NCERT Solutions for Class 10 Maths Chapter 8 Introduction to Trigonometry Exercise 8.2

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NCERT Solutions for Class 10 Maths Chapter 8 Introduction to Trigonometry Exercise 8.2 is provided in this article. Class 10 Maths Chapter 8 Introduction to Trigonometry is included under Unit 5 Trigonometry of class 10 maths syllabus. Chapter 8 exercise 8.2 covers important questions based on trigonometric ratios of some specific angles.

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Check out NCERT solutions of other exercises of class 10 maths chapter 8 Introduction to Trigonometry:

Class 10 Chapter 8 Introduction to Trigonometry Related Links:

Trigonometry Table	Trigonometric Functions	Cosec Cot Formula
Some Applications of Trigonometry	Introduction to Trigonometry Important Formula	Heights and Distances
Angle of Depression	Introduction to Trigonometry Revision Notes	Sec 90°

CBSE Class 10 Maths Study Guides:

Math Formula	Math Study Notes	Trigonometry
Math MCQs	NCERT Solutions for Class 10 Maths	Difference between in Maths
Arithmetic	Mensuration	Calculus
Class 10 Notes	Number System	Geometry

CBSE X Related Questions

1.
Use graphical method to solve the system of linear equations : $x = -3$ and $5x - 2y = -5$.
View Solution
2.
In the given figure, point D divides the side BC of $\Delta ABC$ in the ratio $1 : 2$. Find length AD.
View Solution
3.
If the zeroes of a polynomial p(x) are $-3$ and 8, then p(x) equals
- $x^2 + 5x - 4$
- $(x + 3) (-x + 8)$
- $a(x^2 + 5x - 24)$
- $x^2 - 24$
View Solution
4.
An arc of length $2.2\text{ cm}$ subtends an angle $\theta$ at the centre of the circle with radius $2.8\text{ cm}$. The value of $\theta$ is
- $50^\circ$
- $60^\circ$
- $45^\circ$
- $30^\circ$
View Solution
5.
The value of p for which roots of the quadratic equation $x^2 - px + 6 = 0$ are rational, is
- $1$
- $-5$
- $25$
- $\sqrt{5}$
View Solution
6.
Prove that $14 - 2\sqrt{3}$ is an irrational number, given that $\sqrt{3}$ is irrational.
View Solution

View All

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NCERT Solutions for Class 10 Maths Chapter 8 Introduction to Trigonometry Exercise 8.2

CBSE X Related Questions

1.
Use graphical method to solve the system of linear equations : $x = -3$ and $5x - 2y = -5$.

2.
In the given figure, point D divides the side BC of $\Delta ABC$ in the ratio $1 : 2$. Find length AD.

3.
If the zeroes of a polynomial p(x) are $-3$ and 8, then p(x) equals

4.
An arc of length $2.2\text{ cm}$ subtends an angle $\theta$ at the centre of the circle with radius $2.8\text{ cm}$. The value of $\theta$ is

5.
The value of p for which roots of the quadratic equation $x^2 - px + 6 = 0$ are rational, is

6.
Prove that $14 - 2\sqrt{3}$ is an irrational number, given that $\sqrt{3}$ is irrational.

Similar Mathematics Concepts

Comments

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NCERT Solutions for Class 10 Maths Chapter 8 Introduction to Trigonometry Exercise 8.2

CBSE X Related Questions

1.Use graphical method to solve the system of linear equations : $x = -3$ and $5x - 2y = -5$.

2.In the given figure, point D divides the side BC of $\Delta ABC$ in the ratio $1 : 2$. Find length AD.

3.If the zeroes of a polynomial p(x) are $-3$ and 8, then p(x) equals

4.An arc of length $2.2\text{ cm}$ subtends an angle $\theta$ at the centre of the circle with radius $2.8\text{ cm}$. The value of $\theta$ is

5.The value of p for which roots of the quadratic equation $x^2 - px + 6 = 0$ are rational, is

6.Prove that $14 - 2\sqrt{3}$ is an irrational number, given that $\sqrt{3}$ is irrational.

Similar Mathematics Concepts

Comments

SUBSCRIBE TO OUR NEWS LETTER

1.
Use graphical method to solve the system of linear equations : $x = -3$ and $5x - 2y = -5$.

2.
In the given figure, point D divides the side BC of $\Delta ABC$ in the ratio $1 : 2$. Find length AD.

3.
If the zeroes of a polynomial p(x) are $-3$ and 8, then p(x) equals

4.
An arc of length $2.2\text{ cm}$ subtends an angle $\theta$ at the centre of the circle with radius $2.8\text{ cm}$. The value of $\theta$ is

5.
The value of p for which roots of the quadratic equation $x^2 - px + 6 = 0$ are rational, is

6.
Prove that $14 - 2\sqrt{3}$ is an irrational number, given that $\sqrt{3}$ is irrational.