm}\)
- \(\frac{12}{7} \text{ cm}\)
- \(5.5 \text{ cm}\)
View Solution
2.
A bag contains 25 balls. Some of them are yellow and others are green. One ball is drawn at random. If probability of getting a green ball is \(3/5\), then find the number of yellow balls.
View Solution
3.
In a class test, the sum of Anamika's marks obtained in Maths and Science is 30. Had she got 2 marks more in Maths and 3 marks less in Science, the product of the marks would have been 210. Find the marks she got in the two subjects.
View Solution
4.
A circle centered at (2, 1) passes through the points A(5, 6) and B(-3, K). Find the value(s) of K. Hence find length of chord AB.
View Solution
5.
In the given figure, \(AB \parallel DE\) and \(AC \parallel DF\). Show that \(\triangle ABC \sim \triangle DEF\). If \(BC = 10\) cm, \(EB = CF = 5\) cm and \(AB = 7\) cm, then find the length DE.
View Solution
6.
The HCF of 960 and 432 is :
- 48
- 54
- 72
- 36
View Solution

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NCERT Solutions For Class 10 mathematics Chapter 12: Areas Related to Circles

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NCERT Solutions for Class 10 Maths Chapter 12 Exercise 12.2

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NCERT Solutions for Class 10 Maths Chapter 12 Exercise 12.1

Exercise Solutions of Class 10 Maths Chapter 12 Areas Related to Circles

CBSE X Related Questions

1.
\(ABCD\) is a parallelogram such that \(AF = 7 \text{ cm}\), \(FB = 3 \text{ cm}\) and \(EF = 4 \text{ cm}\), length \(FD\) equals

2.
A bag contains 25 balls. Some of them are yellow and others are green. One ball is drawn at random. If probability of getting a green ball is \(3/5\), then find the number of yellow balls.

3.
In a class test, the sum of Anamika's marks obtained in Maths and Science is 30. Had she got 2 marks more in Maths and 3 marks less in Science, the product of the marks would have been 210. Find the marks she got in the two subjects.

4.
A circle centered at (2, 1) passes through the points A(5, 6) and B(-3, K). Find the value(s) of K. Hence find length of chord AB.

5.
In the given figure, \(AB \parallel DE\) and \(AC \parallel DF\). Show that \(\triangle ABC \sim \triangle DEF\). If \(BC = 10\) cm, \(EB = CF = 5\) cm and \(AB = 7\) cm, then find the length DE.

6.
The HCF of 960 and 432 is :

Similar Mathematics Concepts

Comments

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NCERT Solutions for Class 10 Maths Chapter 12 Exercise 12.1

Exercise Solutions of Class 10 Maths Chapter 12 Areas Related to Circles

CBSE X Related Questions

1.\(ABCD\) is a parallelogram such that \(AF = 7 \text{ cm}\), \(FB = 3 \text{ cm}\) and \(EF = 4 \text{ cm}\), length \(FD\) equals

2.A bag contains 25 balls. Some of them are yellow and others are green. One ball is drawn at random. If probability of getting a green ball is \(3/5\), then find the number of yellow balls.

3.In a class test, the sum of Anamika's marks obtained in Maths and Science is 30. Had she got 2 marks more in Maths and 3 marks less in Science, the product of the marks would have been 210. Find the marks she got in the two subjects.

4.A circle centered at (2, 1) passes through the points A(5, 6) and B(-3, K). Find the value(s) of K. Hence find length of chord AB.

5.In the given figure, \(AB \parallel DE\) and \(AC \parallel DF\). Show that \(\triangle ABC \sim \triangle DEF\). If \(BC = 10\) cm, \(EB = CF = 5\) cm and \(AB = 7\) cm, then find the length DE.

6.The HCF of 960 and 432 is :

Similar Mathematics Concepts

Comments

SUBSCRIBE TO OUR NEWS LETTER

1.
\(ABCD\) is a parallelogram such that \(AF = 7 \text{ cm}\), \(FB = 3 \text{ cm}\) and \(EF = 4 \text{ cm}\), length \(FD\) equals

2.
A bag contains 25 balls. Some of them are yellow and others are green. One ball is drawn at random. If probability of getting a green ball is \(3/5\), then find the number of yellow balls.

3.
In a class test, the sum of Anamika's marks obtained in Maths and Science is 30. Had she got 2 marks more in Maths and 3 marks less in Science, the product of the marks would have been 210. Find the marks she got in the two subjects.

4.
A circle centered at (2, 1) passes through the points A(5, 6) and B(-3, K). Find the value(s) of K. Hence find length of chord AB.

5.
In the given figure, \(AB \parallel DE\) and \(AC \parallel DF\). Show that \(\triangle ABC \sim \triangle DEF\). If \(BC = 10\) cm, \(EB = CF = 5\) cm and \(AB = 7\) cm, then find the length DE.

6.
The HCF of 960 and 432 is :