Perimeter of a Parallelogram: Properties, Formula & Examples

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Arpita Srivastava

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Perimeter of a parallelogram is equivalent to the sum of all sides of the parallelogram. It is a type of quadrilateral that has four sides. When the opposite sides of a quadrilateral are parallel and of equal length, it is termed as parallelogram. 

  • Perimeter of a parallelogram is the distance covered along the boundary.
  • The perimeter is calculated when sides and diagonals are known.
  • The opposite angles of the figure are equal.
  • Diagonals bisect each other at 90 degrees.
  • Θ is the angle formed at the vertex of the parallelogram.
  • There is no line of symmetry in the case of the given figure.
  • The rhombus, rectangle, and square are all examples of parallelograms.
  • Perimeter of a parallelogram is equal to the perimeter of a rectangle.

Read More: Area of Parallelogram

Key Terms: Perimeter of a Parallelogram, Parallelogram, Rectangle, Rhombus, Square, Sides, Diagonals, Quadrilateral, Height


Perimeter of a Parallelogram

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The perimeter of a parallelogram is equal to the sum of all its sides since it is the length of its outline. Parallelogram is a type of quadrilateral, which has four sides. 

  • The pair of opposite sides are parallel and equal to each other in a parallelogram. 
  • The length, width and height measure the area and perimeter of the parallelogram.

The perimeter of a parallelogram is calculated in the following cases:

  • When two adjacent sides are known.
  • When one side and diagonals are known.
  • When the height, base and any angle are given.

Perimeter of a Parallelogram

Perimeter of a Parallelogram

Read More: Difference between Square and Rhombus


How to find Perimeter of a Parallelogrm?

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There are three cases available to calculate the perimeter of a parallelogram which are discussed in below section:

Perimeter of a Parallelogram when sides are given

In case of a parallelogram, opposite sides are equal. Let’s consider a parallelogram with two adjacent sides named a and b.Then Perimeter of parallelogram is a+b+c+d or 2a + 2b= 2(a+b). Therefore, P = 2(a+b).

P = 2(a+b)
Perimeter of a Parallelogram

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Perimeter of a Parallelogram when one side and diagonals are given

Let us consider a parallelogram with sides a & b and diagonals y & x. Now apply the law of cosines rule in triangle ABD,

  • x2 = a2 + b2 – 2ab.cos ∠BAD ---(1)
  • Also apply cosine rule in triangle ADC,
  • y2 = a2 + b2 – 2ab.cos ∠ADC ---(2)
  • Now, By adding equation 1 and 2 then we get;
  • x2 + y2 = 2a2 + 2b2 – 2ab (cos ∠BAD + cos ∠ADC ) ---(3)
  • We know that the two adjacent angles of Parallelogram are 180o.
  • So, ∠BAD + ∠ADC = 180o
  • ∠BAD = 1800 - ∠ADC
  • By applying cos on both sides
  • Cos ∠BAD = cos (180o - ∠ADC)
  • Cos ∠BAD = - cos ∠ADC ---(4)
  • Now, put equation number 4 in equation 3, we get
  • x2 + y2 = 2a2 + 2b2 – 2ab (- cos ∠ADC + cos ∠ADC) 
  • x2 + y2 = 2a2 + 2b2 – 2ab(0)
  • x2 + y2 = 2a2 + 2b2
  • For length ‘b’
  • 2b2 = x2 + y2 - 2a2
  • b2 = (x2 + y2 – 2a2) /2 
  • b = √ [(x2 + y2 – 2a2) /2 ]
  • Now the formula for perimeter (P)is:
  • P = 2a +2b
  • P = 2a + 2 √ [(x2 + y2 – 2a2) /2 ]
  • P = 2a + √ [(x2 + y2 – 2a2)

P = 2a + √ [(2x2 +2y2 – 4a2)

P = 2a + ? [(2x2 +2y2 – 4a2)
Perimeter of a Parallelogram

Perimeter of a Parallelogram when the height, base and angle are given

Let consider the parallelogram with one of the sides a and its corresponding to height ‘h’ and with vertex angle θ. Assume the unknown sides of parallelogram be ‘b’.

  • By applying sin rule in triangle BEC,
  • Sin θ = h/b
  •  b= h/ sin θ
  • therefore, the perimeter of parallelogram is:
  • P = 2a + 2b

P = 2a + 2h/ sin θ

P = 2a + 2h/ sin ?
Perimeter of a Parallelogram

Read More: Perimeter of a Trapezoid


Perimeter of a Parallelogram Formula

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There are different formulas to calculate the perimeter of a parallelogram using different components. Let a and b be the two sides of the parallelogram. Θ is the angle formed between the vertex of parallelogram and h is the height of the parallelogram.

  • Perimeter of a Parallelogram when sides are given

P = 2(a+b)

Read More:Surface Area and Volumes

Solved Example for Perimeter of a Parallelogram when sides are given

Example: Find the perimeter of a parallelogram whose adjacent sides are 9 units and 9 units.

Solution: The adjacent sides of the given parallelogram are, a = 9 units and b = 9 units. Then its perimeter (P) is,

P = 2 (a + b)

P = 2 (9 + 9) = 2 (18) = 36 units.

  • Perimeter of a Parallelogram when one side and diagonals are given

P = 2a + √ [(2x2 +2y2 – 4a2)

Read More: Triangle Theorems 

Solved Example for Perimeter of a Parallelogram when one side and diagonals are given

Example:  Find the perimeter of a parallelogram when one of its sides is 6 units and diagonals are 8 units and 10 units.

Solution: Using the formula when a side and diagonals of a parallelogram are given, we P = 2a + √(2x2 + 2y2 - 4a2). Here a = 7, x = 8, y = 10. Substituting these values into the formula, we have

P = 2a + √(2x2 + 2y2 - 4a2)

= 2 × 6 + √(2(8)2 + 2(10)2 - 4(7)2)

= 12 + √(2 × 64 + 2 × 100 - 4 × 49)

= 12 + √(128 + 200 - 196)

= 12 + √(132)

= 12 + 11.49

= 23.49

  • Perimeter of a Parallelogram when the height, base and angle are given

P = 2a + 2h/ sin θ

Solved Example for Perimeter of a Parallelogram when the height, base and angle are given

Example: What is the perimeter of a parallelogram where one of its sides is 20 yards, its corresponding height is 20 yards, and one of the vertex angles is 30 degrees?

Solution:

One of the sides of the given parallelogram is, a = 20 yards.

Its height is h = 20 yards.

One vertex angle is, θ = 30°.

Its perimeter (P) is,

P = 2a + 2h / sin θ

P = 2(20) + (2 × 20) / (sin 30°) = 120 yards

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Things to Remember

  • The perimeter of a parallelogram is the sum of all lengths enclosed by the boundary.
  • A parallelogram is a four-sided polygon with two parallel sides that also has four edges.
  • If one of the angles in a parallelogram is a right angle, then all four angles must be right angles.
  • The perimeter of a parallelogram is also equivalent to the perimeter of a rectangle.
  • The length of the opposite sides of a parallelogram is the same because they are equal in length.

Read More: Areas of Parallelograms and Triangle


Sample Questions

Ques: Find the perimeter of a parallelogram whose length is 10 cm and breadth is 8 cm. (3 marks)

Ans: Given: length =10 cm & breadth = 8 cm

We also know that formula for perimeter of parallelogram;

 = 2 (l+ b)

= 2 (10+8)

= 2 (18)

= 36 cm.

Therefore, the perimeter of the parallelogram is 36 cm.

Ques: Find the perimeter of parallelogram which length is 50 cm and breadth is 40 cm. (3 marks)

Ans: Given: length = 50 cm & breadth = 40 cm

We know that the formula for perimeter of parallelogram;

 = 2 (l+ b)

= 2 (50+40)

= 2 (90)

= 180 cm

Therefore, Perimeter of the parallelogram is 180 cm.

Ques: What is the perimeter of parallelogram if length of side is 8 cm and diagonals are 10 and 12 cm. (3 marks)

Ans: Given: Side ‘a’ = 8 cm, Diagonals x= 10cm & y = 12 cm

By using the formula of perimeter of parallelogram when side and diagonal given the we get;

P = 2a + √ [(2x2 +2y2 – 4a2)

P = 2(8) + √ [(2(10)2 +2(12)2 – 4(8)2)

P = 31.2 cm

Therefore, Perimeter of the parallelogram is 31.2 cm.

Ques: On a graph, how do you find the perimeter of a parallelogram. (2 marks)

Ans: The perimeter of a parallelogram with adjacent sides 'a' and 'b' is also equal to 2a + 2b, as we know. To find the perimeter of a parallelogram on a graph, we use the distance formula to find the lengths of any two adjacent sides then use the formula 2a + 2b to find its perimeter.

Ques: Find is the perimeter of parallelogram when the height is 20 m and one of its sides is 15 meter & one vertex angle is 450. (3 marks)

Ans: Given; Side ‘a’ = 15 m, height ‘h’ = 20m and vertex angle = 450.

We know the formula of perimeter when side, angle and vertex is given,

P = 2a + 2h/ sin θ

P = 2(15) + 2(20)/ sin 45o

P = 86.56 m

Therefore the perimeter of parallelogram is 86.56 m.

Ques: What is the perimeter of parallelogram when sides are 33 m and 27 m. (3 marks)

Ans: Given: Sides of parallelogram ‘a’ =33 m & ’b’ = 27 m

We also know that the formula for perimeter of parallelogram;

 = 2 (a+ b)

= 2 (60)

= 2 (60)

= 120 m

Therefore, the perimeter of the parallelogram is 120 m.

Ques: What is the perimeter of a parallelogram whose length is 5 m and diagonals are 12 m and 10 m. (3 marks)

Ans: Given: length ‘a’ = 5 m, Diagonals x= 12 m & y = 10 m

By using the formula of perimeter of parallelogram when side and diagonal given;

P = 2a + √ [(2x2 +2y2 – 4a2)

P = 2(5) + √ [(2(12)2 +2(10)2 – 4(5)2)

P = 29.69 m

Therefore, the perimeter of parallelogram is 29.69 m.

Ques: Find the perimeter of parallelogram if the length is 44 m and breadth is 36 m. (3 marks)

Ans: Given: length =44 m & breadth = 36 m

By applying the formula for perimeter of parallelogram we get;

 = 2 (l+ b)

= 2 (44+36)

= 2 (80)

= 160 m

Therefore, the perimeter of the parallelogram is 160 m.

Ques: The length of parallelogram is 15 inches and the breadth is 9 inch then find the perimeter of parallelogram. (3 marks)

Ans: Given; length =15 in & breadth = 9 in.

By applying the formula for perimeter of parallelogram is;

 = 2 (l+ b)

= 2 (15+9)

= 2 (24)

= 48 in.

Therefore, the perimeter of the parallelogram is 48 inches.

Ques: Find the perimeter of a parallelogram whose length is 10 cm and breadth is 18 cm. (3 marks)

Ans: Given: length =10 cm & breadth = 18 cm

We also know that formula for perimeter of parallelogram;

 = 2 (l+ b)

= 2 (10+18)

= 2 (28)

= 56 cm.

Therefore, the perimeter of a parallelogram is 36 cm.

Ques: Find the perimeter of parallelogram which length is 150 cm and breadth is 140 cm. (3 marks)

Ans: Given: length = 150 cm & breadth = 140 cm

We know that the formula for perimeter of parallelogram;

 = 2 (l+ b)

= 2 (150+140)

= 2 (190)

= 380 cm

Therefore, Perimeter of a parallelogram is 380 cm.

Ques: The perimeter of a parallelogram is equal to 48 cm and one of its sides is 12 cm. Find the length of the other side. (3 marks)

Ans: Given: Perimeter (P) = 48 cm, and side, a = 12 cm. To find the length of the other side b of the parallelogram, we will use the formula of the perimeter of a parallelogram P = 2(a + b).

P = 2(a + b)

⇒ 48 = 2 (12 + b)

⇒ 12 + b = 48/2

⇒ b = 24 - 12

⇒ b = 12 cm

Ques What is the perimeter of a parallelogram when the height is 30cm, the vertex angle is 45°, and one of the sides is 12cm. (3 marks)

Ans: The perimeter of a parallelogram is given by:

  • P = 2a + 2h/sinθ
  • P = 2 × 12 + 2 × 30/sin45
  • P = 24 + 84.5
  • P = 24 + 84.5
  • P = 108.5 cm

Ques: Find is the perimeter of parallelogram when the height is 60 m and one of its sides is 20 meter & one vertex angle is 450. (3 marks)

Ans: Given; Side ‘a’ = 20 m, height ‘h’ = 60m and vertex angle = 450.

We know the formula of perimeter when side, angle and vertex is given,

P = 2a + 2h/ sin θ

P = 2(20) + 2(60)/ sin 45o

P = 209.01 m

Therefore the perimeter of parallelogram is 209.01 m.

Ques: What is the perimeter of parallelogram when sides are 30 m and 57 m. (3 marks)

Ans: Given: Sides of parallelogram ‘a’ =30 m & ’b’ = 57 m

We also know that the formula for perimeter of parallelogram;

 = 2 (a+ b)

= 2 (87)

= 174 m

Therefore, the perimeter of the parallelogram is 174 m.


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CBSE X Related Questions

  • 1.
    The graph of \(y = f(x)\) is given. The number of zeroes of \(f(x)\) is :

      • 0
      • 1
      • 3
      • 2

    • 2.
      If the pair of linear equations : \( a_1x + b_1y + c_1 = 0 \) and \( a_2x + b_2y + c_2 = 0 \) is consistent and dependent, then

        • \( \frac{a_1}{a_2} \neq \frac{b_1}{b_2} \)
        • \( \frac{a_1}{a_2} = \frac{b_1}{b_2} = \frac{c_1}{c_2} \)
        • \( \frac{a_1}{a_2} = \frac{b_1}{b_2} \neq \frac{c_1}{c_2} \)
        • \( \frac{a_1}{a_2} = \frac{b_1}{b_2} = \frac{c_1}{c_2} \)

      • 3.
        There are two sections A and B of Grade X. There are 28 students in Section A and 30 students in Section B. What is the minimum number of books you will acquire for the class library so that they can be distributed equally among students of Section A or Section B ?

          • 144
          • 2
          • 420
          • 272

        • 4.
          PQ and PR are two tangents to a circle with centre O and radius 5 cm. AB is another tangent to the circle at C which lies on OP. If \(OP = 13\) cm, then find the length AB and PA.


            • 5.
              The HCF of 960 and 432 is :

                • 48
                • 54
                • 72
                • 36

              • 6.
                The value of \(p\) for which roots of the quadratic equation \(x^{2} - px + 6 = 0\) are rational, is

                  • \(1\)
                  • \(-5\)
                  • \(25\)
                  • \(\sqrt{5}\)

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