NCERT Solutions for Class 10 Maths Chapter 12 Exercise 12.3

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NCERT Solutions for Class 10 Maths Chapter 12 Areas Related to Circles Exercise 12.3 Solutions are based on calculation of areas of some combinations of plane figures which are available in daily life (window designs, bedsheets designs, carpet designs, etc. through some examples.

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CBSE X Related Questions

  • 1.
    The graph of a quadratic polynomial f(x) passes through (5,0), (0, -1) and (-2, 0). The two factors of the polynomial are

      • \((x + 2), (x - 5)\)
      • \((x + 5), (x - 2)\)
      • \((x + 1), (x - 5)\)
      • \((x - 1), (x + 2)\)

    • 2.
      Mean and Median of a frequency distribution are 43 and 40 respectively. The value of mode is

        • 34
        • 43
        • 38.5
        • 41.5

      • 3.
        The value of k for which sum of the zeroes of the polynomial \(p(x) = 3x^2 - kx + 6\) is 2, is

          • 2
          • \(-6\)
          • \(-2\)
          • 6

        • 4.
          Arc \(PQ\) subtends an angle \(\theta\) at the centre of the circle with radius \(6.3 \text{ cm}\). If \(\text{Arc } PQ = 11 \text{ cm}\), then the value of \(\theta\) is

            • \(10^{\circ}\)
            • \(60^{\circ}\)
            • \(45^{\circ}\)
            • \(100^{\circ}\)

          • 5.
            If the zeroes of the polynomial \(p(x) = 2x^2 - 7x + 6\) are \(\alpha\) and \(\beta\), then the value of \(\frac{1}{\alpha} + \frac{1}{\beta}\) is

              • \(\frac{7}{2}\)
              • \(\frac{6}{7}\)
              • \(\frac{-7}{6}\)
              • \(\frac{7}{6}\)

            • 6.
              If \(PQ\) and \(PR\) are tangents to the circle with centre \(O\) and radius \(4 \text{ cm}\) such that \(\angle QPR = 90^{\circ}\), then the length \(OP\) is

                • \(4 \text{ cm}\)
                • \(4\sqrt{2} \text{ cm}\)
                • \(8 \text{ cm}\)
                • \(2\sqrt{2} \text{ cm}\)

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