NCERT Solutions for Class 10 Maths Chapter 15 Probability Exercise 15.1

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NCERT Solutions for Class 10 Maths Chapter 15 Probability Exercise 15.1 Solutions are based on the following concepts:

Occurrence of an event
Impossible Events
Sure Event

Download PDF NCERT Solutions for Class 10 Maths Chapter 15 Probability Exercise 15.1

Check out NCERT Solutions for Class 10 Maths Chapter 15 Probability Exercise 15.1 Solutions

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Exercise Solutions of Class 10 Maths Chapter 15 Probability

Also check other Exercise Solutions of Class 10 Maths Chapter 15 Probability

NCERT Solutions for Class 10 Maths Chapter 15 Probability Exercise 15.2 Solutions

Also Check:

Probability Chapter Related Topics
Theoretical Probability	Equally Likely Events	Empirical Probability
Events in Probability	Complimentary Events	A Theoretical Approach to Probability
P Value	Experimental Probability	Elementary Event
Sum of Probabilities	Geometric Probability	Chance and Probability
Empirical Probability Formula	Poisson Distribution Formula	Standard Normal Distribution

Also check:

Math Study Guides
Maths Important Formulas	Maths MCQs	Comparison Articles in Maths
Difference Between Topics in Maths	Math Study Material	Arithmetic
Class 10 Maths Notes	Permutations and Combinations	Mensuration
Trigonometry	Number Systems	Geometry
Math Formula	NCERT Solutions for Class 10 Maths	Algebra

CBSE X Related Questions

1.
The natural number 1 is :
- a prime number.
- a composite number.
- prime as well as composite.
- neither prime nor composite.
View Solution
2.
Use graphical method to solve the system of linear equations : $x = -3$ and $5x - 2y = -5$.
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3.
A bag contains 25 balls. Some of them are yellow and others are green. One ball is drawn at random. If probability of getting a green ball is $3/5$, then find the number of yellow balls.
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4.
Prove that: $\frac{\tan \theta}{1 - \cot \theta} + \frac{\cot \theta}{1 - \tan \theta} = 1 + \tan \theta + \cot \theta$
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5.
Prove that :
\(\frac{\tan \theta}{1 - \cot \theta} + \frac{\cot \theta}{1 - \tan \theta} = 1 + \tan \theta + \cot \theta\).
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6.
If the zeroes of a polynomial p(x) are $-3$ and 8, then p(x) equals
- $x^2 + 5x - 4$
- $(x + 3) (-x + 8)$
- $a(x^2 + 5x - 24)$
- $x^2 - 24$
View Solution

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