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Trigonometric addition formulas are a set of identities that show the relationship between the trigonometric functions of the sum or difference of two angles and the trigonometric functions of those angles themselves.
- Trigonometric Addition Formulas are an important tool in the study of trigonometry.
- They allow us to express the trigonometric functions of the sum or difference of two angles in terms of the trigonometric functions of the angles themselves.
- These formulas are derived from the Pythagorean identity and angle sum and difference identities
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Key Terms: Trigonometry, Angle, Sine, Cosine, Tangent, Addition, Subtraction, Theorem, Unit circle
Trigonometric Addition Formulas
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The three most commonly used trigonometry addition formulas are the sine addition formula, cosine addition formula, and tangent addition formula.
- The sine addition formula expresses the sine of the sum or difference of two angles in terms of the sines and cosines of the individual angles.
- The formula is sin(a+b) = sin(a)cos(b) + cos(a)sin(b).
- The cosine addition formula expresses the cosine of the sum or difference of two angles in terms of the cosines and sines of the individual angles.
- The formula is cos(a+b) = cos(a)cos(b) - sin(a)sin(b).
- The tangent addition formula expresses the tangent of the sum or difference of two angles in terms of the tangents of the individual angles.
- The formula is tan(a+b) = (tan(a) + tan(b))/(1 - tan(a)tan(b)).
Formulas
There are three main trigonometric addition formulas: the sine addition formula, cosine addition formula, and tangent addition formula.
Sine Addition Formula:
sin(a + b) = sin(a)cos(b) + cos(a)sin(b)
Sine Subtraction Formula:
sin(a - b) = sin(a)cos(b) - cos(a)sin(b)
Cosine Addition Formula:
cos(a + b) = cos(a)cos(b) - sin(a)sin(b)
Cosine Subtraction Formula:
cos(a - b) = cos(a)cos(b) + sin(a)sin(b)
Tangent Addition Formula:
tan(a + b) = (tan(a) + tan(b)) / (1 - tan(a)tan(b))
Tangent Subtraction Formula:
tan(a - b) = (tan(a) - tan(b)) / (1 + tan(a)tan(b))
In addition to these six main formulas, there are also three double angle formulas:
- sin(2a) = 2sin(a)cos(a)
- cos(2a) = cos2(a) - sin2(a) = 2cos2(a) - 1 = 1 - 2sin2(a)
- tan(2a) = (2tan(a)) / (1 - tan2(a))
These formulas relate the trigonometric functions of double angles to the trigonometric functions of the original angles.
Furthermore, there are also three half-angle formulas:
- sin(a/2) = ±√[(1 - cos(a)) / 2]
- cos(a/2) = ±√[(1 + cos(a)) / 2]
- tan(a/2) = ±√[(1 - cos(a)) / (1 + cos(a))]
These formulas relate the trigonometric functions of half angles to the trigonometric functions of the original angles.
Solved Examples
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Example 1: Use the sine addition formula to find sin(75°).
Solution: The sine addition formula is used as follows:
sin(75°) = sin(45° + 30°) = sin(45°) cos(30°) + cos(45°) sin(30°)
Substituting sin(45°) = √2/2 and cos(30°) = √3/2 values in the above equation,
sin(75°) = (√2/2)(√3/2) + (√2/2)(1/2)
Simplifying:
sin(75°) = (√6 + √2) / 4
Therefore, sin(75°) = (√6 + √2) / 4.
Example 2: Use the cosine addition formula to find cos(75°).
Solution: The cosine addition formula is used to solve this question as follows:
cos(75°) = cos(45° + 30°) = cos(45°) cos(30°) - sin(45°) sin(30°)
Substituting cos(45°) = √2/2 and sin(30°) = 1/2 values in the above equation,
cos(75°) = (√2/2)(√3/2) - (√2/2)(1/2)
Simplifying:
cos(75°) = (√6 - √2) / 4
Therefore, cos(75°) = (√6 - √2) / 4.
Example 3: Use the tangent addition formula to find the value of tan(75°).
Solution: The tangent addition formula is:
tan(a + b) = (tan(a) + tan(b)) / (1 - tan(a)tan(b))
We can use this formula to find the value of tan(75°) as follows:
tan(75°) = tan(45° + 30°) = (tan(45°) + tan(30°)) / (1 - tan(45°)tan(30°))
Substituting tan(30°) = 1/√3 and tan(45°) = 1 values in the above equation,
tan(75°) = (1 + 1/√3) / (1 - 1/√3)
Simplifying:
tan(75°) = (3 + √3) / (3 - √3)
Rationalizing the denominator by multiplying both numerator and denominator by the conjugate of the denominator:
tan(75°) = [(3 + √3) / (3 - √3)] * [(3 + √3) / (3 + √3)]
tan(75°) = (9 + 6√3 + 3) / (9 - 3)
tan(75°) = (12 + 6√3)
Therefore, tan(75°) = 12 + 6√3.
Value of Sin 120 with verification
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Using the sine addition formula, we can find the value of sin(120°) as follows:
sin(120°) = sin(90° + 30°) = sin(90°)cos(30°) + cos(90°)sin(30°)
Since sin(90°) = 1 and cos(90°) = 0, we have:
sin(120°) = cos(30°)
Using the exact value of cos(30°) = √3/2, we get:
sin(120°) = √3/2
Therefore, sin(120°) = √3/2.
Verification: To verify the value of sin(120°) using the quadrant relationship, note that in the second quadrant, the sine function is positive and the cosine function is negative. Therefore:
sin(120°) = |sin(120°)| = sin(60°)
Using the exact value of sin(60°) = √3/2, we have:
sin(120°) = √3/2
This is consistent with the value obtained earlier using the sine addition formula.
Derivation of Trigonometric Addition Formulas
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There are several ways to derive these formulas, but one common method is to use the complex exponential function.
Let's start by defining the complex exponential function:
e(ix) = cos(x) + i sin(x)
where i is the imaginary unit (i2 = -1).
Using this definition, we can derive the following addition formulas:
sin(a + b) = sin(a) cos(b) + cos(a) sin(b)
cos(a + b) = cos(a) cos(b) - sin(a) sin(b)
tan(a + b) = (tan(a) + tan(b)) / (1 - tan(a) tan(b))
To derive the sine formula, we start with:
e(i(a+b)) = e(ia) e(ib)
Expanding both sides using Euler's formula (which relates the exponential function to sine and cosine), we get:
cos(a+b) + i sin(a+b) = (cos(a) + i sin(a))(cos(b) + i sin(b))
Expanding the right-hand side using the distributive property, we get:
cos(a+b) + i sin(a+b) = cos(a) cos(b) + i sin(a) cos(b) + i sin(b) cos(a) - sin(a) sin(b)
Equating the real and imaginary parts of both sides, we get:
sin(a+b) = sin(a) cos(b) + cos(a) sin(b)
cos(a+b) = cos(a) cos(b) - sin(a) sin(b)
To derive the cosine formula, we use the same approach but use the imaginary part instead of the real part. This gives:
cos(a+b) + i sin(a+b) = (cos(a) + i sin(a))(cos(b) + i sin(b))
cos(a+b) + i sin(a+b) = cos(a) cos(b) - sin(a) sin(b) + i sin(a) cos(b) + i cos(a) sin(b)
Equating the real and imaginary parts of both sides, we get:
cos(a+b) = cos(a) cos(b) - sin(a) sin(b)
sin(a+b) = sin(a) cos(b) + cos(a) sin(b)
To derive the tangent formula, we divide the sine formula by the cosine formula:
tan(a+b) = (sin(a+b))/(cos(a+b))
tan(a+b) = (sin(a) cos(b) + cos(a) sin(b))/(cos(a) cos(b) - sin(a) sin(b))
Using the identities sin(a+b) and cos(a+b), we get:
tan(a+b) = (tan(a) + tan(b))/(1 - tan(a) tan(b))
Proof of Sin(a+b) Theorem
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Consider two angles, a and b, such that 0° ≤ a, b ≤ 90°.
Let A be the point on the unit circle that corresponds to angle a, and let B be the point on the unit circle that corresponds to angle b. Let C be the foot of the perpendicular from A to the x-axis, and let D be the foot of the perpendicular from B to the x-axis. Let E be the intersection point of the line segments AC and BD.
Therefore, AC = sin(a) and BD = sin(b). And AE = cos(b) and BE = cos(a), since these are the x-coordinates of points A and B, respectively. Furthermore, CE = sin(b)cos(a) and DE = sin(a)cos(b), since these are the y-coordinates of points C and D, respectively.
Now calculate the length of line segment AE using the Pythagorean theorem:
AE2 = AC2 + CE2
AE2 = sin2(a) + sin2(b)cos2(a)
Similarly, calculate the length of line segment BE:
BE2 = BD2 + DE2
BE2 = sin2(b) + sin2(a)cos2(b)
Now, calculate the length of line segment AB using the Pythagorean theorem:
AB2 = AE2 + BE2
AB2 = sin2(a) + sin2(b)cos2(a) + sin2(b) + sin2(a)cos2(b)
Simplifying and factoring out sin2(a)sin2(b), we get:
AB2 = sin2(a)(1 - cos2(b)) + sin2(b)(1 - cos2(a))
AB2 = sin2(a)sin2(b) + (sin2(a)cos^2(b) + sin2(b)cos2(a))
AB2 = sin2(a)sin2(b) + 2sin(a)sin(b)cos(a)cos(b)
Taking the square root of both sides, we get:
AB = sin(a)cos(b) + cos(a)sin(b)
Therefore, we have proved the sine addition formula:
sin(a + b) = sin(a)cos(b) + cos(a)sin(b)
Also Read:
Things to Remember
- Trigonometric addition formulas are used to find the sine, cosine, and tangent of the sum or difference of two angles.
- The two most common trigonometric addition formulas are the sum and difference formulas, which are:
- sin(A + B) = sin A cos B + cos A sin B
- cos(A + B) = cos A cos B - sin A sin B
- The sum and difference formulas can be used in reverse to find the sine, cosine, and tangent of the difference of two angles.
- To use the addition formulas, it is important to be familiar with the values of sine and cosine for common angles, such as 0, 30, 45, 60, and 90 degrees.
- Trigonometric addition formulas are often used in calculus, physics, and engineering to solve problems related to angles and periodic functions.
Sample Questions
Q1. Find the value of cos(75°) using the cosine addition formula. (3 marks)
Solution: We know that cos(75°) = cos(45° + 30°). Using the cosine addition formula, we have:
cos(75°) = cos(45°)cos(30°) - sin(45°)sin(30°)
We know that cos(45°) = sin(45°) = sqrt(2)/2 and sin(30°) = 1/2, so we can substitute these values to obtain:
cos(75°) = (sqrt(2)/2)(1/2) - (sqrt(2)/2)(1/2)
cos(75°) = 0.2588
Therefore, the value of cos(75°) is approximately 0.2588.
Q2. Find the value of sin(105°) using the sine addition formula. (3 marks)
Solution: We know that sin(105°) = sin(45° + 60°). Using the sine addition formula, we have:
sin(105°) = sin(45°)cos(60°) + cos(45°)sin(60°)
We know that sin(45°) = cos(45°) = sqrt(2)/2 and sin(60°) = sqrt(3)/2, so we can substitute these values to obtain:
sin(105°) = (sqrt(2)/2)(sqrt(3)/2) + (sqrt(2)/2)(sqrt(3)/2)
sin(105°) = sqrt(6)/4
Therefore, the value of sin(105°) is approximately 0.9659.
Q3. Use the addition formula to find sin(105°) given that sin(75°) = √(6 + 2√3)/4 and cos(15°) = √(6 - 2√3)/4. (5 marks)
Solution: We can use the addition formula sin(A + B) = sin(A)cos(B) + cos(A)sin(B) to find sin(105°). First, we need to find sin(30°) and cos(30°) using the half-angle formula:
sin(30°) = √(1 - cos²(30°)) = √(1 - 3/4) = √(1/4) = 1/2
cos(30°) = √(1 - sin²(30°)) = √(1 - 1/4) = √(3/4) = √3/2
Now, we can use the addition formula:
sin(105°) = sin(75° + 30°) = sin(75°)cos(30°) + cos(75°)sin(30°)
We know sin(75°) and cos(30°) from the problem statement, so we just need to find cos(75°) and sin(30°):
cos(75°) = cos(90° - 15°) = sin(15°) = √(6 - 2√3)/4
sin(30°) = 1/2
Substituting these values into the addition formula, we get:
sin(105°) = (√(6 + 2√3)/4)(√3/2) + (√(6 - 2√3)/4)(1/2)
= (√2/4)(√3√(6 + 2√3) + √(6 - 2√3))
= (√2/4)(√(18 + 6√3) + √(6 - 2√3))
= (√2/4)(√(9 + 3√3) + √(9 - 3√3) + √(6 - 2√3))
= (√2/4)(2√3 + √(6 - 2√3))
= √6/4 + (√2/4)√(6 - 2√3)
= (√6 + √2√(6 - 2√3))/4
Therefore, sin(105°) = (√6 + √2√(6 - 2√3))/4.
Q4. Prove the identity cos(π/4 + x)cos(π/4 - x) = cos2(π/4) - sin2x. (3 marks)
Solution: We can use the addition formula cos(A + B) = cos(A)cos(B) - sin(A)sin(B) to find cos(π/4 + x) and cos(π/4 - x):
cos(π/4 + x) = cos(π/4)cos(x) - sin(π/4)sin(x) = (√2/2)cos(x) - (√2/2)sin(x) = (√2/2)(cos(x) - sin(x))
cos(π/4 - x) = cos(π/4)cos(-x) - sin(π/4)sin(-x) = (√2/2)cos(x) + (√2/2)sin(x) = (√2/2)(cos(x) + sin(x))
Substituting these expressions into the left-hand side of the identity, we get:
cos(π/4 + x)cos(π/4 - x) = [√2/2(cos(x) - sin(x))] x [√2/2(cos(x) + sin(x))]
= 1/2[(cos2(x) - sin2(x))]
Using the identity cos2(π/4) = sin2(π/4) = 1/2, we can simplify this expression to:
cos(π/4 + x)cos(π/4 - x) = cos2(π/4) - sin2(x)
Therefore, the identity is proved.
Q5. Find cos(11π/12) using the half-angle formula. (5 marks)
Solution: We can use the half-angle formula cos(x/2) = ±√[(1 + cos(x))/2] to find cos(11π/24) and then double it using the double-angle formula cos(2x) = cos²(x) - sin²(x). First, we need to find cos(π/6) using the values for cos(30°) and sin(30°):
cos(π/6) = √(1 - sin²(π/6)) = √(1 - 1/4) = √(3/4) = √3/2
Now, we can use the half-angle formula:
cos(π/12) = ±√[(1 + cos(π/6))/2] = ±√[(1 + √3/2)/2]
To determine the sign, we need to use the fact that cos(π/12) is positive because it lies in the first quadrant (0 < π/12 < π/2). Therefore, we take the positive square root:
cos(π/12) = √[(1 + √3/2)/2]
Using the double-angle formula, we get:
cos(11π/12) = cos(2π/3 - π/12) = cos(2(π/4 - π/12)) = cos(π/6)
= √[(1 + √3/2)/2] = (√6 + √2)/4
Therefore, cos(11π/12) = (√6 + √2)/4.
Q6. Find cos(11π/12) using the addition formula. (3 marks)
Solution: We can use the addition formula cos(A + B) = cos(A)cos(B) - sin(A)sin(B) to find cos(11π/12) by expressing it as the sum or difference of known angles. First, we need to find cos(π/6) and sin(π/6) using the values for cos(30°) and sin(30°):
cos(π/6) = √(1 - sin²(π/6)) = √(1 - 1/4) = √(3/4) = √3/2
sin(π/6) = 1/2
Now, we can use the addition formula:
cos(11π/12) = cos(π/4 + π/3) = cos(π/4)cos(π/3) - sin(π/4)sin(π/3)
= (√2/2)(1/2) - (√2/2)(√3/2) = (√2 - √6)/4 - (√6 + √2)/4 = -√6/2
Therefore, cos(11π/12) = -√6/2.
Q7. Prove the identity tan(x + y) = (tan(x) + tan(y))/(1 - tan(x)tan(y)). (3 marks)
Solution: We can use the addition formula for tangent to derive the identity. First, we write the addition formula for tangent:
tan(x + y) = (tan(x) + tan(y))/(1 - tan(x)tan(y))
Now, we need to prove this identity. To do so, we will start with the left-hand side of the identity and manipulate it until we get the right-hand side:
tan(x + y) = sin(x + y)/cos(x + y)
= (sin(x)cos(y) + cos(x)sin(y))/(cos(x)cos(y) - sin(x)sin(y)) (using the addition formulas for sine and cosine)
= (sin(x)/cos(x) + sin(y)/cos(y))/((cos(x)/cos(y)) - (sin(x)/sin(y)))
= (tan(x) + tan(y))/(1 - tan(x)tan(y))
Therefore, the identity is proved.
Q8. Find sin(15°) using the half-angle formula. (5 marks)
Solution: We can use the half-angle formula sin(x/2) = ±√[(1 - cos(x))/2] to find sin(15°/2) and then double it using the double-angle formula sin(2x) = 2sin(x)cos(x). First, we need to find cos(30°) using the values for cos(30°) and sin(30°):
cos(30°) = √3/2
Now, we can use the half-angle formula:
sin(15°) = 2sin(15°/2)cos(15°/2) = 2√[(1 - cos(15°))/2]cos(15°/2)
To find cos(15°/2), we can use the identity cos(2x) = cos²(x) - sin²(x) and the fact that cos(30°) = √3/2 and sin(30°) = 1/2:
cos(15°) = cos(30°/2) = √[(1 + cos(30°))/2] = √[(1 + √3/2)/2]
Substituting this expression into the equation for sin(15°), we get:
sin(15°) = 2√[(1 - √(1 + cos(30°)/2))/2]√[(1 + cos(30°))/2]
= √[(2 - √3)/4]√[(1 + √3)/2]
= (√6 - √2)/4
Therefore, sin(15°) = (√6 - √2)/4.
Q9. Find sin(15°) using the addition formula. (5 marks)
Solution: We can use the addition formula for sine to derive sin(15°) by expressing it as the sum or difference of known angles. First, we need to find sin(45°) and cos(45°) using the values for cos(45°) and sin(45°):
cos(45°) = sin(45°) = √2/2
Now, we can use the addition formula:
sin(15°) = sin(45°/3) = sin(30°/2 +15°/2) = sin(30°/2)cos(15°/2) + cos(30°/2)sin(15°/2)
= (√3/2)(√[(1 + cos(15°))/2]) + (1/2)sin(15°/2)
Substituting the half-angle formula sin(x/2) = ±√[(1 - cos(x))/2], we get:
sin(15°/2) = ±√[(1 - cos(15°))/2] = ±√[(1 - √(1 + cos(30°))/2)/2]
Substituting this expression into the equation for sin(15°), we get:
sin(15°) = (√3/2)√[(1 + √(1 + cos(30°))/2)] ± (√3/4)√[(1 - √(1 + cos(30°))/2)]
= (√6 + √2)/4 or (√6 - √2)/4
Therefore, sin(15°) = (√6 + √2)/4 or (√6 - √2)/4.
Q10. Prove the identity sin(x + y) = sin(x)cos(y) + cos(x)sin(y). (3 marks)
Solution: We can use the addition formula for sine to derive the identity. First, we write the addition formula for sine:
sin(x + y) = sin(x)cos(y) + cos(x)sin(y)
Now, we need to prove this identity. To do so, we will start with the left-hand side of the identity and manipulate it until we get the right-hand side:
sin(x + y) = (sin(x)cos(y) + cos(x)sin(y))
Therefore, the identity is proved.
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