NCERT Solutions for Class 11 Maths Chapter 3 Exercise 3.1

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Class 11 Maths NCERT Solutions Chapter 3 Trigonometric Functions Exercise 3.1 based on the following concepts:

Degree measure
Radian measure
Relation between radian and real numbers
Relation between degree and radian

Download PDF NCERT Solutions for Class 11 Maths Chapter 3 Trigonometric Functions Exercise 3.1

Check out the solutions of Class 11 Maths NCERT solutions Chapter Chapter 3 Trigonometric Functions Exercise 3.1

Read More: NCERT Solutions For Class 11 Maths Chapter 3 Trigonometric Functions

Also check other Exercise Solutions of Class 11 Maths Chapter 3 Trigonometric Functions

Also check:

Class 11 Chapter 3 Important Topics
Side angle side formula	Domain and range of trigonometric functions	Degrees to Radians
Cosine Rule	Sin 180 Degrees	Law of Sines
Cosine Formula	Tan2x Formula	Sin2x Formula
Cos2x Formula	Sin squared x formula	2cosa cosb formula
Tangent 3 theta formula	Cos Square Theta formula	Cot tan formula
Cotangent formula	Degree and radian measure formula	Relation between degree and radian

Also check:

Class 11 Mathematics Important Guides
Maths Important Formulas	Maths MCQs	Comparison Articles in Maths
Difference Between Topics in Maths	Math Study Material	Arithmetic

CBSE CLASS XII Related Questions

1.
\( \int e^{x}\left( \frac{2+\sin 2x}{1+\cos 2x} \right) dx \) is equal to :
- \( \log \cos 2x + C \)
- \( \sec^{2} 2x + C \)
- \( e^{x}\tan x + C \)
- \( e^{x}\cot x + C \)
View Solution
2.
Differential of \( \log \sin x \) with respect to \( \sqrt{\cos x} \) is :
- \( -2\sqrt{\cos x}\cdot\cot x\cdot\operatorname{cosec} x \)
- \( \sqrt{\cos x}\cdot\cot x\cdot\operatorname{cosec} x \)
- \( \frac{2\sqrt{\cos x}}{\sin x} \)
- \( \frac{1}{\sin x\sqrt{\cos x}} \)
View Solution
3.
Evaluate :
\[ I = \int_{-\pi}^{\pi} \frac{2x\,(1+\sin x)}{1+\cos^2 x}\,dx \]
View Solution
4.
Solve the differential equation \( (x+y)\,dy + (x-y)\,dx = 0 \), given that \( y(1) = 1 \).
View Solution
5.
If \(y = \sqrt{\log \left\{ \sin \left( \dfrac{x^2}{3} + 1 \right) \right\}}\), then show that
\[ \frac{dy}{dx} = \frac{x \cot \left( \dfrac{x^2}{3} + 1 \right)}{3y}. \]
View Solution
6.
For events A and B, if \(P(B)=\frac{3}{5}\), \(P(A/B)=\frac{1}{2}\) and \(P(A\cup B)=\frac{4}{5}\), then \(P(A)\) is :
- \(\frac{1}{2}\)
- \(\frac{3}{5}\)
- \(\frac{1}{5}\)
- \(\frac{3}{10}\)
View Solution

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