NCERT Solutions for Class 10 Maths Chapter 8 Introduction to Trigonometry Exercise 8.3

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NCERT Solutions for Class 10 Maths Chapter 8 Introduction to Trigonometry Exercise 8.3 is provided in this article. Class 10 Maths Chapter 8 Introduction to Trigonometry carries a weightage of 12 Marks along with chapter 9 some applications of trigonometry. Chapter 8 exercise 8.3 includes questions based on trigonometric ratios of complementary angles.

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Read Also: NCERT Solutions for Class 10 Maths Chapter 8 Introduction to Trigonometry

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CBSE X Related Questions

  • 1.
    The value of k for which sum of the zeroes of the polynomial \(p(x) = 3x^2 - kx + 6\) is 2, is

      • 2
      • \(-6\)
      • \(-2\)
      • 6

    • 2.
      Which of the following graphs represents a polynomial with both zeroes being positive?


      • 3.
        Assertion (A) : H.C.F. \((36 m^{2}, 18 m) = 18 m\), where \(m\) is a prime number.
        Reason (R) : H.C.F. of two numbers is always less than or equal to the smaller number.

          • Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of the Assertion (A).
          • Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of the Assertion (A).
          • Assertion (A) is true, but Reason (R) is false.
          • Assertion (A) is false, but Reason (R) is true.

        • 4.
          If the zeroes of the polynomial \(p(x) = 2x^2 - 7x + 6\) are \(\alpha\) and \(\beta\), then the value of \(\frac{1}{\alpha} + \frac{1}{\beta}\) is

            • \(\frac{7}{2}\)
            • \(\frac{6}{7}\)
            • \(\frac{-7}{6}\)
            • \(\frac{7}{6}\)

          • 5.
            The graph of a quadratic polynomial f(x) passes through (5,0), (0, -1) and (-2, 0). The two factors of the polynomial are

              • \((x + 2), (x - 5)\)
              • \((x + 5), (x - 2)\)
              • \((x + 1), (x - 5)\)
              • \((x - 1), (x + 2)\)

            • 6.
              If for a data, median is 5 and mode is 4, then mean is equal to :

                • 7
                • 11
                • \(\frac{11}{2}\)
                • \(\frac{14}{3}\)

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