NCERT Solutions for Class 10 Maths Chapter 8 Introduction to Trigonometry Exercise 8.4

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Jasmine Grover

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NCERT Solutions for Class 10 Maths Chapter 8 Introduction to Trigonometry Exercise 8.4 is provided in this article. Class 10 Maths Chapter 8 Introduction to Trigonometry is included under the unit Trigonometry. Chapter 8 exercise 8.4 is the last exercise of this chapter and includes questions based on trigonometric identities.

Download PDF: NCERT Solutions for Class 10 Maths Exercise 8.4


Check below the pdf of NCERT Solutions for Class 10 Maths Chapter 8 Exercise 8.4

Read Also: NCERT Solutions for Class 10 Maths Chapter 8 Introduction to Trigonometry

Check out NCERT solutions of other exercises of class 10 maths chapter 8 Introduction to Trigonometry:


Class 10 Chapter 8 Introduction to Trigonometry Related Links:

CBSE Class 10 Maths Study Guides:

CBSE X Related Questions

  • 1.
    PQ and PR are two tangents to a circle with centre O and radius 5 cm. AB is another tangent to the circle at C which lies on OP. If OP = 13 cm, then find the length AB and PA.


      • 2.
        The natural number 1 is :

          • a prime number.
          • a composite number.
          • prime as well as composite.
          • neither prime nor composite.

        • 3.
          \(ABCD\) is a parallelogram such that \(AF = 7 \text{ cm}\), \(FB = 3 \text{ cm}\) and \(EF = 4 \text{ cm}\), length \(FD\) equals

            • \(\frac{21}{4} \text{ cm}\)
            • \(\frac{28}{3} \text{ cm}\)
            • \(\frac{12}{7} \text{ cm}\)
            • \(5.5 \text{ cm}\)

          • 4.
            The first term of an AP is $p$ and the common difference is $q$, then its 10th term is :

              • $q - 9p$
              • $p - 9q$
              • $p + 9q$
              • $2p + 9q$

            • 5.
              A bag contains 25 balls. Some of them are yellow and others are green. One ball is drawn at random. If probability of getting a green ball is $3/5$, then find the number of yellow balls.


                • 6.
                  If the zeroes of a polynomial p(x) are $-3$ and 8, then p(x) equals

                    • $x^2 + 5x - 4$
                    • $(x + 3) (-x + 8)$
                    • $a(x^2 + 5x - 24)$
                    • $x^2 - 24$

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