NCERT Solutions for Class 11 Maths Chapter 3 Exercise 3.4

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Class 11 Maths NCERT Solutions Chapter 3 Trigonometric Functions Exercise 3.4 based on Trigonometric Equations.

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Also check other Exercise Solutions of Class 11 Maths Chapter 3 Trigonometric Functions

Also check:

Class 11 Chapter 3 Important Topics
Side angle side formula	Domain and range of trigonometric functions	Degrees to Radians
Cosine Rule	Sin 180 Degrees	Law of Sines
Cosine Formula	Tan2x Formula	Sin2x Formula
Cos2x Formula	Sin squared x formula	2cosa cosb formula
Tangent 3 theta formula	Cos Square Theta formula	Cot tan formula
Cotangent formula	Degree and radian measure formula	Relation between degree and radian

Also check:

Class 11 Mathematics Important Guides
Maths Important Formulas	Maths MCQs	Comparison Articles in Maths
Difference Between Topics in Maths	Math Study Material	Arithmetic

CBSE CLASS XII Related Questions

1.
Evaluate :
\[ I = \int_{-\pi}^{\pi} \frac{2x\,(1+\sin x)}{1+\cos^2 x}\,dx \]
View Solution
2.
The value of \( \left[ \tan^{-1}(-1) + \cos^{-1}\left(-\frac{1}{2}\right) + \sin^{-1}\left(\frac{1}{2}\right) \right] \) is :
- \( \frac{7\pi}{12} \)
- \( \frac{5\pi}{12} \)
- \( -\frac{5\pi}{12} \)
- \( \frac{\pi}{3} \)
View Solution
3.
If \(y = \sqrt{\log \left\{ \sin \left( \dfrac{x^2}{3} + 1 \right) \right\}}\), then show that
\[ \frac{dy}{dx} = \frac{x \cot \left( \dfrac{x^2}{3} + 1 \right)}{3y}. \]
View Solution
4.
For the given Linear Programming Problem, shade the feasible region on the graph and write the coordinates of the corner points.
Minimize \(Z = 5x + 7y\)
subject to constraints
\[ 2x + y \geq 8 \]
\[ x + 2y \geq 10 \]
\[ x,\ y \geq 0. \]
View Solution
5.
\( \int e^{x}\left( \frac{2+\sin 2x}{1+\cos 2x} \right) dx \) is equal to :
- \( \log \cos 2x + C \)
- \( \sec^{2} 2x + C \)
- \( e^{x}\tan x + C \)
- \( e^{x}\cot x + C \)
View Solution
6.
For events A and B, if \(P(B)=\frac{3}{5}\), \(P(A/B)=\frac{1}{2}\) and \(P(A\cup B)=\frac{4}{5}\), then \(P(A)\) is :
- \(\frac{1}{2}\)
- \(\frac{3}{5}\)
- \(\frac{1}{5}\)
- \(\frac{3}{10}\)
View Solution

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