NCERT Solutions for Class 10 Maths Chapter 7 Exercise 7.3

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NCERT Solutions for Class 10 Maths Chapter 7 Coordinate Geometry Exercise 7.3 is provided in this article. Class 10 Maths Chapter 7 Exercise 7.3 has questions covering the concept of distance formula and section formula.

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Check out the solutions of Class 10 Maths NCERT solutions chapter 7 Coordinate Geometry Exercise 7.3

Check out other exercise solutions of Class 10 Maths Chapter 7

Class 10 Chapter 7 Topics:

Quadrant	Centroid	Midpoint Formula
Centroid Formula	Centroid of a Triangle	Point of Intersection Formula
Coordinate Geometry MCQs	Cartesian System	Ordinate

CBSE Class 10 Maths Study Guides:

Arithmetic	Mensuration	Calculus
Class 10 Notes	Number System	Geometry
Math Formula	Math Study Notes	Trigonometry
Math MCQs	NCERT Solutions for Class 10 Maths	Difference between in Maths

CBSE X Related Questions

1.
If the zeroes of a polynomial p(x) are $-3$ and 8, then p(x) equals
- $x^2 + 5x - 4$
- $(x + 3) (-x + 8)$
- $a(x^2 + 5x - 24)$
- $x^2 - 24$
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2.
The natural number 1 is :
- a prime number.
- a composite number.
- prime as well as composite.
- neither prime nor composite.
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3.
A kite is flying at a height of $60 \text{ m}$ above the ground level. Ravi, standing at the roof of the house is holding the string straight and observes the angle of elevation of kite as $30^{\circ}$. From the bottom of the same building, the angle of elevation of kite is $45^{\circ}$. Find the length of the string and height of roof from the ground. (Use $\sqrt{3} = 1.73$)
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4.
Prove that :
$\frac{\tan \theta}{1 - \cot \theta} + \frac{\cot \theta}{1 - \tan \theta} = 1 + \tan \theta + \cot \theta$.
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5.
$ABCD$ is a parallelogram such that $AF = 7 \text{ cm}$, $FB = 3 \text{ cm}$ and $EF = 4 \text{ cm}$, length $FD$ equals
- $\frac{21}{4} \text{ cm}$
- $\frac{28}{3} \text{ cm}$
- $\frac{12}{7} \text{ cm}$
- $5.5 \text{ cm}$
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6.
Use graphical method to solve the system of linear equations : $x = -3$ and $5x - 2y = -5$.
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