Tangential Quadrilateral Formula: Characteristics & Examples

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Jasmine Grover

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Tangential Quadrilateral is a quadrilateral in which a circle is inscribed and all the sides of the quadrilateral act as tangents to the circle. The enclosed circle is known as an incircle or inscribed circle with respect to the quadrilateral. Some synonyms of Tangential Quadrilateral are circumscribable quadrilateral, circumscriptive quadrilateral and circumscribing quadrilaterals.

Read More: Inradius of Incircle

Key Terms: Tangential Quadrilateral, Formula, Area, Incircle


Tangential Quadrilateral

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Common quadrilaterals are square, rectangle, parallelogram, kite, diamond, rhombus etc. But the Tangential Quadrilateral is a little different from the mentioned quadrilaterals. Tangential Quadrilaterals refer to those quadrilaterals that have a well-defined circle inscribed in it.

Tangential Quadrilateral

Tangential Quadrilateral

The four respective sides of the quadrilateral turn out to be tangents for the circle. The sides of the Tangential Quadrilateral may or may not be equal. 

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Characteristics of Tangential Quadrilateral

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  • All the four sides of the quadrilateral must touch the circle.
  • The circle should be fully contained within the quadrilateral. No part of the circle must protrude outside the quadrilateral. 
  • The angle bisectors of four sides of quadrilateral meet at the centre of the inscribed circle. 

angle bisectors of four sides

  • The sum of length of two opposite sides must be equal. For example if the four sides of a tangential quadrilateral are as a,b,c and d. Then, a+c = b+d
  • Any quadrilateral can become tangential quadrilateral if it satisfies all the above conditions. 

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Area Formula of Tangential Quadrilateral

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Area of a Tangential Quadrilateral can be derived from the semi-perimeter and radius of the inscribed circle. Take the following suppositions:

Four sides are a,b,c and d. 

Semi-Perimeter (Half Perimeter) or s = (a+b+c+d)/ 2 

Radius of the incircle or inscribed circle = r

Thus, area of the quadrilateral, A = r.s

Another formula for area of quadrilateral is, A= √abcd

But before calculating make sure you check whether a+c = b+d.

Also Read: Section Formula


Construction of Tangential Quadrilateral

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  1. Create the angle bisector of the four angles in the corner. 
  2. Meet the angle bisectors at a point inside the quadrilateral. This point is called the incentre of the inscribed circle. 
  3. From that point draw a circle which touches all sides of the quadrilateral. The sides of the quadrilateral touching the circle are tangents to it. Thus, a tangential quadrilateral is made.
  4. The distance between the centre of the circle and point of tangent is the radius of the inscribed circle. 

Construction of Tangential Quadrilateral

Construction of Tangential Quadrilateral

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Things to Remember

  • Before considering any quadrilateral as a tangential quadrilateral, first verify whether pairs of opposite sides are equal or not i.e., a+c = b+d. 
  • Tangential quadrilaterals come under the category of convex quadrilaterals. Convex quadrilaterals are those quadrilaterals whose interior angles are less than 180o and diagonals lie inside the perimeter. 
  • While drawing the inscribed circle all the angle bisectors should meet at a single point inside the circle (incentre). 

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Sample Questions

Ques:  Which parameters of the tangential quadrilateral are needed to find the area? (2 Marks)

Ans: As we know, the formula to find the area of the tangential quadrilateral is A = r.s where, r is the radius of the inscribed circle and s is the semi-perimeter of the quadrilateral. Sometimes in problems, you need to find out the semi-perimeter of the quadrilateral and length of the sides are given. In that case you need to have length of all four sides, unless the area is given. 

Ques: Solve the following problem:
The area of a tangential quadrilateral needs to be found. Semi-Perimeter of the quadrilateral is 16 cm, radius of the circle is 8 cm.  (2 Marks)

Ans. The formula of the area of tangential quadrilateral says, A (area) = r (radius) * s(semi-perimeter). 

Thus, Area = 8*16 = 128 cm2.

Ques: Four sides of a tangential quadrilateral are 4 cm, 3 cm, 5 cm and 6 cm. The distance between the incentre and point of contact on the quadrilateral is 5 cm. Find the area of the quadrilateral. (2 Marks)

Ans: First of all, calculate the semi-perimeter. 

Semi-perimeter (s) = (4+3+5+6)/2 = (18/2) = 9 cm. 

The distance between the incentre and point of contact on the quadrilateral is the radius of the inscribed circle, which is = 5 cm. 

Hence, Area = 9*5 = 45 cm2.

Ques: The square of the product of length of four sides is 81. Find the area of the tangential quadrilateral. (2 Mark)

Ans: If four sides of the quadrilateral are a,b,c and d then abcd = 81

=> We know that, A= √abcd

=> A = √81 = 9 cm

Thus, Area of the tangential quadrilateral is 9 cm2.

Ques: If thrice the area of a tangential quadrilateral is 54cm2 and double the perimeter is 24 cm. Find radius of the inscribed circle. (3 Marks)

Ans: Let us take Area = a, perimeter = p, radius = r.

Given, 3*a = 54 cm2, 2*p = 24 cm.

Thus, a = 54/3 = 18 cm2 and p = 24/2 = 12 cm.

Semi-perimeter (s) = 12/2 = 6 cm.

As per the formula of area, A = r.s

=> 18 = r*6

=> 18/6 = r

Therefore, r = 3 cm.

Ques: If the perimeter of a tangential quadrilateral is 1/4th of its area, which is 88 cm2. Find the radius of the inscribed circle. (3 Marks)

Ans: Given, area = 88 cm2 and perimeter = 1/4th of area

→ perimeter = 1/4 * 88 = 22 cm. 

→ Semi-perimeter = 22/2 = 11 cm. 

→ Area = Radius*Semi-Perimeter

→ 88 = Radius*11

Thus, Radius = 88/11 = 8 cm

Ques: Diameter of the inscribed circle in a tangential quadrilateral is 14 cm. Sum of four sides of the quadrilateral is 32 cm. Calculate the area of the tangential quadrilateral.  (3 Marks)

Ans: Given, diameter = 14 cm and sum of four sides = 32 cm. 

→ Radius (r) = diameter/2 = 14/2 = 7 cm.

→ Sum of four sides means perimeter (p), which is 32 cm. 

→ Semi-perimeter (s) = 32/2 = 16 cm.

→Area = r.s

Thus, Area = 7*16 = 102 cm2

Ques: The area of a tangential quadrilateral is 48 cm2 and radius of inscribed circle is 6 cm. Length of three sides of the quadrilateral are given as 6 cm, 4 cm, 3 cm, length of one side is unknown. Find the length of the unknown side. (5 Marks)

Ans: Given data, area = 48 cm2 and radius = 6 cm. 

Let us assume the length of the unknown side as x cm. 

Now, the semi-perimeter (s) = (6+4+3+x)/ 2 = (13+x)/ 2 cm

We know that, Area = r.s 

→ 48 = 6*(13+x)/ 2

→ 48*2 = 6*(13+x)

→ 96/6 = 13+x

→ 16 – 13 = 3 = x

Therefore, the length of the unknown side is 3 cm. 


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CBSE X Related Questions

  • 1.
    Use graphical method to solve the system of linear equations : $x = -3$ and $5x - 2y = -5$.


      • 2.
        In the given figure, $AB \parallel DE$ and $AC \parallel DF$. Show that $\Delta ABC \sim \Delta DEF$. If $BC = 10\text{ cm}$, $EB = CF = 5\text{ cm}$ and $AB = 7\text{ cm}$, then find the length $DE$.


          • 3.
            Two dice are rolled together. The probability of getting an outcome $(x, y)$ where $x \gt y$, is

              • $\frac{5}{12}$
              • $\frac{5}{6}$
              • $1$
              • $0$

            • 4.
              A chord of a circle, of radius 14 cm, subtends an angle of $60^\circ$ at the centre. Find the area of the smaller sector and perimeter of the smaller segment.


                • 5.
                  An arc of length $2.2\text{ cm}$ subtends an angle $\theta$ at the centre of the circle with radius $2.8\text{ cm}$. The value of $\theta$ is

                    • $50^\circ$
                    • $60^\circ$
                    • $45^\circ$
                    • $30^\circ$

                  • 6.
                    Prove that: $\frac{\tan \theta}{1 - \cot \theta} + \frac{\cot \theta}{1 - \tan \theta} = 1 + \tan \theta + \cot \theta$

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