NCERT Solutions for Class 10 Maths Chapter 8 Introduction to Trigonometry Exercise 8.2

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NCERT Solutions for Class 10 Maths Chapter 8 Introduction to Trigonometry Exercise 8.2 is provided in this article. Class 10 Maths Chapter 8 Introduction to Trigonometry is included under Unit 5 Trigonometry of class 10 maths syllabus. Chapter 8 exercise 8.2 covers important questions based on trigonometric ratios of some specific angles.

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Check below the pdf of NCERT Solutions for Class 10 Maths Chapter 8 Exercise 8.2

Read Also: NCERT Solutions for Class 10 Maths Chapter 8 Introduction to Trigonometry

Check out NCERT solutions of other exercises of class 10 maths chapter 8 Introduction to Trigonometry:

Class 10 Chapter 8 Introduction to Trigonometry Related Links:

Trigonometry Table	Trigonometric Functions	Cosec Cot Formula
Some Applications of Trigonometry	Introduction to Trigonometry Important Formula	Heights and Distances
Angle of Depression	Introduction to Trigonometry Revision Notes	Sec 90°

CBSE Class 10 Maths Study Guides:

Math Formula	Math Study Notes	Trigonometry
Math MCQs	NCERT Solutions for Class 10 Maths	Difference between in Maths
Arithmetic	Mensuration	Calculus
Class 10 Notes	Number System	Geometry

CBSE X Related Questions

1.
The first term of an AP is $p$ and the common difference is $q$, then its 10th term is :
- $q - 9p$
- $p - 9q$
- $p + 9q$
- $2p + 9q$
View Solution
2.
The HCF of 960 and 432 is :
- 48
- 54
- 72
- 36
View Solution
3.
The graph of \(y = f(x)\) is given. The number of zeroes of \(f(x)\) is :
- 0
- 1
- 3
- 2
View Solution
4.
Prove that :
\(\frac{\tan \theta}{1 - \cot \theta} + \frac{\cot \theta}{1 - \tan \theta} = 1 + \tan \theta + \cot \theta\).
View Solution
5.
If the pair of linear equations : \( a_1x + b_1y + c_1 = 0 \) and \( a_2x + b_2y + c_2 = 0 \) is consistent and dependent, then
- \( \frac{a_1}{a_2} \neq \frac{b_1}{b_2} \)
- \( \frac{a_1}{a_2} = \frac{b_1}{b_2} = \frac{c_1}{c_2} \)
- \( \frac{a_1}{a_2} = \frac{b_1}{b_2} \neq \frac{c_1}{c_2} \)
- \( \frac{a_1}{a_2} = \frac{b_1}{b_2} = \frac{c_1}{c_2} \)
View Solution
6.
If the zeroes of a polynomial p(x) are $-3$ and 8, then p(x) equals
- $x^2 + 5x - 4$
- $(x + 3) (-x + 8)$
- $a(x^2 + 5x - 24)$
- $x^2 - 24$
View Solution

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