NCERT Solutions For Class 11 Mathematics Chapter 3: Trigonometric Functions

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NCERT Solutions for class 11 mathematics Chapter 3 Trigonometric Functions are provided in the article below. Trigonometric Functions are the functions of angles of a triangle that explains the relationships between them.

NCERT Solutions for Class 11 Mathematics Chapter 3 cover important concepts including Basic Trigonometric Functions, Trigonometric Identities, and Formulas.

Download: NCERT Solutions for Class 11 Mathematics Chapter 3 pdf

Class 11 Maths NCERT Solutions Chapter 3 Trigonometric Functions

Class 11 Maths NCERT Solutions Chapter 3 Trigonometric Functions are provided below:

Also check: Trigonometric Functions

Important Topics: Class 11 Maths NCERT Solutions Chapter 3 Trigonometric Functions

Important Topics Class 11 Maths NCERT Solutions Chapter 3 Trigonometric Functions are elaborated below:

Degree measure

Important angles of trigonometry are 0°, 30°, 45°, 60°, 90°. These are standard angles of trigonometric ratios like sin, cos, tan, sec, cosec, and cot. These angles have different values with different trigonometric functions.

Radian measure

Angle subtended at the centre by an arc of length 1 unit in a unit circle (circle of radius 1 unit) is said to have a measure of 1 radian.

The symbol used to denote the radian measure is “rad” or ^“c”

Relation between radian and real numbers

The relation between radian and real numbers can be established using following steps:

Step 1: Consider the unit circle with centre A.

Step 2: Locate a point, say B on the circle.

Step 3: Now, take the line segment AB as the initial side of an angle.

Step 4: From the initial side AB, the length of an arc of the circle will give the radian measure of the angle, which the arc will subtend at the centre of the circle.

Step 5: Draw the line OPQ, which is tangent to the circle with the point of contact B.

Step 6: Consider this line as a number line with real numbers such that the point O represents the real number zero (0), OB represents the positive real numbers, and BP represents negative real numbers.

Sign of trigonometric functions

Following are the signs of trigonometric functions:

Trigonometric Functions	Quadrant I	Quadrant II	Quadrant III	Quadrant IV
sin θ	+ve	+ve	-ve	-ve
cos θ	+ve	-ve	-ve	+ve
tan θ	+ve	-ve	+ve	-ve
cosec θ	+ve	+ve	-ve	-ve
sec θ	+ve	-ve	-ve	+ve
cot θ	+ve	-ve	+ve	-ve

NCERT Solutions For Class 11 Maths Chapter 1 Exercises:

The detailed solutions for all the NCERT Solutions for Chapter 1 Sets under different exercises are as follows:

Also check:

Chapter Related Topics
Relation between degree and radian	Domain and range of trigonometric functions	Degrees to Radians
Cosine Rule	Sin 180 Degrees	Law of Sines
Cosine Formula	Tan2x Formula	Sin2x Formula
Cos2x Formula	Sin squared x formula	2cosa cosb formula
Tangent 3 theta formula	Cos Square Theta formula	Cot tan formula
Cotangent formula	Degree and radian measure formula	Side angle side formula

Also check:

Math Study Guides
Maths Important Formulas	Maths MCQs	Comparison Articles in Maths
Difference Between Topics in Maths	Math Study Material	Arithmetic

CBSE CLASS XII Related Questions

1.
Check whether \[ f:\mathbb{R}-\{3\}\rightarrow\mathbb{R} \] defined as \[ f(x)=\frac{x-2}{x-3} \] is onto or not.
View Solution
2.
Assertion (A) : In an experiment of throwing an unbiased die, the probability of getting a prime number given that number appearing on the die being odd is \( \frac{2}{3} \).
Reason (R) : For any two events \( A \) and \( B \), \( P(A|B) = \frac{P(A \cup B)}{P(B)} \).
- Both Assertion (A) and Reason (R) are true and the Reason (R) is the correct explanation of the Assertion (A).
- Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of the Assertion (A).
- Assertion (A) is true and Reason (R) is false.
- Assertion (A) is false and Reason (R) is true.
View Solution
3.
In a school, the probability of holding a debate competition is \( \frac{1}{3} \) and that of a quiz competition is \( \frac{2}{3} \). In the two participating teams, A has 4 girls and 6 boys and B has 7 girls and 3 boys. If a debate competition is held, the students are selected from team A and for the quiz competition they are selected from team B. If only two students are to be chosen from the teams, then find the probability that one will be a girl and the other a boy.
View Solution
4.
For two vectors \(\vec{a}\) and \(\vec{b}\):

Assertion (A): \[ |\vec{a}\times\vec{b}|^2+(\vec{a}\cdot\vec{b})^2 = |\vec{a}|^2|\vec{b}|^2 \] Reason (R): \[ |\vec{a}\times\vec{b}| = (\vec{a}\cdot\vec{b})\tan\theta, \quad \theta\neq\frac{\pi}{2}. \]
- Both Assertion (A) and Reason (R) are true and the Reason (R) is the correct explanation of the Assertion (A).
- Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of the Assertion (A).
- Assertion (A) is true, but Reason (R) is false.
- Assertion (A) is false, but Reason (R) is true.
View Solution
5.
If \[ \frac{d}{dx}(F(x))=\frac{1}{e^x+1}, \] then find \(F(x)\), given that \[ F(0)=\log\left(\frac{1}{2}\right). \]
View Solution
6.
For \[ f(x)=x+\frac{1}{x}, \quad x\neq 0. \]
- local maximum value is 2
- local minimum value is \( -2 \)
- local maximum value is \( -2 \)
- local minimum value \( < \) local maximum value
View Solution

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NCERT Solutions For Class 11 Mathematics Chapter 3: Trigonometric Functions

Class 11 Maths NCERT Solutions Chapter 3 Trigonometric Functions

Important Topics: Class 11 Maths NCERT Solutions Chapter 3 Trigonometric Functions

NCERT Solutions For Class 11 Maths Chapter 1 Exercises:

CBSE CLASS XII Related Questions

1.
Check whether \[ f:\mathbb{R}-\{3\}\rightarrow\mathbb{R} \] defined as \[ f(x)=\frac{x-2}{x-3} \] is onto or not.

2.
Assertion (A) : In an experiment of throwing an unbiased die, the probability of getting a prime number given that number appearing on the die being odd is \( \frac{2}{3} \).
Reason (R) : For any two events \( A \) and \( B \), \( P(A|B) = \frac{P(A \cup B)}{P(B)} \).

4.
For two vectors \(\vec{a}\) and \(\vec{b}\):

Assertion (A): \[ |\vec{a}\times\vec{b}|^2+(\vec{a}\cdot\vec{b})^2 = |\vec{a}|^2|\vec{b}|^2 \] Reason (R): \[ |\vec{a}\times\vec{b}| = (\vec{a}\cdot\vec{b})\tan\theta, \quad \theta\neq\frac{\pi}{2}. \]

5.
If \[ \frac{d}{dx}(F(x))=\frac{1}{e^x+1}, \] then find \(F(x)\), given that \[ F(0)=\log\left(\frac{1}{2}\right). \]

6.
For \[ f(x)=x+\frac{1}{x}, \quad x\neq 0. \]

Similar Mathematics Concepts

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NCERT Solutions For Class 11 Mathematics Chapter 3: Trigonometric Functions

Class 11 Maths NCERT Solutions Chapter 3 Trigonometric Functions

Important Topics: Class 11 Maths NCERT Solutions Chapter 3 Trigonometric Functions

NCERT Solutions For Class 11 Maths Chapter 1 Exercises:

CBSE CLASS XII Related Questions

1.Check whether \[ f:\mathbb{R}-\{3\}\rightarrow\mathbb{R} \] defined as \[ f(x)=\frac{x-2}{x-3} \] is onto or not.

2.Assertion (A) : In an experiment of throwing an unbiased die, the probability of getting a prime number given that number appearing on the die being odd is \( \frac{2}{3} \). Reason (R) : For any two events \( A \) and \( B \), \( P(A|B) = \frac{P(A \cup B)}{P(B)} \).

4.For two vectors \(\vec{a}\) and \(\vec{b}\): Assertion (A): \[ |\vec{a}\times\vec{b}|^2+(\vec{a}\cdot\vec{b})^2 = |\vec{a}|^2|\vec{b}|^2 \] Reason (R): \[ |\vec{a}\times\vec{b}| = (\vec{a}\cdot\vec{b})\tan\theta, \quad \theta\neq\frac{\pi}{2}. \]

5. If \[ \frac{d}{dx}(F(x))=\frac{1}{e^x+1}, \] then find \(F(x)\), given that \[ F(0)=\log\left(\frac{1}{2}\right). \]

6. For \[ f(x)=x+\frac{1}{x}, \quad x\neq 0. \]

Similar Mathematics Concepts

Comments

SUBSCRIBE TO OUR NEWS LETTER

1.
Check whether \[ f:\mathbb{R}-\{3\}\rightarrow\mathbb{R} \] defined as \[ f(x)=\frac{x-2}{x-3} \] is onto or not.

2.
Assertion (A) : In an experiment of throwing an unbiased die, the probability of getting a prime number given that number appearing on the die being odd is \( \frac{2}{3} \).
Reason (R) : For any two events \( A \) and \( B \), \( P(A|B) = \frac{P(A \cup B)}{P(B)} \).

4.
For two vectors \(\vec{a}\) and \(\vec{b}\):

Assertion (A): \[ |\vec{a}\times\vec{b}|^2+(\vec{a}\cdot\vec{b})^2 = |\vec{a}|^2|\vec{b}|^2 \] Reason (R): \[ |\vec{a}\times\vec{b}| = (\vec{a}\cdot\vec{b})\tan\theta, \quad \theta\neq\frac{\pi}{2}. \]

5.
If \[ \frac{d}{dx}(F(x))=\frac{1}{e^x+1}, \] then find \(F(x)\), given that \[ F(0)=\log\left(\frac{1}{2}\right). \]

6.
For \[ f(x)=x+\frac{1}{x}, \quad x\neq 0. \]