NCERT Solutions for Class 10 Maths Chapter 14 Statistics Exercise 14.2

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NCERT Solutions for Class 10 Maths Chapter 14 Statistics Exercise 14.2 Solutions are based on finding the mode of grouped data along with finding the mean value.

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Check out NCERT Solutions for Class 10 Maths Chapter 14 Statistics Exercise 14.2 Solutions

Exercise Solutions of Class 10 Maths Chapter 14 Statistics

Also check other Exercise Solutions of Class 10 Maths Chapter 14 Statistics

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Chapter Related Topics
Mean of Grouped Data	Statistics Important Question	Statistics Revision Notes
Cumulative Frequency Curve	Class Mark	Statistics for Class 10
Mean Formula	Confidence Interval	Confidence Interval Formula
Step Deviation Method	Differences between Correlation and Regression

Also Check:

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Math Formula	NCERT Solutions for Class 10 Maths	Algebra

CBSE X Related Questions

1.
There are two sections A and B of Grade X. There are 28 students in Section A and 30 students in Section B. What is the minimum number of books you will acquire for the class library so that they can be distributed equally among students of Section A or Section B ?
- 144
- 2
- 420
- 272
View Solution
2.
Which of the following graphs represents a polynomial with both zeroes being positive?
View Solution
3.
Assertion (A) : H.C.F. \((36 m^{2}, 18 m) = 18 m\), where \(m\) is a prime number.
Reason (R) : H.C.F. of two numbers is always less than or equal to the smaller number.
- Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of the Assertion (A).
- Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of the Assertion (A).
- Assertion (A) is true, but Reason (R) is false.
- Assertion (A) is false, but Reason (R) is true.
View Solution
4.
It is given that \(\triangle ABC \sim \triangle EDF\). Which of the following is not true?
- \(\frac{\text{Perimeter of } \triangle ABC}{\text{Perimeter of } \triangle EDF} = \frac{AB}{ED}\)
- \(\frac{AB}{ED} = \frac{AC}{EF}\)
- \(\angle A = \angle D, \angle C = \angle F\)
- \(\frac{AB + BC}{AC} = \frac{ED + DF}{EF}\)
View Solution
5.
For an acute angle \(\theta\), if \(\sin \theta = \frac{1}{9}\), then value of \(\frac{9 \csc \theta + 1}{9 \csc \theta - 1}\) is
- \(0\)
- \(\frac{80}{81}\)
- \(1\)
- \(\frac{82}{80}\)
View Solution
6.
Mean and Median of a frequency distribution are 43 and 40 respectively. The value of mode is
- 34
- 43
- 38.5
- 41.5
View Solution

View All

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NCERT Solutions for Class 10 Maths Chapter 14 Statistics Exercise 14.2

Exercise Solutions of Class 10 Maths Chapter 14 Statistics

CBSE X Related Questions

1.
There are two sections A and B of Grade X. There are 28 students in Section A and 30 students in Section B. What is the minimum number of books you will acquire for the class library so that they can be distributed equally among students of Section A or Section B ?

2.
Which of the following graphs represents a polynomial with both zeroes being positive?

3.
Assertion (A) : H.C.F. \((36 m^{2}, 18 m) = 18 m\), where \(m\) is a prime number.
Reason (R) : H.C.F. of two numbers is always less than or equal to the smaller number.

4.
It is given that \(\triangle ABC \sim \triangle EDF\). Which of the following is not true?

5.
For an acute angle \(\theta\), if \(\sin \theta = \frac{1}{9}\), then value of \(\frac{9 \csc \theta + 1}{9 \csc \theta - 1}\) is

6.
Mean and Median of a frequency distribution are 43 and 40 respectively. The value of mode is

Similar Mathematics Concepts

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NCERT Solutions for Class 10 Maths Chapter 14 Statistics Exercise 14.2

Exercise Solutions of Class 10 Maths Chapter 14 Statistics

CBSE X Related Questions

1.There are two sections A and B of Grade X. There are 28 students in Section A and 30 students in Section B. What is the minimum number of books you will acquire for the class library so that they can be distributed equally among students of Section A or Section B ?

2.Which of the following graphs represents a polynomial with both zeroes being positive?

3.Assertion (A) : H.C.F. \((36 m^{2}, 18 m) = 18 m\), where \(m\) is a prime number. Reason (R) : H.C.F. of two numbers is always less than or equal to the smaller number.

4.It is given that \(\triangle ABC \sim \triangle EDF\). Which of the following is not true?

5.For an acute angle \(\theta\), if \(\sin \theta = \frac{1}{9}\), then value of \(\frac{9 \csc \theta + 1}{9 \csc \theta - 1}\) is

6.Mean and Median of a frequency distribution are 43 and 40 respectively. The value of mode is

Similar Mathematics Concepts

Comments

SUBSCRIBE TO OUR NEWS LETTER

1.
There are two sections A and B of Grade X. There are 28 students in Section A and 30 students in Section B. What is the minimum number of books you will acquire for the class library so that they can be distributed equally among students of Section A or Section B ?

2.
Which of the following graphs represents a polynomial with both zeroes being positive?

3.
Assertion (A) : H.C.F. \((36 m^{2}, 18 m) = 18 m\), where \(m\) is a prime number.
Reason (R) : H.C.F. of two numbers is always less than or equal to the smaller number.

4.
It is given that \(\triangle ABC \sim \triangle EDF\). Which of the following is not true?

5.
For an acute angle \(\theta\), if \(\sin \theta = \frac{1}{9}\), then value of \(\frac{9 \csc \theta + 1}{9 \csc \theta - 1}\) is

6.
Mean and Median of a frequency distribution are 43 and 40 respectively. The value of mode is