Cos Square Theta Formula: Trigonometric Ratio & Types

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Cos Square Theta Formula is, Cos 2 theta= 1 – sin2 theta. The function of an angle, that is the angles and sides relationships are given by trigonometric functions. The equations which relate to the variety of trigonometric functions for any variable are referred to as trigonometric identities

As per the trigonometric identities, the cos square theta formula is represented by:

Cos2θ + Sin2θ = 1
→ Cos 2 theta= 1 – Sin2 theta

The sine or sin, the cosine or cos, the tangent or tan, the cotangent or cot, the cosecant or cosec, and the secant or the sec are the six trigonometric signs. Trigonometry is a branch of mathematics in geometry that was discovered to deal with the ideas and problems of right-angled triangles. And hence, these trigonometric signs are used for the calculation of sides and angles in general.

Also read: Isosceles Triangle Theorems

Key Terms: Sin, Sin Squared X, Triangle, Pythagoras Theorem, Cosine, Secant, Cosecant, Tangent, Cotangent, Perpendicular, Hypotenuse, Integrals, Trigonometric Ratio, Trigonometry


What are Trigonometric Ratios?

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Trigonometric ratios are the value of the trigonometric functions that are on the basis of the value of the ratio of sides of a right-angled triangle or an orthogonal triangle. The three sides of a right-angled triangle are as follows:

  • The hypotenuse (longest edge)
  • The perpendicular (the opposite side of the hypotenuse)
  • The base (the adjacent side to the angle to be considered)

The trigonometric ratios are defined as,

“The ratios of sides of a right-angled triangle concerning any of its acute angles are known as the trigonometric ratios of that particular angle.”

Trigonometric Functions Detailed Video Explanation

Types of Trigonometric Ratios

There are six different trigonometric ratios, which are as follows:

  • Sine or the sin
  • Cosine or the cos
  • Tangent or the tan
  • Cosecant or the cosec
  • Secant or the sec
  • Cotangent or the cot.

Let there be a right-angled triangle given in the figure whose rations are taken for an angle C:

The formulas will be:

  • Sine = perpendicular/hypotenuse = AB/AC
  • Cosine = Base/hypotenuse = BC/AC
  • Tangent = perpendicular/base = AB/BC
  • Cosecant = 1/sin = hypotenuse/perpendicular = AC/AB
  • Secant = 1/cos = hypotenuse/base = AC/BC
  • Cotangent = 1/tan = base/perpendicular = BC/AB

Also read: Determinant Formula


Cos Square Theta

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Cos square theta is a double-angle formula that is used in trigonometry for solving different complex problems. It has got its use in calculus as well. Other than the primary trigonometric signs such as sin, cos, and tan, these double-angle formulas are also important in trigonometry.

Examples Based on Cos Square Theta

Example: Determine the value of cosθ, with the value of sinθ given as 3/5.

Ans: The value of sinθ is given as = 3/5

Now, by using the cos square formula, we can obtain:

⇒ cos2θ + sin2θ = 1

⇒ cos2θ = 1 – sin2θ = 1 – (3/5)2 = 1 – 9/25

⇒ cos2θ = 16/25

⇒ cosθ = √(16/25) = ± 4/5

Thus, the value of cosθ is ± 4/5.

Example: Determine the value of cos2θ, with the value of cosθ given as = 1/2.

Ans: By applying a generalized formula,

⇒ cos2θ = 2cos2θ – 1

The value of cos2θ, after substituting the value is, cosθ = 1/2

Hence,

⇒ cos2θ = 2 × (1/2)2 – 1 = 2/4 – 1 = 1/2 – 1 = – 1/2

Accordingly, cos2θ = – 1/2.

Also Read:


Cos Square Theta Formula

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The basic formula to obtain the value of cos square theta is,

cos2 x + sinx = 1

Where, the basic formula for

sin = perpendicular/hypotenuse and

cos = base/hypotenuse.

By shifting the sin square x in the above formula to the right-hand side we get the formula for cos square x.

So, the formula will be,

Cos2 x = 1 - sin2 x

Also, some other formulas derived from the above expression for cos square theta are:

  • Cos 2x = cos2 x - sin2 x
  • Cos 2x = 2cos2 x – 1

Things to Remember

  • Trigonometric ratios are the value of the trigonometric functions that are based on the ratio of the primary trigonometric signs.
  • The right-angled triangle has three edges, the hypotenuse, the perpendicular, and the base.
  • The six trigonometric ratios are sine, cosine, tangent, cotangent, cosecant, and secant.
  • The ratios are expressed as: Sin x = perpendicular/hypotenuse; Cos x = base/hypotenuse; Tan x = perpendicular/base; Cosec x = 1 / sin; Sec x = 1 / cos; Cot X = 1 / tan.
  • The formula for cos square theta is, Cos2x = 1 – sin2.
  • Other formulas of cos square theta are: Cos square x = cos 2x + 1; Cos square x = cos 2x + sin square x.

Also read:


Previous Year Questions


Sample Questions

Ques: What do you mean by trigonometric ratios? (2 marks)

Ans: Trigonometric ratios are the value of the trigonometric functions that are based on the ratio of the primary trigonometric signs sin, cos, and tan of a right-angled triangle. They are used widely in mathematics for solving trigonometry and calculus problems.

Ques: What are the different types of trigonometric ratios? (2 marks)

Ans: There are six trigonometric ratios which are,

  • Sine or sin
  • Cosine or cos
  • Tangent or tan
  • Cosecant or cosec
  • Secant or sec
  • Cotangent or cot

Ques: What are the values of the different trigonometric ratios? (2 marks)

Ans: The trigonometry ratios are expressed as follows:

  • Sine = perpendicular/hypotenuse
  • Cosine = base/hypotenuse
  • Tangent = perpendicular/base
  • Cosecant = 1/sine = hypotenuse/perpendicular
  • Secant = 1/cosine = hypotenuse/base
  • Cotangent = 1/tangent = base/perpendicular

Ques: What is the formula for cos square theta? (3 marks)

Ans: The formula for cos square theta is derived from the following equation:

Cos2 x + sin2 x = 1

So we will get the formula for cos square x by shifting sin square x to the right hand side.

Cos2 x = 1 - sin2 x

Other formulas for cos square x are:

Cos2 x = cos 2x + 1

Cos2 x = cos 2x + sin2 x

Ques: Let there be an angle with sin x value as 2/3. Calculate the value of cos x. (3 marks)

Ans: As we know,

Sin square x + cos square x = 1

(2/3)2 + cos2 x = 1

Cos2 x = 1- (2/3)2

Cos2 x = 1- 4/9

= (9-4)/9

= 5/9

Cos x = 5/3.

Ques: The value of cos x is ¾ . Calculate the value of sin x. (3 marks)

Ans: As we know,

Cos square x + sin square x = 1

Sin2 x = 1- cos2 x

= 1- (3/4)2

= 1- 9/16

= (16-9)/16

= 7/16

Sin x = 7/4 .

Ques: Derive the value of cos2x, if cos square x is 2/6. (3 marks)

Ans: As we know,

Cos 2x = 2 cos22 x – 1

Cos 2x = 2 (2/6)2 – 1

 Cos 2x = 2 (4/36) – 1

 Cos 2x = (2/9) – 1

 Cos 2x = (2-9)/1

Cos 2x = -7.

Ques: Determine the value of cosθ, with the value given as, cosθ – sinθ = 1. (5 marks)

Ans: The given value is, cosθ – sinθ = 1.

or, cosθ = 1 + sinθ —- (i)

By applying the cos square formula, we get

cos2θ + sin2θ = 1

cos2θ = 1 – sin2θ = (1 + sinθ)(1 – sinθ)

cos2θ = cosθ (1 – sinθ)

cosθ (cosθ – 1 + sinθ) = 0

So, can obtain the two cases,

cosθ = 0

else, cosθ – 1 + sinθ = 0

or, cosθ = 1 – sinθ     —- (ii)

From eq.(i) and eq.(ii), we get

1 – sinθ = 1 + sinθ

2sinθ = 0

sinθ = -

From eq.(i), we get cosθ = 1 + sinθ = 1 + 0 = 1

Thus, cosθ = 1

So, we get two possibilities. The value of cosθ is or 1.

Ques: If cosθ = 3/5, then what is the value of sin2θ – cos2θ? (3 marks)

Ans: As per the question, the value of cosθ = 3/5

Now, using the cos square formula, we can express:

⇒ sin2θ – cos2θ = (1 – cos2θ) – cos2θ = 1 – 2cos2θ

After we put the value of cosθ = 3/5, we can obtain:

⇒ sin2θ – cos2θ = 1 – 2cos2θ

= 1 – 2 × (3/5)2 

= 1 – 2 × 9/25

= 1 – 18/25

7/25

Ques: What is the proof of cos2θ + sin2θ = 1? (3 marks)

Ans: The trigonometric functions for any right-angled triangle can be expressed as:

  • cosθ = base/hypotenuse
  • sinθ = altitude/hypotenuse

So, we can represent the same as:

→ cos2θ + sin2θ = base2/hypotenuse2 + altitude2/hypotenuse2

hence,

cos2θ + sin2θ = (base2 + altitude2)/hypotenuse2

By using the Pythagoras theorem for right-angled triangle, we can obtain:

base2 + altitude2 = hypotenuse2

Thus, we acquire:

cos2θ + sin2θ = 1

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CBSE CLASS XII Related Questions

  • 1.
    Find:

    If \[ (3\hat{i}-2\hat{j}+5\hat{k})\times(4\hat{i}+p\hat{j}+q\hat{k})=\vec{0} \] then find the values of \(p\) and \(q\).

      • \(p = -\frac{2}{3}, \, q = \frac{5}{3}\)
      • \(p = -\frac{8}{3}, \, q = \frac{20}{3}\)
      • \(p = \frac{20}{3}, \, q = -\frac{8}{3}\)
      • \(p = 0, \, q = 0\)

    • 2.

      An NGO organises a charity event in which they decide to distribute woollen caps to protect children from winter. The caps to be distributed are in three separate boxes, Box I has 30 red caps, Box II has 20 red and 10 green caps, and Box III has 30 green caps. The probability that a Box i is selected and a cap picked out is i/6, where i = 1, 2, 3.  
      Based on the above information, answer the following questions :


        • 3.
          Find:

          The principal value of \[ \sec^{-1}(\sqrt{2})+2\csc^{-1}(-2) \] is:

            • \(-\frac{\pi}{2}\)
            • \(-\frac{\pi}{4}\)
            • \(\frac{\pi}{4}\)
            • \(\frac{\pi}{2}\)

          • 4.
            Find the vector and cartesian equations of the line passing through the point of intersection of the lines \( \vec{r} = (\hat{i} + \hat{j} - \hat{k}) + \lambda(3\hat{i} - \hat{j}) \) and \( \vec{r} = (4\hat{i} - \hat{k}) + \mu(2\hat{i} + 3\hat{k}) \) and parallel to the line \( \frac{x - 1}{-2} = \frac{7 - y}{-3} = z \).


              • 5.
                Find a point on the line \( \frac{x - 2}{3} = \frac{1 - y}{2} = \frac{z - 3}{2} \) at a distance of \( \sqrt{2} \) units from the point \( (1, 2, 3) \).


                  • 6.

                    Find:
                    Let \(A=[a_{ij}]\) be a \(2\times2\) matrix whose elements are given by \[ a_{ij}=\frac{(2i-j)^2}{3} \] Find the transpose matrix \(A'\).

                      • \(\begin{bmatrix} \frac{1}{3} & 3 \\ 0 & \frac{4}{3} \end{bmatrix}\)
                      • \(\begin{bmatrix} \frac{1}{3} & 0 \\ 3 & \frac{4}{3} \end{bmatrix}\)
                      • \(\begin{bmatrix} \frac{4}{3} & 3 \\ 1 & 0 \end{bmatrix}\)
                      • \(\begin{bmatrix} \frac{4}{3} & 0 1 & \frac{3}{3} \end{bmatrix}\)
                    CBSE CLASS XII Previous Year Papers

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