NCERT Solutions For Class 11 Physics Chapter 12: Thermodynamics

NCERT Solutions for Class 11 Physics Chapter 12 Thermodynamics are given in this article. Thermodynamics is a branch of physics that deals with the study of the transformation of heat energy into several other forms of energy. For example, when we rub our palms together, the work done in rubbing produces heat. This process of rubbing hands denotes a Thermodynamic process.

Class 11 Physics Chapter 12 Thermodynamics is of Unit 8 which has a weightage of 20 marks along with unit 7 and Unit 9. Class 11 NCERT Solutions for Chapter 12 cover important concepts of laws of thermodynamicsCarnot Cycle, Born Haber Cycleand Enthalpy.

Download PDF: NCERT Solutions for Class 11 Physics Chapter 12


NCERT Solutions for Class 11 Physics Chapter 12

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Class 11 Physics Chapter 12 – Concepts Covered

  • Thermodynamics is the branch of physics that deals with the study of the transformation of heat into other forms of energy and vice-versa.
A collection of a large number of atoms or molecules confined within certain boundaries in a way that it has specific values of pressure (P), volume (V) and temperature (T) is known as a thermodynamic system.
  • Zeroth Law of Thermodynamics identifies thermal equilibrium and introduces the concept of temperature as a tool for identifying equilibrium. 
If two systems are in thermal equilibrium with a third system then those two systems themselves are in equilibrium with each other.
  • Work is said to be done if a system moves a certain distance in the direction of the applied force.
It is given as dW = PdV
where P refers to the pressure of the gas in the cylinder.

The total change in heat energy in any system is the sum of the work done and the change in internal energy.

  • Second Law of Thermodynamics is the principle that disallows certain phenomena that are consistent with the First law of thermodynamics.
The two statements of second law of thermodynamics are as follows – 
- Kelvin-Planck Statement: It is impossible to form an engine, operating in a cycle, to extract heat from a hot body and then convert it completely into work without leaving change anywhere i.e., 100% conversion of heat into work is not possible.
- Clausius Statement: It is impossible for a self acting machine, operating in a cycle, without the help of any external energy to transfer heat from a cold body to a hot body. Heat can not flow itself from a colder body to a hotter body.

CBSE CLASS XII Related Questions

  • 1.
    A long solenoid of length \( L \) and radius \( r_1 \) having \( N_1 \) turns is surrounded symmetrically by a coil of radius \( r_2 \, (r_2>r_1) \) having \( N_2 \) turns (\( N_2 \ll N_1 \)) around its mid-point. Derive an expression for the mutual inductance of solenoid and coil. Is \( M_{12} = M_{21} \) valid in this case?


      • 2.
        Write the expression for the magnetic field due to a current element in vector form. Consider a 1 cm segment of a wire, centered at the origin, carrying a current of 10 A in positive x-direction. Calculate the magnetic field \( \mathbf{B} \) at a point \( (1 \, \text{m}, 1 \, \text{m}, 0) \).


          • 3.
            If Bohr’s quantization postulate (angular momentum \( = \frac{nh}{2\pi} \)) is a basic law of nature, it should be equally valid for the case of planetary motion also. Why, then, do we never speak of quantization of orbits of planets around the Sun? Explain.


              • 4.
                What is displacement current (\( i_d \))? Considering the case of charging of a capacitor, show that \( i_d = \varepsilon_0 \frac{d\Phi_E}{dt} \). What is the value of \( i_d \) for a conductor across which a constant voltage is applied?


                  • 5.
                    Suppose a pure Si crystal has \( 5 \times 10^{28} \) atoms per \( \text{m}^3 \). It is doped with \( 5 \times 10^{22} \) atoms per \( \text{m}^3 \) of Arsenic. Calculate majority and minority carrier concentration in the doped silicon. (Given: \( n_i = 1.5 \times 10^{16} \, \text{m}^{-3} \))


                      • 6.
                        Two small identical metallic balls having charges \( q \) and \( -2q \) are kept far at a separation \( r \). They are brought in contact and then separated at distance \( \frac{r}{2} \). Compared to the initial force \( F \), they will now:

                          • attract with a force \( \frac{F}{2} \)
                          • repel with a force \( \frac{F}{2} \)
                          • repel with a force \( F \)
                          • attract with a force \( F \)
                        CBSE CLASS XII Previous Year Papers

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