NCERT Solutions for Class 10 Maths Chapter 8 Introduction to Trigonometry Exercise 8.3

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Jasmine Grover

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NCERT Solutions for Class 10 Maths Chapter 8 Introduction to Trigonometry Exercise 8.3 is provided in this article. Class 10 Maths Chapter 8 Introduction to Trigonometry carries a weightage of 12 Marks along with chapter 9 some applications of trigonometry. Chapter 8 exercise 8.3 includes questions based on trigonometric ratios of complementary angles.

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Read Also: NCERT Solutions for Class 10 Maths Chapter 8 Introduction to Trigonometry

Check out NCERT solutions of other exercises of class 10 maths chapter 8 Introduction to Trigonometry:


Class 10 Chapter 8 Introduction to Trigonometry Related Links:

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CBSE X Related Questions

  • 1.
    The natural number 1 is :

      • a prime number.
      • a composite number.
      • prime as well as composite.
      • neither prime nor composite.

    • 2.
      There are two sections A and B of Grade X. There are 28 students in Section A and 30 students in Section B. What is the minimum number of books you will acquire for the class library so that they can be distributed equally among students of Section A or Section B ?

        • 144
        • 2
        • 420
        • 272

      • 3.
        If \( \alpha, \beta \) are the zeroes of the quadratic polynomial \( px^2 + qx + r \), then find the value of \( \alpha^3\beta + \beta^3\alpha \).


          • 4.
            In a class test, the sum of Anamika's marks obtained in Maths and Science is 30. Had she got 2 marks more in Maths and 3 marks less in Science, the product of the marks would have been 210. Find the marks she got in the two subjects.


              • 5.
                If \(PQ\) and \(PR\) are tangents to the circle with centre \(O\) and radius \(4 \text{ cm}\) such that \(\angle QPR = 90^{\circ}\), then the length \(OP\) is

                  • \(4 \text{ cm}\)
                  • \(4\sqrt{2} \text{ cm}\)
                  • \(8 \text{ cm}\)
                  • \(2\sqrt{2} \text{ cm}\)

                • 6.
                  In the given figure, \(AB \parallel EF\). If \(AB = 24\) cm, \(EF = 36\) cm and \(DA = 7\) cm, then \(AE\) equals

                    • \(2.5\) cm
                    • \(10.5\) cm
                    • \(3.5\) cm
                    • \(\frac{14}{3}\) cm

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