NCERT Solutions For Class 10 Maths Chapter 14: Statistics

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NCERT Solutions for class 10 Maths Chapter 14 Statistics are provided in the article below. Some of the important topics of Statistics chapter include:

Expected no of questions: 2 to 3 questions of total 5 marks

Download PDF: NCERT Solutions for Class 10 Mathematics Chapter 14 pdf

NCERT Solutions for Class 10 Mathematics Chapter 14

NCERT Solutions for Class 10 Maths Chapter 14 Statistics is given below.

NCERT Solution class 10 mathematics chapter 14 statistics

Class 10 Mathematics Chapter 14 Statistics – Important Topics

Study of collection, presentation, organisation and analysis of data is known as Statistics.

Important formulas in Statistics include:

Mean x = ∑x / n

Median [if n is odd] = (n+1 /2)

Median [if n is even] = [(n/2)th + (n+1 /2)] / 2

Standard Deviation σ = √∑ni=1(xi-μμ)² /n

Variance σ² = ∑ni=1(xi-μμ)² /n

Average of a given set of numbers is known as the mean.
Middle Value in a given set of data is known as median.
Most Occurring item in a given set of data is known as mode.
A measure which gives an approximate idea about data is known as variance. It is used to calculate standard deviation of a data set.
We can find how far a value is from the mean by the help of Standard Deviation. It can be found by taking the square root of Variance.

NCERT Solutions for Class 10 Maths Chapter 14 Exercises

NCERT Solutions for Class 10 Mathematics Chapter 14 Statistics Exercises are given below.

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CBSE X Related Questions

1.
$ABCD$ is a parallelogram such that $AF = 7 \text{ cm}$, $FB = 3 \text{ cm}$ and $EF = 4 \text{ cm}$, length $FD$ equals
- $\frac{21}{4} \text{ cm}$
- $\frac{28}{3} \text{ cm}$
- $\frac{12}{7} \text{ cm}$
- $5.5 \text{ cm}$
View Solution
2.
The first term of an AP is $p$ and the common difference is $q$, then its 10th term is :
- $q - 9p$
- $p - 9q$
- $p + 9q$
- $2p + 9q$
View Solution
3.
Prove that :
$\frac{\tan \theta}{1 - \cot \theta} + \frac{\cot \theta}{1 - \tan \theta} = 1 + \tan \theta + \cot \theta$.
View Solution
4.
A bag contains 25 balls. Some of them are yellow and others are green. One ball is drawn at random. If probability of getting a green ball is $3/5$, then find the number of yellow balls.
View Solution
5.
Assertion (A) : H.C.F. $(36 m^{2}, 18 m) = 18 m$, where $m$ is a prime number.
Reason (R) : H.C.F. of two numbers is always less than or equal to the smaller number.
- Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of the Assertion (A).
- Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of the Assertion (A).
- Assertion (A) is true, but Reason (R) is false.
- Assertion (A) is false, but Reason (R) is true.
View Solution
6.
A kite is flying at a height of $60 \text{ m}$ above the ground level. Ravi, standing at the roof of the house is holding the string straight and observes the angle of elevation of kite as $30^{\circ}$. From the bottom of the same building, the angle of elevation of kite is $45^{\circ}$. Find the length of the string and height of roof from the ground. (Use $\sqrt{3} = 1.73$)
View Solution

View All

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NCERT Solutions For Class 10 Maths Chapter 14: Statistics

Download PDF: NCERT Solutions for Class 10 Mathematics Chapter 14 pdf

NCERT Solutions for Class 10 Mathematics Chapter 14

Class 10 Mathematics Chapter 14 Statistics – Important Topics

NCERT Solutions for Class 10 Maths Chapter 14 Exercises

CBSE X Related Questions

1.
\(ABCD\) is a parallelogram such that \(AF = 7 \text{ cm}\), \(FB = 3 \text{ cm}\) and \(EF = 4 \text{ cm}\), length \(FD\) equals

2.
The first term of an AP is $p$ and the common difference is $q$, then its 10th term is :

3.
Prove that :
\(\frac{\tan \theta}{1 - \cot \theta} + \frac{\cot \theta}{1 - \tan \theta} = 1 + \tan \theta + \cot \theta\).

4.
A bag contains 25 balls. Some of them are yellow and others are green. One ball is drawn at random. If probability of getting a green ball is $3/5$, then find the number of yellow balls.

5.
Assertion (A) : H.C.F. \((36 m^{2}, 18 m) = 18 m\), where \(m\) is a prime number.
Reason (R) : H.C.F. of two numbers is always less than or equal to the smaller number.

Similar Mathematics Concepts

Comments

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NCERT Solutions For Class 10 Maths Chapter 14: Statistics

Download PDF: NCERT Solutions for Class 10 Mathematics Chapter 14 pdf

NCERT Solutions for Class 10 Mathematics Chapter 14

Class 10 Mathematics Chapter 14 Statistics – Important Topics

NCERT Solutions for Class 10 Maths Chapter 14 Exercises

CBSE X Related Questions

1.\(ABCD\) is a parallelogram such that \(AF = 7 \text{ cm}\), \(FB = 3 \text{ cm}\) and \(EF = 4 \text{ cm}\), length \(FD\) equals

2.The first term of an AP is $p$ and the common difference is $q$, then its 10th term is :

3.Prove that : \(\frac{\tan \theta}{1 - \cot \theta} + \frac{\cot \theta}{1 - \tan \theta} = 1 + \tan \theta + \cot \theta\).

4.A bag contains 25 balls. Some of them are yellow and others are green. One ball is drawn at random. If probability of getting a green ball is $3/5$, then find the number of yellow balls.

5.Assertion (A) : H.C.F. \((36 m^{2}, 18 m) = 18 m\), where \(m\) is a prime number. Reason (R) : H.C.F. of two numbers is always less than or equal to the smaller number.

Similar Mathematics Concepts

Comments

SUBSCRIBE TO OUR NEWS LETTER

1.
\(ABCD\) is a parallelogram such that \(AF = 7 \text{ cm}\), \(FB = 3 \text{ cm}\) and \(EF = 4 \text{ cm}\), length \(FD\) equals

2.
The first term of an AP is $p$ and the common difference is $q$, then its 10th term is :

3.
Prove that :
\(\frac{\tan \theta}{1 - \cot \theta} + \frac{\cot \theta}{1 - \tan \theta} = 1 + \tan \theta + \cot \theta\).

4.
A bag contains 25 balls. Some of them are yellow and others are green. One ball is drawn at random. If probability of getting a green ball is $3/5$, then find the number of yellow balls.

5.
Assertion (A) : H.C.F. \((36 m^{2}, 18 m) = 18 m\), where \(m\) is a prime number.
Reason (R) : H.C.F. of two numbers is always less than or equal to the smaller number.