NCERT Solutions For Class 11 Physics Chapter 12: Thermodynamics

NCERT Solutions for Class 11 Physics Chapter 12 Thermodynamics are given in this article. Thermodynamics is a branch of physics that deals with the study of the transformation of heat energy into several other forms of energy. For example, when we rub our palms together, the work done in rubbing produces heat. This process of rubbing hands denotes a Thermodynamic process.

Class 11 Physics Chapter 12 Thermodynamics is of Unit 8 which has a weightage of 20 marks along with unit 7 and Unit 9. Class 11 NCERT Solutions for Chapter 12 cover important concepts of laws of thermodynamics, Carnot Cycle, Born Haber Cycle, and Enthalpy.

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NCERT Solutions for Class 11 Physics Chapter 12

Class 11 Physics Chapter 12 – Concepts Covered

Thermodynamics is the branch of physics that deals with the study of the transformation of heat into other forms of energy and vice-versa.

A collection of a large number of atoms or molecules confined within certain boundaries in a way that it has specific values of pressure (P), volume (V) and temperature (T) is known as a thermodynamic system.

Zeroth Law of Thermodynamics identifies thermal equilibrium and introduces the concept of temperature as a tool for identifying equilibrium.

If two systems are in thermal equilibrium with a third system then those two systems themselves are in equilibrium with each other.

Work is said to be done if a system moves a certain distance in the direction of the applied force.

It is given as dW = PdV
where P refers to the pressure of the gas in the cylinder.

First Law of Thermodynamics is the general law of conservation of energy applied to a body or a system.

The total change in heat energy in any system is the sum of the work done and the change in internal energy.

Second Law of Thermodynamics is the principle that disallows certain phenomena that are consistent with the First law of thermodynamics.

The two statements of second law of thermodynamics are as follows –
- Kelvin-Planck Statement: It is impossible to form an engine, operating in a cycle, to extract heat from a hot body and then convert it completely into work without leaving change anywhere i.e., 100% conversion of heat into work is not possible.
- Clausius Statement: It is impossible for a self acting machine, operating in a cycle, without the help of any external energy to transfer heat from a cold body to a hot body. Heat can not flow itself from a colder body to a hotter body.

Class 11 Physics Chapter 12 Related Guides –

Terms Related to Thermodynamics	Entropy	Heat Engine
Refrigerator and Heat Pump	Bomb Calorimeter	Celsius Scale
Enthalpy and Entropy	Enthalpy Change	Thermodynamic Processes
Isobaric process	Cyclic process	Reversible and irreversible processes
Applications of Thermodynamics	Heat Capacity	Standard Enthalpy of Formation

Class 11 Physics Study Guides:

NCERT Solutions for Class 11 Physics	Physics Formula	Class 11 Physics Notes
Relation between articles in Physics	Derivations in Physics	SI Units in Physics
Difference between in Physics	Physics Constants	Physics Study Notes

CBSE CLASS XII Related Questions

1.
Read the following paragraph and answer the questions that follow.
In an experiment with convex lens of focal length f, the screen is fixed at a distance D from the object. A student slowly moves the lens away from the object towards the screen and finds that she is able to form sharp image of the object for two positions of the lens. The distance between these two positions of the lens is d.

2.
Read the following paragraph and answer the questions that follow.
A p-type or n-type semiconductor can be converted into a p-n junction by doping it with suitable impurity. The motion of majority charge carriers causes diffusion current across the junction while the barrier electric field causes motion of minority carriers for drift current. In case of unbiased diode, the diffusion and drift currents are equal. This equilibrium is disturbed by the biasing batteries. Diodes, therefore, allow currents in one direction. This property of diode is used in making rectifiers.

3.
The resistance of a metal wire at $ 20^\circ \text{C} $ is $ 1.05 \, \Omega $ and at $ 100^\circ \text{C} $ is $ 1.38 \, \Omega $. Determine the temperature coefficient of resistivity of this metal.

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4.
Consider a cylindrical conductor of length $ l $ and area of cross-section $ A $. Current $ I $ is maintained in the conductor and electrons drift with velocity $ \vec{v}_d \, (|\vec{v}_d| = \frac{eE}{m} \tau) $, where symbols have their usual meanings. Show that the conductivity of the material of the conductor is given by \[ \sigma = \frac{n e^2 \tau}{m}. \]

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5.
Two air-filled capacitors of capacitances $C_1$ and $C_2$ are connected in parallel with a dc battery. After the capacitors are fully charged, a slab of dielectric constant K is inserted between the plates of each capacitor. How will the (i) charge on each capacitor and (ii) energy stored in the capacitor affected after the slab is introduced.

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6.
Two metal spheres of radii $r_1$ and $r_2$ ($> r_1$) having charges $q_1$ and $q_2$ respectively kept in air, are brought in contact. Which of the following statements is not correct ?

The total charge of the two spheres is conserved.
Both spheres attain the same potential.
The final potential of the system equals $\frac{1}{4\pi\epsilon_0} \frac{(q_1 + q_2)}{(r_1 + r_2)}$
The final potential of the system equals $\frac{1}{4\pi\epsilon_0} \frac{(q_1 + q_2) (r_1 + r_2)}{r_1 r_2}$

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NCERT Solutions For Class 11 Physics Chapter 12: Thermodynamics

NCERT Solutions for Class 11 Physics Chapter 12

Class 11 Physics Chapter 12 – Concepts Covered

CBSE CLASS XII Related Questions

3.
The resistance of a metal wire at \( 20^\circ \text{C} \) is \( 1.05 \, \Omega \) and at \( 100^\circ \text{C} \) is \( 1.38 \, \Omega \). Determine the temperature coefficient of resistivity of this metal.

6.
Two metal spheres of radii $r_1$ and $r_2$ ($> r_1$) having charges $q_1$ and $q_2$ respectively kept in air, are brought in contact. Which of the following statements is not correct ?

Similar Physics Concepts

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NCERT Solutions For Class 11 Physics Chapter 12: Thermodynamics

NCERT Solutions for Class 11 Physics Chapter 12

Class 11 Physics Chapter 12 – Concepts Covered

CBSE CLASS XII Related Questions

3. The resistance of a metal wire at \( 20^\circ \text{C} \) is \( 1.05 \, \Omega \) and at \( 100^\circ \text{C} \) is \( 1.38 \, \Omega \). Determine the temperature coefficient of resistivity of this metal.

6.Two metal spheres of radii $r_1$ and $r_2$ ($> r_1$) having charges $q_1$ and $q_2$ respectively kept in air, are brought in contact. Which of the following statements is not correct ?

Similar Physics Concepts

Comments

SUBSCRIBE TO OUR NEWS LETTER

3.
The resistance of a metal wire at \( 20^\circ \text{C} \) is \( 1.05 \, \Omega \) and at \( 100^\circ \text{C} \) is \( 1.38 \, \Omega \). Determine the temperature coefficient of resistivity of this metal.

6.
Two metal spheres of radii $r_1$ and $r_2$ ($> r_1$) having charges $q_1$ and $q_2$ respectively kept in air, are brought in contact. Which of the following statements is not correct ?