Law of Equipartition of Energy: Definition, Degree of Freedom and Sample Questions

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Equipartition of energy states that in a thermal equilibrium system, equal distribution of energy will be connected with each degree of freedom on average. For example, a molecule that is moving through space will have three degrees of freedom as its location will be defined through the three coordinates.

  • The degree of freedom of a system is defined as the total number of coordinates or independent quantities required to describe the position and configuration of the system completely.
  • The scientific definition of this law is ‘The Equal distribution of energy among the degrees of freedom for any dynamic system in thermal equilibrium’.
  • According to the law of Equipartition of energy, in equilibrium the energy is equally distributed in all possible energy modes i.e. translational, rotational, and vibrational with each mode having an average energy equal to 1/2KT.
  • This law can be applied to predict the specific heat of gases.

Key Terms: Degree of freedom, energy, rms velocity, Equipartition of energy, Boltzmann constant, Vibrational motion, Gas constant, Temperature

Read More: Elastic Limit


Law of Equipartition of Energy

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The invention of this law was done by the physicists named Ludwig Boltzmann from Germany & James Clerk Maxwell from Scotland. If we apply formulas to define this law then the law states:

“A system of equilibrium molecules at established Temperature (T) will consist of a standard 1/2KT energy correlated with each degree of freedom where ‘K’ is seen as the Boltzmann constant”.

Additionally, if there is any other degree of freedom providing energy which is quite prospective, then it will have another 1/2KT energy correlated with it.

Law of Equipartition of Energy
Law of Equipartition of Energy

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Path Length

Uniform Motion

Displacement vector

In a system where ‘s’ is the degree of freedom & ‘t’ has prospective energies. The average energy in totality will be

E= 1/2(s+t)kT

Let us take an example:

  • A particle of gas contains three degrees of freedom (coordinates of the particle).
  • Therefore, it will have an average energy of 3/2 kT in totality.
  • Hence, for the particle in a solid form, the vibrational movement consists of possible energy and also kinetic energy.
  • With both modes contributing to a term 1/2 kT, it will result in an average energy of 3 kT in totality.
Law of Equipartition of Energy
Law of Equipartition of Energy

Among the kinetic theory of gases, the average thermal equilibrium square value of elements of the velocity of a ‘C’ gas molecule across three axes X, Y, and Z are uniformly dispersed, i.e., u2 = v2 = w2. The average total value of the elements of velocities across the X, Y, and Z axes are respectively u, v, and w.

The kinetic energy is distributed uniformly in a single particle along the x-axis, y-axis, and z-axis.

  1. X-Axis = 1/2 m(vx)2
  2. Y-Axis = 1/2 m(vy​)2
  3. Z-Axis = 1/2 m(vz​)2

The average kinetic energy when gas is at thermal equilibrium is constituted as

  1. X-Axis = 1/2KbT
  2. Y-Axis = 1/2KbT
  3. Z-Axis = 1/2KbT

The average kinetic energy according to the kinetic theory of gases is constituted as

E= 3/2m(vrms)2 = 3/2 KbT

The vrms is represented as the square root of the velocity of the particles. The Boltzmann constant is indicated by Kb and T is the temperature of the gas.

The kinetic energy is distributed uniformly in a single particle along the x-axis, y-axis, and z-axis.
The kinetic energy is distributed uniformly in a single particle along the x-axis, y-axis, and z-axis.

Read More: Mean Free Path


Degree of Freedom

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As we have discussed above, every particle consists of three translational degrees of freedom to allow the particle to freely move through space. For specifying the location in orbit, the particle has three coordinates. Similarly, if required to move it to a place then the molecule is supposed to have two translational degrees of freedom & one translational degree of freedom is required if there is a straight line. Therefore, it varies from one atom to another.

Degree of Freedom
Degree of Freedom

Likewise, if we discuss the triatomic atom, it should contain 6 degrees of freedom. So, the per molecule kinetic energy of the gas will be:

6 x N x ½ KbT = 3 x R / N N KbT = 3RT

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Let us take another different example for a deeper understanding of the degree of freedom. The gases, helium and argon contain only one translational degree of freedom, the equation of per particle kinetic energy of the gas will be:

3 x N x ½ KbT = 3 x R / N N KbT = 3 / 2 RT

Thirdly, if we consider a diatomic molecule (2 atoms like O2 or N2). These molecules go through translational movement and contain three degrees of freedom. Additionally, they can also revolve around the center of the mass.

The degree of freedom can be comprehensively detailed as the number of criteria where a molecule or an atom has space to move. This concept is the foundation of the Law of Equipartition of energy. 

Degree of Freedom
Degree of Freedom

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Things to Remember

  • Equipartition of energy states that in a thermal equilibrium system, equal distribution of energy will be connected with each degree of freedom on average.
  • A system of equilibrium molecules at an established Temperature (T) will consist of a standard ½ kT energy correlated with each degree of freedom where ‘k’ is seen as the Boltzmann constant.
  • The kinetic energy is distributed uniformly in a single particle along the x-axis, y-axis, and z-axis.
  • The vrms is represented as the square root of the velocity of the particles. The Boltzmann constant is indicated by Kb and T is the temperature of the gas.
  • The degree of freedom can be comprehensively detailed as the number of criteria where a molecule or an atom has space to move. This concept is the foundation of the Law of Equipartition of energy.


Sample Questions

Ques. Who invented the theory of equipartition of energy? (2 marks)

Ans. The equipartition of kinetic energy was given in 1843 & more accurately in 1845, by John James Waterston. In 1859, James Clerk Maxwell kept an argument that the kinetic heat energy of a gas is uniformly distributed between linear and rotational energy.

Ques. What is the correlation between pressure & kinetic energy of gas? (2 marks)

Ans. From the formula, we can conclude that the pressure of the gas is equal to two-thirds of internal energy per unit volume or internal energy density (u=U/V). From the formula, pressure is equal to 2/3 of the mean kinetic energy per unit volume.

Ques. What are the applications of the law of equipartition of energy? (2 marks)

Ans. In more general terms, equipartition can be related to the classical system of thermal equilibrium. It is used to derive the ideal gas law. Meyer's relation Cp − Cv = R connects the two specific heats for one mole of an ideal gas.

Ques. How can we generate the degree of freedom? (2 marks)

Ans. The degree of freedom can be generated by the number of gas particles and the number of constraints.

Ques. What is the formula for degree freedom? (2 marks)

Ans. The most known equation used to find the degree of freedom is df = N – 1. It helps to ascertain the critical value table, which can ascertain the statistical importance of the outcome.

Ques. How much energy is needed to hit the baseball? Explain in reference to the influence of kinetic energy. (3 marks)

Ans. Kinetic energy is regarded as the energy of motion. Any object that is in motion contains kinetic energy. Baseball consists of a lot of kinetic energy. The pitcher throws the ball, transmitting kinetic energy to the ball. When the batman swings, the swinging motion will create kinetic energy in the bat. The striking of the bat with the ball will change the direction and pace of the speed of the ball, with the formula of kinetic energy working.

Ques. What is the term ‘Absolute zero’? (2 marks)

Ans. Absolute zero is the temperature at which the movement of particles ceases. Absolute zero has never been achieved but temperatures in the systematic order of 1 × 10-10 K have been attained. The Kelvin temperature scale is based on molecular motion, therefore absolute zero is also called 0 K.

Ques. Explain average kinetic energy. (2 marks)

Ans. At a given temperature, not every particle of a sample of matter involves a similar kinetic energy. In fact, the particles exhibit a varied range of kinetic energies. Many of the molecules consist of kinetic energy close to the middle range. 


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CBSE CLASS XII Related Questions

  • 1.
    Two heaters rated as \((P_1,V)\) and \((P_2,V)\) are connected in series across a dc source of \(V/2\) volt. The power consumed by the combination will be –

      • \((P_1+P_2)\)
      • \(\dfrac{P_1+P_2}{2}\)
      • \(\dfrac{P_1P_2}{2(P_1+P_2)}\)
      • \(\dfrac{P_1P_2}{4(P_1+P_2)}\)

    • 2.
      Photoemission of electrons occurs from a metal (\( \phi_0 = 1.96 \, \text{eV} \)) when light of frequency \( 6.4 \times 10^{14} \, \text{Hz} \) is incident on it. Calculate: Energy of a photon in the incident light, The maximum kinetic energy of the emitted electrons, and The stopping potential.


        • 3.
          A long solenoid of length \( L \) and radius \( r_1 \) having \( N_1 \) turns is surrounded symmetrically by a coil of radius \( r_2 \, (r_2>r_1) \) having \( N_2 \) turns (\( N_2 \ll N_1 \)) around its mid-point. Derive an expression for the mutual inductance of solenoid and coil. Is \( M_{12} = M_{21} \) valid in this case?


            • 4.
              Write the expression for the magnetic field due to a current element in vector form. Consider a 1 cm segment of a wire, centered at the origin, carrying a current of 10 A in positive x-direction. Calculate the magnetic field \( \mathbf{B} \) at a point \( (1 \, \text{m}, 1 \, \text{m}, 0) \).


                • 5.
                  The figure shows three point charges kept at the vertices of triangle ABC. The net electric field, due to this system of charges, at the midpoint M of base BC will be:

                    • \( \frac{q}{4 \pi \epsilon_0 l^2} \) pointing along MA
                    • \( \frac{q}{\pi \epsilon_0 l^2} \) pointing along AM
                    • \( \frac{q}{2 \pi \epsilon_0 l^2} \) pointing along AM
                    • Zero

                  • 6.
                    If Bohr’s quantization postulate (angular momentum \( = \frac{nh}{2\pi} \)) is a basic law of nature, it should be equally valid for the case of planetary motion also. Why, then, do we never speak of quantization of orbits of planets around the Sun? Explain.

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