NCERT Solutions For Class 11 Physics Chapter 12: Thermodynamics

NCERT Solutions for Class 11 Physics Chapter 12 Thermodynamics are given in this article. Thermodynamics is a branch of physics that deals with the study of the transformation of heat energy into several other forms of energy. For example, when we rub our palms together, the work done in rubbing produces heat. This process of rubbing hands denotes a Thermodynamic process.

Class 11 Physics Chapter 12 Thermodynamics is of Unit 8 which has a weightage of 20 marks along with unit 7 and Unit 9. Class 11 NCERT Solutions for Chapter 12 cover important concepts of laws of thermodynamics, Carnot Cycle, Born Haber Cycle, and Enthalpy.

Download PDF: NCERT Solutions for Class 11 Physics Chapter 12


NCERT Solutions for Class 11 Physics Chapter 12

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Class 11 Physics Chapter 12 – Concepts Covered

  • Thermodynamics is the branch of physics that deals with the study of the transformation of heat into other forms of energy and vice-versa.
A collection of a large number of atoms or molecules confined within certain boundaries in a way that it has specific values of pressure (P), volume (V) and temperature (T) is known as a thermodynamic system.
  • Zeroth Law of Thermodynamics identifies thermal equilibrium and introduces the concept of temperature as a tool for identifying equilibrium. 
If two systems are in thermal equilibrium with a third system then those two systems themselves are in equilibrium with each other.
  • Work is said to be done if a system moves a certain distance in the direction of the applied force.
It is given as dW = PdV
where P refers to the pressure of the gas in the cylinder.

The total change in heat energy in any system is the sum of the work done and the change in internal energy.

  • Second Law of Thermodynamics is the principle that disallows certain phenomena that are consistent with the First law of thermodynamics.
The two statements of second law of thermodynamics are as follows – 
- Kelvin-Planck Statement: It is impossible to form an engine, operating in a cycle, to extract heat from a hot body and then convert it completely into work without leaving change anywhere i.e., 100% conversion of heat into work is not possible.
- Clausius Statement: It is impossible for a self acting machine, operating in a cycle, without the help of any external energy to transfer heat from a cold body to a hot body. Heat can not flow itself from a colder body to a hotter body.

CBSE CLASS XII Related Questions

  • 1.
    A wire of length \(L\) is bent round into (i) a square coil having \(N\) turns and (ii) a circular coil having \(N\) turns. The coil in both cases is free to turn about a vertical axis coinciding with the plane of the coil, in a uniform, horizontal magnetic field and carry the same currents. Find the ratio of the maximum value of the torque acting on the square coil to that on the circular coil.


      • 2.
        The resistance of a metal wire at \(20^\circ\text{C}\) is \(1.05\,\Omega\) and at \(100^\circ\text{C}\) is \(1.38\,\Omega\). Determine the temperature coefficient of resistivity of this metal.


          • 3.

            Find the ratio $\dfrac{\lambda_\alpha}{\lambda_p}$ of the de Broglie wavelength $\lambda_\alpha$ associated with an alpha particle to the de Broglie wavelength $\lambda_p$ associated with a proton if both are moving with the same velocity.


              • 4.

                (I) The real image of an object placed between $f$ and $2f$ from a convex lens can be seen on a screen placed at the image location. If the screen is removed, is the image still there? Explain.

                (II) Plane and convex mirrors produce virtual images of objects. Can they produce real images under some circumstances? Explain.


                  • 5.

                    A rectangular loop of size 5 cm $\times$ 8 cm is lying in the $x$-$y$ plane in a uniform magnetic field $\vec{B} = (2.0\ \text{T})\hat{k}$. The total magnetic flux linked with the loop is:

                      • 80 Wb
                      • 16 Wb
                      • \(8 \times 10^{-2}\) Wb
                      • \(8 \times 10^{-3}\) Wb

                    • 6.

                      A circular coil of 100 turns and radius $\left(\frac{10}{\sqrt{\pi}}\right)$ cm carrying current of $5.0\,\text{A}$ is suspended vertically in a uniform horizontal magnetic field of $2.0\,\text{T}$. The field makes an angle $30^\circ$ with the normal to the coil. Calculate:

                      (I) the magnetic dipole moment of the coil, and

                      (II) the magnitude of the counter torque that must be applied to prevent the coil from turning.

                        CBSE CLASS XII Previous Year Papers

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