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Question: An astronomical telescope and a Galilean telescope use identical objective lenses. They have the same magnification when both are in normal adjustment. The eyepiece of the astronomical telescope has a focal length ‘f’.
Let's call the focal length of the eyepiece of the Galilean telescope "g". Then, we know that the magnification (M) of both telescopes is the same, which means:
M = - fo / fe for the Galilean telescope
M = fo / fe for the astronomical telescope
where fo is the focal length of the objective lens and fe is the effective focal length of the telescope. The negative sign in the equation for the Galilean telescope is because the image is inverted.
Since M is the same for both telescopes, we can set the two equations equal to each other and solve for g:
fo / feg = fo / f
feg = -f
So, the effective focal length of the Galilean telescope is -f. This means that the eyepiece must have a negative focal length, which is why the Galilean telescope has a concave eyepiece.
Now, we will apply a formula to find eyepiece of astronomical telescope with focal length f which is given as:
L= fo + fe + d
Where, L= Length
fo = Focal length of objective lens
fe = Focal length of eyepiece
d= Final image distance formation by eyepiece lens
Note: The final image distance (d) is always taken as +25 cm in a normal adjustment.
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