NCERT Solutions for class 10 Maths chapter 15 Probability

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NCERT Solutions for class 10 Maths chapter 15 Probability are provided in this article. Some of the important topics in Probability chapter include:

Expected no.of questions: 2 to 3 questions of total 5 marks

Download PDF: NCERT Solutions for Class 10 Mathematics Chapter 15 pdf

NCERT Solutions for Class 10 Mathematics Chapter 15

NCERT Solutions for Class 10 Mathematics Chapter 15 Probability is given below.

Class 10 Mathematics Chapter 15 Probability – Important Topics

The three types of probabilities are theoretical probability, experimental probability, and axiomatic probability. The theoretical probability calculates the probability based on formulas and input values. The experimental probability gives a realistic value and is based on the experimental values for calculation. Quite often the theoretical and experimental probability differ in their results and the axiomatic probability is based on the axioms which govern the concepts of probability.

Formula for Probability:

P(E) = n(E) / n(S)

Formula for Theoretical Probability:

P(E) = Number of Favourable Outcomes / Number of Total Outcomes

Formula for Experimental Probability:

P(E) = Number of Favourable Outcomes / Total number of times experiment is done

Rules of Probability:

Probability of an impossible event is null.
Maximum Probability of any event can be its total number of possible outcomes.
Probability exists between 0 and 1. The probability can be zero also.
Probability cannot be negative.
Probability of A or Probability of B is addition of probability of A and the probability of B.

NCERT Solutions for Class 10 Maths Chapter 15 Exercises

NCERT Solutions for Class 10 Mathematics Chapter 15 Probability Exercises are given below.

Chapter Related Articles:

Theoretical Probability	Equally likely events	Empirical Probability
Events	Complimentary Events	Sure event
Experimental Probability	Elementary Event	Sum of probabilities

Maths Related Articles:

NCERT Solutions for Class 10 Mathematics	Important Maths Formulas	Maths Study material
Difference between in Maths	Algebra	Arithmetics
Geometry	Number System	Mensuration

CBSE X Related Questions

1.
The first term of an AP is $p$ and the common difference is $q$, then its 10th term is :
- $q - 9p$
- $p - 9q$
- $p + 9q$
- $2p + 9q$
View Solution
2.
Prove that: $\frac{\tan \theta}{1 - \cot \theta} + \frac{\cot \theta}{1 - \tan \theta} = 1 + \tan \theta + \cot \theta$
View Solution
3.
A chord of a circle, of radius 14 cm, subtends an angle of $60^\circ$ at the centre. Find the area of the smaller sector and perimeter of the smaller segment.
View Solution
4.
The natural number 1 is :
- a prime number.
- a composite number.
- prime as well as composite.
- neither prime nor composite.
View Solution
5.
PQ and PR are two tangents to a circle with centre O and radius 5 cm. AB is another tangent to the circle at C which lies on OP. If OP = 13 cm, then find the length AB and PA.
View Solution
6.
Prove that :
$\frac{\tan \theta}{1 - \cot \theta} + \frac{\cot \theta}{1 - \tan \theta} = 1 + \tan \theta + \cot \theta$.
View Solution

View All

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NCERT Solutions for class 10 Maths chapter 15 Probability

Download PDF: NCERT Solutions for Class 10 Mathematics Chapter 15 pdf

NCERT Solutions for Class 10 Mathematics Chapter 15

Class 10 Mathematics Chapter 15 Probability – Important Topics

NCERT Solutions for Class 10 Maths Chapter 15 Exercises

CBSE X Related Questions

1.
The first term of an AP is $p$ and the common difference is $q$, then its 10th term is :

2.
Prove that: $\frac{\tan \theta}{1 - \cot \theta} + \frac{\cot \theta}{1 - \tan \theta} = 1 + \tan \theta + \cot \theta$

3.
A chord of a circle, of radius 14 cm, subtends an angle of $60^\circ$ at the centre. Find the area of the smaller sector and perimeter of the smaller segment.

4.
The natural number 1 is :

5.
PQ and PR are two tangents to a circle with centre O and radius 5 cm. AB is another tangent to the circle at C which lies on OP. If OP = 13 cm, then find the length AB and PA.

6.
Prove that :
\(\frac{\tan \theta}{1 - \cot \theta} + \frac{\cot \theta}{1 - \tan \theta} = 1 + \tan \theta + \cot \theta\).

Similar Mathematics Concepts

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NCERT Solutions for class 10 Maths chapter 15 Probability

Download PDF: NCERT Solutions for Class 10 Mathematics Chapter 15 pdf

NCERT Solutions for Class 10 Mathematics Chapter 15

Class 10 Mathematics Chapter 15 Probability – Important Topics

NCERT Solutions for Class 10 Maths Chapter 15 Exercises

CBSE X Related Questions

1.The first term of an AP is $p$ and the common difference is $q$, then its 10th term is :

2.Prove that: $\frac{\tan \theta}{1 - \cot \theta} + \frac{\cot \theta}{1 - \tan \theta} = 1 + \tan \theta + \cot \theta$

3.A chord of a circle, of radius 14 cm, subtends an angle of $60^\circ$ at the centre. Find the area of the smaller sector and perimeter of the smaller segment.

4.The natural number 1 is :

5.PQ and PR are two tangents to a circle with centre O and radius 5 cm. AB is another tangent to the circle at C which lies on OP. If OP = 13 cm, then find the length AB and PA.

6.Prove that : \(\frac{\tan \theta}{1 - \cot \theta} + \frac{\cot \theta}{1 - \tan \theta} = 1 + \tan \theta + \cot \theta\).

Similar Mathematics Concepts

Comments

SUBSCRIBE TO OUR NEWS LETTER

1.
The first term of an AP is $p$ and the common difference is $q$, then its 10th term is :

2.
Prove that: $\frac{\tan \theta}{1 - \cot \theta} + \frac{\cot \theta}{1 - \tan \theta} = 1 + \tan \theta + \cot \theta$

3.
A chord of a circle, of radius 14 cm, subtends an angle of $60^\circ$ at the centre. Find the area of the smaller sector and perimeter of the smaller segment.

4.
The natural number 1 is :

5.
PQ and PR are two tangents to a circle with centre O and radius 5 cm. AB is another tangent to the circle at C which lies on OP. If OP = 13 cm, then find the length AB and PA.

6.
Prove that :
\(\frac{\tan \theta}{1 - \cot \theta} + \frac{\cot \theta}{1 - \tan \theta} = 1 + \tan \theta + \cot \theta\).