NCERT Solutions for Class 10 Maths Chapter 8 Introduction to Trigonometry Exercise 8.4

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NCERT Solutions for Class 10 Maths Chapter 8 Introduction to Trigonometry Exercise 8.4 is provided in this article. Class 10 Maths Chapter 8 Introduction to Trigonometry is included under the unit Trigonometry. Chapter 8 exercise 8.4 is the last exercise of this chapter and includes questions based on trigonometric identities.

Download PDF: NCERT Solutions for Class 10 Maths Exercise 8.4


Check below the pdf of NCERT Solutions for Class 10 Maths Chapter 8 Exercise 8.4

Read Also: NCERT Solutions for Class 10 Maths Chapter 8 Introduction to Trigonometry

Check out NCERT solutions of other exercises of class 10 maths chapter 8 Introduction to Trigonometry:


Class 10 Chapter 8 Introduction to Trigonometry Related Links:

CBSE Class 10 Maths Study Guides:

CBSE X Related Questions

  • 1.
    Two water taps together can fill a tank in $8\frac{8}{9}$ hours. The tap of larger diameter takes 4 hours less than the smaller one to fill the tank separately. Find the time in which each tap can separately fill the tank.


      • 2.
        The graph of \(y = f(x)\) is given. The number of zeroes of \(f(x)\) is :

          • 0
          • 1
          • 3
          • 2

        • 3.
          If the zeroes of a polynomial p(x) are $-3$ and 8, then p(x) equals

            • $x^2 + 5x - 4$
            • $(x + 3) (-x + 8)$
            • $a(x^2 + 5x - 24)$
            • $x^2 - 24$

          • 4.
            If the quadratic equation \(9x^2 + 8kx + 16 = 0\) has real and equal roots, then the value of k is

              • 3
              • –3
              • –4
              • \(\pm 3\)

            • 5.
              The natural number 1 is :

                • a prime number.
                • a composite number.
                • prime as well as composite.
                • neither prime nor composite.

              • 6.
                Prove that :
                \(\frac{\tan \theta}{1 - \cot \theta} + \frac{\cot \theta}{1 - \tan \theta} = 1 + \tan \theta + \cot \theta\).

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