Conservation of Angular Momentum: Law, Calculation, and Applications

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Conservation of angular momentum states that the total angular momentum of an isolated system remains constant.

  • The quantity of motion contained in a body is known as momentum.
  • It is given by the product of the mass and velocity of the body.
  • When the momentum of the body is in a straight line then it is referred to as linear momentum.
  • Angular momentum is a rotating analog of linear momentum.
  • Angular momentum is a vector quantity and its SI unit is kg m2/s.

According to the law of conservation angular momentum,

“Angular momentum of a rotating body is constant if there is no external torque acting on the object”

i.e. if external torque, τ = 0, then L = constant

Key Terms: Angular momentum, Law of conservation of angular momentum, Linear momentum, Torque, Velocity, Rotational motion, Angular velocity


Angular Momentum

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The rotating analog of linear momentum is called angular momentum. 

  • It is also known as the moment of momentum or rotational momentum. 
  • It is a property of a rotating body determined by the product of the rotating moment of inertia of the object and its angular velocity. 
  • It is a vector quantity, which means that the direction is taken into account in addition to the magnitude.
  • It is an important physical quantity since it is a conserved quantity. 
  • In a closed system, the total angular momentum remains constant.
  • It is denoted by \(\vec{L}\)
  • The SI unit of angular momentum is kg m2/s.
  • The dimensional formula of angular momentum is [M L2 T-1].

The formula of angular momentum for a point object is given by

\(\vec{L} = \vec{r} \times \vec{p}\)

Where

  • L is the angular momentum
  • r is the radius of the circular path
  • p is the linear momentum of the body

The formula of angular momentum for an extended object is given by

\(\vec{L} = \vec{I} \times \vec{\omega}\)

Where

  • I is the moment of inertia of the rotating object
  • ω is the angular velocity

Angular momentum

Angular Momentum

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Relationship Between Torque and Angular Momentum

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The angular momentum of an object having linear p rotating about a point in a circular path of radius r is given by

\(\vec{L} = \vec{r} \times \vec{p}\)

Differentiating both sides with respect to time t, we get

\(\frac{d}{dt} \vec{L} = \frac{d}{dt} (\vec{r} \times \vec{p})\)

\(\frac{d}{dt} \vec{L} = \vec{r} \times \frac{d}{dt} \vec{P} + \vec{P}\frac{d}{dt} \vec{r}\)

But \(\frac{d}{dt} \vec{r} = \vec{v} \)

And \(\vec{P} = m \vec{v}\)

Where

  • m is the mass of the rotating object
  • v is the linear velocity of the object

On substituting the values, we get

\(\frac{d}{dt} \vec{L} = \vec{r} \times \frac{d}{dt} \vec{P} + (m\vec{v} \times \vec{v})\)

Since (\(m \vec{v} \times \vec{v}\))=0, therefore

\(\frac{d}{dt} \vec{L} =\vec{r} \times \frac{d}{dt} \vec{p}\)

Also, \(\frac{d}{dt} \vec{P} = \vec{F}\)

\(\frac{d}{dt} \vec{L} = \vec{r} \times \vec{F}\)

But \(\vec{r} \times \vec{F} = \tau\), the torque acting on the rotating object

Therefore

\(\frac{d}{dt} \vec{L} = \vec{\tau}\)

Hence the time rate of change of angular momentum of a particle is equal to the torque acting on it.


Law of Conservation of Angular Momentum

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Angular momentum, like other aspects of physics, is subject to the laws of conservation, which define that certain properties of a physical system remain constant even while that system evolves over time. 

  • In other words, unless acted upon by an external force, that quality remains constant. 
  • Energy, electric charge, particle physics, linear momentum, and angular momentum are all governed by conservation laws.
  • The law of conservation, as applied to angular momentum, states that the momentum of a rotating object does not change until some form of external torque is applied. 
  • Torque, in this case, can refer to any external force acting on an object to cause it to rotate or spin.

According to the law of conservation of angular momentum,

“If the external torque on a system is zero, the total angular momentum of the system is conserved i.e. remains constant.”

The relation between angular momentum and torque is given by

\(\vec{\tau} = \frac{d}{dt} \vec{L}\)

If the external torque on the system is zero i.e. =0, then

\(\frac{d}{dt} \vec{L}=0\)

 i.e. change in linear momentum is zero

\(\vec{L}\) = constant

Where L is the angular momentum of the body.


Conservation of Angular Momentum Calculation

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The angular momentum of a system is conserved as long as there is no net external torque working on the system. Because of the law of conservation of angular momentum, the earth has been revolving on its axis since the formation of the solar system.

There are two ways to calculate the angular momentum of an object

  • If the object is a point object, then angular momentum is given by the cross product of the position vector and linear momentum i.e.

\(\vec{L} = \vec{r} \times \vec{p}\)

  • If the object is an extended object, then angular momentum is given by the cross product of the moment of inertia of the rotating object and its angular velocity i.e.

\(\vec{L} = \vec{I} \times \vec{\omega}\)

In both cases, if no external torque is acting on the body then the initial angular momentum of the body will be equal to the final angular momentum i.e. angular momentum will remain conserved if no external torque acting on the object.

Angular momentum formula

Angular Momentum Formula


Applications of Conservation of Angular Momentum

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The following are examples of the conservation of angular momentum

  • Based on the conservation of momentum, an ice skater performs the feasts.
  • Suppose an ice skater is rotating with her arms and legs stretched outwards. When she folds her arms and brings the stretched legs close to each other, her moment of inertia decreases, and hence her angular velocity increases.
  • The angular velocity of the revolution of a planet around the sun in an elliptical orbit increases, when the planet comes closer to the sun and vice versa. This is because when the planet comes closer to the sun, its moment of inertia about the sun decreases, therefore its angular velocity increases.
  • The conservation of angular momentum is also used in the design of roller coasters and other amusement park rides to ensure that riders are not thrown from the ride.
  • When a diver tucks their body into a ball before entering the water, they decrease their moment of inertia, which allows them to spin faster.

Things to Remember

  • The momentum of a body is given by the product of its mass and velocity.
  • Angular momentum is a property of a rotating body determined by the product of the rotating moment of inertia of the object and its angular velocity i.e.

L = Iω

  • Angular momentum is a scalar quantity and its SI unit is kg m2/s.
  • The dimensional formula of angular momentum is [M L2 T-1].
  • According to the law of conservation of angular momentum, the angular momentum of a body will remain constant if no external torque acts on the body i.e. L1 = L2 or L = constant.
  • If I1 and I2 are the initial and final moment of inertia, and ω1 and ω2 are their initial and final angular velocities, if no external torque is applied, then 

I1ω1 = I2ω2

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Sample Questions

Ques. A car of mass 300 kg is traveling on a circular track of radius 100 m with a constant speed of 60 m/s. Calculate the angular momentum about the center of the circle. (5 Marks)

Ans. Given

  • The mass of the car, m = 300 kg
  • The radius of the circular track, r = 100 m
  • Speed of the car, v = 60 m/s

The linear momentum of the car is given by

p = mv

⇒ p = 300 x 60 = 18000 kg m/s

The angular momentum of the car is given by

L = rp sinθ

Where

  • L is the angular momentum
  • r is the radius of the circular track
  • p is the linear momentum of the object
  • θ is the angular between the position vector and the momentum vector

On substituting the values, we get

L = 100 x 18000 x sin 90

⇒ L = 18 x 105 kgm2/s

Ques. Define Momentum. (2 Marks)

Ans. Momentum is a vector quantity that measures the motion of an object. It is defined as the product of the mass of the object and its velocity. 

Momentum is denoted by the symbol p and is calculated using the following equation:

p = mv

Where

  • m is the mass of the object
  • v is the velocity

Ques. What is angular momentum? (2 Marks)

Ans. Angular momentum is a rotational analog of linear momentum. It is a measure of the rotational inertia of an object about a particular axis of rotation. Angular momentum is a vector quantity, meaning that it has both magnitude and direction.

Ques. Two bodies are accelerating toward each other. After some time they collide. Which one of the following statements is true about the system? (2 Marks)
(a) The total momentum does not remain conserved
(b) The total momentum remains conserved during collision
(c) The total momentum remains conserved about the instant of collision
(d) The total momentum remains conserved

Ans. The correct answer is c. The total momentum remains conserved about the instant of collision

Explanation: Because they are accelerating, overall momentum is not conserved during the motion. However, at the point of contact, both bodies have the same velocity. As a result, the total momentum will be conserved shortly before and after the collision.

Ques. A torque of 10 N m is applied on a wheel having an angular momentum of 2 kg m2/s, calculate the angular momentum of the wheel after 4 seconds. (5 Marks)

Ans. Given

  • Torque applied on the wheel, τ = 10 N m
  • Initial angular momentum, L1 = 2 kg m2/s
  • The time up to which torque is applied, t = 4 seconds

The time rate of change of angular momentum of a particle is equal to the torque

Torque, τ = dl/dt

⇒ τ = (L2 - L1)/t

Where

  • L1 is the initial angular momentum of the body
  • L2 is the final angular momentum of the body
  • t is the time during which momentum is changed on the application of torque

On substituting the values, we get

10 = (L2 - 2)/4

⇒ L2 = 40 + 2 = 42 kg m2/s

Ques. What is the law of conservation of angular momentum? (2 Marks)

Ans. According to the law of conservation angular momentum, the angular momentum of a rotating body is constant if there is no external torque acting on the object

i.e. if external torque, τ = 0, then L = constant

Ques. What is the SI unit of angular momentum? (1 Mark)

Ans. The SI unit of angular momentum is kg m2/s.

Ques. A flywheel having a moment of inertia of 20 kg m2 rotates about its axis with an angular velocity of 100 rad/s. If the moment of inertia of the flywheel is reduced to 10 kg m2 without applying external torque, calculate the new angular velocity of the flywheel. (3 Marks)

Ans. Given

  • Initial moment of inertia, I1 = 20 kg m2
  • The final moment of inertia, I2 = 10 kg m2
  • Initial angular velocity, ω1 = 100 rad/s

Let ω2 be the new angular velocity of the flywheel

As no external torque acts on the flywheel, therefore, angular momentum is conserved. Hence

I1ω1 = I2ω2

⇒ ω2 = (I1ω1)/I2

On substituting the values, we get

ω2 = (20 x 100)/10 = 200 rad/s

Hence the new angular velocity of the flywheel is 200 rad/s.

Ques. Define torque. (2 Marks)

Ans. A torque is a rotational force that tends to cause an object to rotate about an axis. It is defined as the product of force and the perpendicular distance from the line of action of the force to the axis of rotation. 

Torque is denoted by the symbol τ and it is given by

τ = r × F

Where

  • F is the force
  • r is the distance from the line of action of the force to the axis of rotation

Ques. A rod of mass 2 kg and length 1 m is pivoted at one end A and kept on a smooth surface. A particle of mass 500 gm strikes the other end B of the rod and sticks to the rod. If the particle was moving with the speed of 10 m/s, what is the angular speed of the rod after collision? (5 Marks)

Ans. Given

  • The mass of the rod, m1 = 2 kg
  • The mass of the particle strikes the end B of the rod, m2 = 500 gm = 0.5 kg
  • Length of the rod = radius of the circular path, r = 1 m
  • The initial linear speed of the particle, v = 10 ms

Initial angular momentum is given by

Li = m2vr

⇒ Li = 0.5 x 10 x 1 = 5 kg m2/s

The final angular momentum is given by

Lf = IAω

Where 

  • IA is the moment of inertia about point A
  • ω is the angular speed of the rod after collision

⇒ Lf = [m1l2/3 + m2l2

On substituting the values, we get

⇒ Lf = [2/3 + 1/2]ω = 7/6ω

Since the rod is pivoted at point A, the angular momentum of the rod and particle system can only be conserved about point A. Therefore

Li = Lf

⇒ 5 = 7/6ω

⇒ ω = 4.28 rad/s

Hence the angular speed of the rod after the collision is 4.28 rad/s.

Ques. A child sits stationary at one end of a long trolley moving uniformly with speed v on a smooth horizontal floor. If the child gets up and runs about on the trolley in any manner, then what is the effect of the speed of the center of mass of the (trolley+child) system? (2 Marks)
(a) The speed of the center of mass will not change
(b) The speed of the center of mass increases
(c) The speed of the center of mass will first increase and then decrease
(d) The speed of the center of mass decreases

Ans. The correct answer is a. The speed of the center of mass will not change

Explanation: The internal forces of the system are the forces involved in the given situation. When the child runs, no external force works on the system. As a result, the speed of the (trolley+child) system's center of mass will remain constant.

Ques. Two bodies moving with constant velocities collide with each other. Which of the following quantities remain conserved? (2 Marks)
(a) Velocity
(b) Force
(c) Speed
(d) Momentum

Ans. The correct answer is d. Momentum

Explanation: In the absence of any external force, two bodies collide. Because there is no force in this case, the momentum will remain constant, and there will be no change in momentum. After a collision, the bodies' velocity and speed may change.

Ques. A bus of mass 500 kg is traveling on a circular track of radius 80 m with a constant speed of 50 m/s. Calculate the angular momentum about the center of the circle. (5 Marks)

Ans. Given

  • The mass of the bus, m = 500 kg
  • The radius of the circular track, r = 80 m
  • Speed of the car, v = 50 m/s

The linear momentum of the bus is given by

p = mv

⇒ p = 500 x 50 = 25000 kg m/s

The angular momentum of the car is given by

L = rp sinθ

Where

  • L is the angular momentum
  • r is the radius of the circular track
  • p is the linear momentum of the object
  • θ is the angular between the position vector and the momentum vector

On substituting the values, we get

L = 80 x 25000 x sin 90

⇒ L = 2 x 106 kgm2/s

Ques. Where does the center of mass of two particles of an equal mass lie? (2 Marks)
(a) Outside the body
(b) Midway between them
(c) Near the first body
(d) Inside the body

Ans. The correct answer is b. Midway between them

Explanation: The center of mass of two particles of equal mass is located in the middle of them. Its position vector is the average of the two particles' position vectors.

Ques. What is the plural of the word ‘momentum’? (2 Marks)
(a) Momentums
(b) Momenta
(c) Moment
(d) Moments

Ans. The correct answer is b. Momenta

Explanation: Momenta is the plural of momentum.

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