NCERT Solutions for Class 10 Maths Chapter 8 Introduction to Trigonometry Exercise 8.2

Jasmine Grover logo

Jasmine Grover

Education Journalist | Study Abroad Lead

NCERT Solutions for Class 10 Maths Chapter 8 Introduction to Trigonometry Exercise 8.2 is provided in this article. Class 10 Maths Chapter 8 Introduction to Trigonometry is included under Unit 5 Trigonometry of class 10 maths syllabus. Chapter 8 exercise 8.2 covers important questions based on trigonometric ratios of some specific angles.

Download PDF: NCERT Solutions for Class 10 Maths Chapter 8 Introduction to Trigonometry Exercise 8.2


Check below the pdf of NCERT Solutions for Class 10 Maths Chapter 8 Exercise 8.2

Read Also: NCERT Solutions for Class 10 Maths Chapter 8 Introduction to Trigonometry

Check out NCERT solutions of other exercises of class 10 maths chapter 8 Introduction to Trigonometry:


Class 10 Chapter 8 Introduction to Trigonometry Related Links:

CBSE Class 10 Maths Study Guides:

CBSE X Related Questions

  • 1.
    In the given figure, \(AB \parallel DE\) and \(AC \parallel DF\). Show that \(\triangle ABC \sim \triangle DEF\). If \(BC = 10\) cm, \(EB = CF = 5\) cm and \(AB = 7\) cm, then find the length DE.


      • 2.
        A circle centered at (2, 1) passes through the points A(5, 6) and B(-3, K). Find the value(s) of K. Hence find length of chord AB.


          • 3.
            The value of \(p\) for which roots of the quadratic equation \(x^{2} - px + 6 = 0\) are rational, is

              • \(1\)
              • \(-5\)
              • \(25\)
              • \(\sqrt{5}\)

            • 4.
              A bag contains 25 balls. Some of them are yellow and others are green. One ball is drawn at random. If probability of getting a green ball is \(3/5\), then find the number of yellow balls.


                • 5.
                  D is the mid-point of side BC of \(\triangle ABC\). CE and BF intersect at O, a point on AD. AD is produced to G such that \(OD = DG\). Prove that OBGC is a parallelogram.


                    • 6.
                      If \(PQ\) and \(PR\) are tangents to the circle with centre \(O\) and radius \(4 \text{ cm}\) such that \(\angle QPR = 90^{\circ}\), then the length \(OP\) is

                        • \(4 \text{ cm}\)
                        • \(4\sqrt{2} \text{ cm}\)
                        • \(8 \text{ cm}\)
                        • \(2\sqrt{2} \text{ cm}\)

                      Comments


                      No Comments To Show