NCERT Solutions for Class 10 Maths Chapter 14 Statistics Exercise 14.1

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NCERT Solutions for Class 10 Maths Chapter 14 Statistics Exercise 14.1 Solutions are based on the following topics:

Direct Method
Assumed Mean Method
Step Deviation Method

Download PDF NCERT Solutions for Class 10 Maths Chapter 14 Statistics Exercise 14.1 Solutions

Check out NCERT Solutions for Class 10 Maths Chapter 14 Statistics Exercise 14.1 Solutions

Read More: NCERT Solutions For Class 10 Maths Chapter 14 Statistics

Exercise Solutions of Class 10 Maths Chapter 14 Statistics

Also check other Exercise Solutions of Class 10 Maths Chapter 14 Statistics

Also Check:

Chapter Related Topics
Mean of Grouped Data	Statistics Important Question	Statistics Revision Notes
Cumulative Frequency Curve	Class Mark	Statistics for Class 10
Mean Formula	Confidence Interval	Confidence Interval Formula

Also Check:

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Math Formula	NCERT Solutions for Class 10 Maths	Algebra

CBSE X Related Questions

1.
Prove that :
\(\frac{\tan \theta}{1 - \cot \theta} + \frac{\cot \theta}{1 - \tan \theta} = 1 + \tan \theta + \cot \theta\).
View Solution
2.
The HCF of 960 and 432 is :
- 48
- 54
- 72
- 36
View Solution
3.
The natural number 1 is :
- a prime number.
- a composite number.
- prime as well as composite.
- neither prime nor composite.
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4.
\(ABCD\) is a parallelogram such that \(AF = 7 \text{ cm}\), \(FB = 3 \text{ cm}\) and \(EF = 4 \text{ cm}\), length \(FD\) equals
- \(\frac{21}{4} \text{ cm}\)
- \(\frac{28}{3} \text{ cm}\)
- \(\frac{12}{7} \text{ cm}\)
- \(5.5 \text{ cm}\)
View Solution
5.
If the pair of linear equations : \( a_1x + b_1y + c_1 = 0 \) and \( a_2x + b_2y + c_2 = 0 \) is consistent and dependent, then
- \( \frac{a_1}{a_2} \neq \frac{b_1}{b_2} \)
- \( \frac{a_1}{a_2} = \frac{b_1}{b_2} = \frac{c_1}{c_2} \)
- \( \frac{a_1}{a_2} = \frac{b_1}{b_2} \neq \frac{c_1}{c_2} \)
- \( \frac{a_1}{a_2} = \frac{b_1}{b_2} = \frac{c_1}{c_2} \)
View Solution
6.
The first term of an AP is $p$ and the common difference is $q$, then its 10th term is :
- $q - 9p$
- $p - 9q$
- $p + 9q$
- $2p + 9q$
View Solution

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