NCERT Solutions for Class 10 Maths Chapter 15 Probability Exercise 15.1

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NCERT Solutions for Class 10 Maths Chapter 15 Probability Exercise 15.1 Solutions are based on the following concepts:

Occurrence of an event
Impossible Events
Sure Event

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Check out NCERT Solutions for Class 10 Maths Chapter 15 Probability Exercise 15.1 Solutions

Exercise Solutions of Class 10 Maths Chapter 15 Probability

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NCERT Solutions for Class 10 Maths Chapter 15 Probability Exercise 15.2 Solutions

Also Check:

Probability Chapter Related Topics
Theoretical Probability	Equally Likely Events	Empirical Probability
Events in Probability	Complimentary Events	A Theoretical Approach to Probability
P Value	Experimental Probability	Elementary Event
Sum of Probabilities	Geometric Probability	Chance and Probability
Empirical Probability Formula	Poisson Distribution Formula	Standard Normal Distribution

Also check:

Math Study Guides
Maths Important Formulas	Maths MCQs	Comparison Articles in Maths
Difference Between Topics in Maths	Math Study Material	Arithmetic
Class 10 Maths Notes	Permutations and Combinations	Mensuration
Trigonometry	Number Systems	Geometry
Math Formula	NCERT Solutions for Class 10 Maths	Algebra

CBSE X Related Questions

1.
In the figure given above, \(\triangle ABC \sim \triangle XYZ\), then find the values of \(x\) and \(y\).
View Solution
2.
The natural number 1 is :
- a prime number.
- a composite number.
- prime as well as composite.
- neither prime nor composite.
View Solution
3.
In the given figure, \(AB \parallel DE\) and \(AC \parallel DF\). Show that \(\triangle ABC \sim \triangle DEF\). If \(BC = 10\) cm, \(EB = CF = 5\) cm and \(AB = 7\) cm, then find the length DE.
View Solution
4.
In a class test, the sum of Anamika's marks obtained in Maths and Science is 30. Had she got 2 marks more in Maths and 3 marks less in Science, the product of the marks would have been 210. Find the marks she got in the two subjects.
View Solution
5.
Find the greatest number less than 10,000 which is exactly divisible by 48, 60 and 65.
View Solution
6.
In the given figure, PA and PB are tangents to a circle centred at O. If \( \angle AOB = 130^\circ \), then \( \angle APB \) is equal to :
- \( 130^\circ \)
- \( 50^\circ \)
- \( 120^\circ \)
- \( 90^\circ \)
View Solution

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NCERT Solutions for Class 10 Maths Chapter 15 Probability Exercise 15.1

Exercise Solutions of Class 10 Maths Chapter 15 Probability

CBSE X Related Questions

1.
In the figure given above, \(\triangle ABC \sim \triangle XYZ\), then find the values of \(x\) and \(y\).

2.
The natural number 1 is :

3.
In the given figure, \(AB \parallel DE\) and \(AC \parallel DF\). Show that \(\triangle ABC \sim \triangle DEF\). If \(BC = 10\) cm, \(EB = CF = 5\) cm and \(AB = 7\) cm, then find the length DE.

4.
In a class test, the sum of Anamika's marks obtained in Maths and Science is 30. Had she got 2 marks more in Maths and 3 marks less in Science, the product of the marks would have been 210. Find the marks she got in the two subjects.

5.
Find the greatest number less than 10,000 which is exactly divisible by 48, 60 and 65.

6.
In the given figure, PA and PB are tangents to a circle centred at O. If \( \angle AOB = 130^\circ \), then \( \angle APB \) is equal to :

Similar Mathematics Concepts

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NCERT Solutions for Class 10 Maths Chapter 15 Probability Exercise 15.1

Exercise Solutions of Class 10 Maths Chapter 15 Probability

CBSE X Related Questions

1.In the figure given above, \(\triangle ABC \sim \triangle XYZ\), then find the values of \(x\) and \(y\).

2.The natural number 1 is :

3.In the given figure, \(AB \parallel DE\) and \(AC \parallel DF\). Show that \(\triangle ABC \sim \triangle DEF\). If \(BC = 10\) cm, \(EB = CF = 5\) cm and \(AB = 7\) cm, then find the length DE.

4.In a class test, the sum of Anamika's marks obtained in Maths and Science is 30. Had she got 2 marks more in Maths and 3 marks less in Science, the product of the marks would have been 210. Find the marks she got in the two subjects.

5.Find the greatest number less than 10,000 which is exactly divisible by 48, 60 and 65.

6.In the given figure, PA and PB are tangents to a circle centred at O. If \( \angle AOB = 130^\circ \), then \( \angle APB \) is equal to :

Similar Mathematics Concepts

Comments

SUBSCRIBE TO OUR NEWS LETTER

1.
In the figure given above, \(\triangle ABC \sim \triangle XYZ\), then find the values of \(x\) and \(y\).

2.
The natural number 1 is :

3.
In the given figure, \(AB \parallel DE\) and \(AC \parallel DF\). Show that \(\triangle ABC \sim \triangle DEF\). If \(BC = 10\) cm, \(EB = CF = 5\) cm and \(AB = 7\) cm, then find the length DE.

4.
In a class test, the sum of Anamika's marks obtained in Maths and Science is 30. Had she got 2 marks more in Maths and 3 marks less in Science, the product of the marks would have been 210. Find the marks she got in the two subjects.

5.
Find the greatest number less than 10,000 which is exactly divisible by 48, 60 and 65.

6.
In the given figure, PA and PB are tangents to a circle centred at O. If \( \angle AOB = 130^\circ \), then \( \angle APB \) is equal to :