NCERT Solutions for Class 10 Maths Chapter 7 Exercise 7.2

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NCERT Solutions for Class 10 Maths Chapter 7 Coordinate Geometry Exercise 7.2 is given in this article with a detailed explanation. Class 10 Maths Chapter 7 Exercise 7.2 has questions covering the concept of section formula.

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Check out the solutions of Class 10 Maths NCERT solutions chapter 7 Coordinate Geometry Exercise 7.1

Check out other exercise solutions of Class 10 Maths Chapter 7

Class 10 Chapter 7 Topics:

Coordinate Geometry MCQs	Cartesian System	Ordinate
Quadrant	Centroid	Midpoint Formula
Centroid Formula	Centroid of a Triangle	Point of Intersection Formula

CBSE Class 10 Maths Study Guides:

Math Formula	Math Study Notes	Trigonometry
Math MCQs	NCERT Solutions for Class 10 Maths	Difference between in Maths
Arithmetic	Mensuration	Calculus
Class 10 Notes	Number System	Geometry

CBSE X Related Questions

1.
Mean and Median of a frequency distribution are 43 and 40 respectively. The value of mode is

34
43
38.5
41.5

View Solution

2.
The graph of a quadratic polynomial f(x) passes through (5,0), (0, -1) and (-2, 0). The two factors of the polynomial are

\((x + 2), (x - 5)\)
\((x + 5), (x - 2)\)
\((x + 1), (x - 5)\)
\((x - 1), (x + 2)\)

View Solution

3.
Case Study - 1 : A model of Leafy Ball Fountain is made to be kept on the tabletop. Water gently cascades down the ball into a decorative cylindrical pool where it is recycled. The diameter of spherical ball is 21 cm. Cylindrical pool - Outer diameter is 50 cm and inner diameter is 40 cm. Height of solid base is 14 cm. Height of water filled is 7 cm. Observe the figure and answer the following questions : (i) Determine the total height of the fountain. (ii) Find the volume of the ball. (iii) (a) If one-third of the ball is submerged in the water, find the volume of the water filled in the pool. OR (iii) (b) Find the sum of the outer curved surface area of the cylindrical part and surface area of the ball.

View Solution

4.
Assertion (A) : H.C.F. \((36 m^{2}, 18 m) = 18 m\), where \(m\) is a prime number.
Reason (R) : H.C.F. of two numbers is always less than or equal to the smaller number.

Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of the Assertion (A).
Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of the Assertion (A).
Assertion (A) is true, but Reason (R) is false.
Assertion (A) is false, but Reason (R) is true.

View Solution

5.
If \( \alpha \) and \( \beta \) are two zeroes of a polynomial \( f(x) = px^2 - 2x + 3p \) and \( \alpha + \beta = \alpha\beta \), then value of p is :

\( -\frac{2}{3} \)
\( \frac{2}{3} \)
\( \frac{1}{3} \)
\( -\frac{1}{3} \)

View Solution

6.
If for a data, median is 5 and mode is 4, then mean is equal to :

7
11
\(\frac{11}{2}\)
\(\frac{14}{3}\)

View Solution

NCERT Solutions for Class 10 Maths Chapter 7 Exercise 7.2

CBSE X Related Questions

1.
Mean and Median of a frequency distribution are 43 and 40 respectively. The value of mode is

2.
The graph of a quadratic polynomial f(x) passes through (5,0), (0, -1) and (-2, 0). The two factors of the polynomial are

4.
Assertion (A) : H.C.F. \((36 m^{2}, 18 m) = 18 m\), where \(m\) is a prime number.
Reason (R) : H.C.F. of two numbers is always less than or equal to the smaller number.

5.
If \( \alpha \) and \( \beta \) are two zeroes of a polynomial \( f(x) = px^2 - 2x + 3p \) and \( \alpha + \beta = \alpha\beta \), then value of p is :

6.
If for a data, median is 5 and mode is 4, then mean is equal to :

Similar Mathematics Concepts

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NCERT Solutions for Class 10 Maths Chapter 7 Exercise 7.2

CBSE X Related Questions

1.Mean and Median of a frequency distribution are 43 and 40 respectively. The value of mode is

2.The graph of a quadratic polynomial f(x) passes through (5,0), (0, -1) and (-2, 0). The two factors of the polynomial are

4.Assertion (A) : H.C.F. \((36 m^{2}, 18 m) = 18 m\), where \(m\) is a prime number. Reason (R) : H.C.F. of two numbers is always less than or equal to the smaller number.

5.If \( \alpha \) and \( \beta \) are two zeroes of a polynomial \( f(x) = px^2 - 2x + 3p \) and \( \alpha + \beta = \alpha\beta \), then value of p is :

6.If for a data, median is 5 and mode is 4, then mean is equal to :

Similar Mathematics Concepts

Comments

SUBSCRIBE TO OUR NEWS LETTER

1.
Mean and Median of a frequency distribution are 43 and 40 respectively. The value of mode is

2.
The graph of a quadratic polynomial f(x) passes through (5,0), (0, -1) and (-2, 0). The two factors of the polynomial are

4.
Assertion (A) : H.C.F. \((36 m^{2}, 18 m) = 18 m\), where \(m\) is a prime number.
Reason (R) : H.C.F. of two numbers is always less than or equal to the smaller number.

5.
If \( \alpha \) and \( \beta \) are two zeroes of a polynomial \( f(x) = px^2 - 2x + 3p \) and \( \alpha + \beta = \alpha\beta \), then value of p is :

6.
If for a data, median is 5 and mode is 4, then mean is equal to :