NCERT Solutions for Class 10 Maths Chapter 12 Exercise 12.1

CBSE X Related Questions

  • 1.
    In the given figure, \(AB \parallel EF\). If \(AB = 24\) cm, \(EF = 36\) cm and \(DA = 7\) cm, then \(AE\) equals

      • \(2.5\) cm
      • \(10.5\) cm
      • \(3.5\) cm
      • \(\frac{14}{3}\) cm

    • 2.
      Prove that : \( \frac{\sec^3 \theta}{\sec^2 \theta - 1} + \frac{\text{cosec}^3 \theta}{\text{cosec}^2 \theta - 1} = \sec \theta \cdot \text{cosec} \theta (\sec \theta + \text{cosec} \theta) \)


        • 3.
          In the figure given above, \(\triangle ABC \sim \triangle XYZ\), then find the values of \(x\) and \(y\).


            • 4.
              The HCF of 960 and 432 is :

                • 48
                • 54
                • 72
                • 36

              • 5.
                If \( \alpha, \beta \) are the zeroes of the quadratic polynomial \( px^2 + qx + r \), then find the value of \( \alpha^3\beta + \beta^3\alpha \).


                  • 6.
                    Find the H.C.F. and L.C.M. of 1530 and 2040.

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