NCERT Solutions For Class 12 Physics Chapter 1: Electric Charges and Fields

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NCERT Solutions for Class 12 Physics Chapter 1 Electric charges and fields are provided in this article. Electric charge is the basic property of matter that causes it to experience a force when it is kept in an electric or a magnetic field. The electric field lines start from the positive charge and end on the negative charge.

The chapter is included in the unit Electrostatics which together with Current Electricity has a weightage of 17 marks in the CBSE Class 12 Physics Exam. The NCERT Solutions for Class 12 Physics Chapter 1 covers concepts of electric charge, conductors and insulators, Coulomb’s Law, electric field lines, Gauss’s law, and electric dipole.

Download PDF: NCERT Solutions for Class 12 Physics Chapter 1 Electric Charges and Fields

NCERT Solutions for Class 12 Physics Chapter 1

The NCERT Solutions for class 12 physics chapter 1 Electric Charges and fields are as given below –

Check out: Electric Charges and Fields MCQ

Important Topics of Electric Charges and Fields

Electric Charge refers to the property of subatomic particles that leads it to experience a force when it is placed in an electric and magnetic field.

Electric Charges are of two types – like charges and unlike charges

Like Charges repel each other.
Unlike Charges attract each other.

An electric charge has 3 fundamental properties – quantization, additive nature, and conservation of electric charge.

Quantization – The total charge of a body denotes the integral multiple of a basic quantum of charge.
Additive – This property represents the total charge of a body as an algebraic sum of all the singular charges that act on the system.
Conservation – This property expressed that the total charge of a system is not affected with time. Charges can neither be created nor destroyed.

Coulomb’s law states that mutual electrostatic force that exists between two point charges A and B is directly proportional to their product, AB and inversely proportional to the square of the distance between them.

F_e = ${kq_1q_2\over r^2}$

Electric flux is the total number of electric field lines that pass through a given area in a unit of time.

The electric flux Δθ through an area element of ΔS can be denoted by

Δθ = E.ΔS = EΔScosθ

Conductors are the objects that assist in the movement of electric charge.
Insulators offer resistance to the flow of electricity through them.

Examples of Conductors – Human bodies, Earth, metal, etc.

Examples of Insulators – Nylon, Wood, Porcelain, etc.

Gauss law states that the total amount of electric flux that passes through a closed surface is directly proportional to the enclosed electric charge. The Gauss law formula is expressed by-

Φ = ${Q \over ϵo}$

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Also Read:

Chapter 1 Related Articles
Applications of Gauss’s Law	Charging by Induction	Dipole in a Uniform External Field
Electric Dipole	Maxwell’s Equations	Cells, EMF and Internal Resistance
Kirchhoffs Laws	Electrostatics	Unit of Electric Field

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CBSE CLASS XII Related Questions

1.
Find the ratio $\dfrac{\lambda_\alpha}{\lambda_p}$ of the de Broglie wavelength $\lambda_\alpha$ associated with an alpha particle to the de Broglie wavelength $\lambda_p$ associated with a proton if both are moving with the same velocity.

View Solution

2.
A square loop of side 0.50 m is placed in a uniform magnetic field of 0.4 T perpendicular to the plane of the loop. The loop is rotated through an angle of $60^\circ$ in 0.2 s. The value of emf induced in the loop will be:

5 V
3.5 V
2.5 V
Zero V

View Solution

3.
Consider a cylindrical conductor of length $l$ and area of cross-section $A$. Current $I$ is maintained in the conductor and electrons drift with velocity $\vec{v}_d$ ($|\vec{v}_d| = \frac{e|\vec{E}|}{m}\tau$), (where symbols have their usual meanings). Show that the conductivity $\sigma$ of the material of the conductor is given by
$$\sigma = \frac{ne^2}{m}\tau.$$

View Solution

4.
A ray of light MN is incident normally on the face corresponding with side AB of a prism with an isosceles right-angled triangular base ABC. Trace the path of the ray as it passes through the prism when the refractive index of the prism material is (i) $\sqrt{2}$, and (ii) $\sqrt{3}$.

View Solution

5.
A circular coil of 100 turns and radius $\left(\frac{10}{\sqrt{\pi}}\right)$ cm carrying current of $5.0\,\text{A}$ is suspended vertically in a uniform horizontal magnetic field of $2.0\,\text{T}$. The field makes an angle $30^\circ$ with the normal to the coil. Calculate:
(I) the magnetic dipole moment of the coil, and
(II) the magnitude of the counter torque that must be applied to prevent the coil from turning.

View Solution

6.
A wire of length $L$ is bent round into (i) a square coil having $N$ turns and (ii) a circular coil having $N$ turns. The coil in both cases is free to turn about a vertical axis coinciding with the plane of the coil, in a uniform, horizontal magnetic field and carry the same currents. Find the ratio of the maximum value of the torque acting on the square coil to that on the circular coil.

View Solution

NCERT Solutions For Class 12 Physics Chapter 1: Electric Charges and Fields

NCERT Solutions for Class 12 Physics Chapter 1

Important Topics of Electric Charges and Fields

Previous Year Questions

CBSE CLASS XII Related Questions

1.
Find the ratio $\dfrac{\lambda_\alpha}{\lambda_p}$ of the de Broglie wavelength $\lambda_\alpha$ associated with an alpha particle to the de Broglie wavelength $\lambda_p$ associated with a proton if both are moving with the same velocity.

2.
A square loop of side 0.50 m is placed in a uniform magnetic field of 0.4 T perpendicular to the plane of the loop. The loop is rotated through an angle of $60^\circ$ in 0.2 s. The value of emf induced in the loop will be:

4.
A ray of light MN is incident normally on the face corresponding with side AB of a prism with an isosceles right-angled triangular base ABC. Trace the path of the ray as it passes through the prism when the refractive index of the prism material is (i) $\sqrt{2}$, and (ii) $\sqrt{3}$.

Similar Physics Concepts

Comments

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NCERT Solutions For Class 12 Physics Chapter 1: Electric Charges and Fields

NCERT Solutions for Class 12 Physics Chapter 1

Important Topics of Electric Charges and Fields

Previous Year Questions

CBSE CLASS XII Related Questions

1.Find the ratio $\dfrac{\lambda_\alpha}{\lambda_p}$ of the de Broglie wavelength $\lambda_\alpha$ associated with an alpha particle to the de Broglie wavelength $\lambda_p$ associated with a proton if both are moving with the same velocity.

2.A square loop of side 0.50 m is placed in a uniform magnetic field of 0.4 T perpendicular to the plane of the loop. The loop is rotated through an angle of $60^\circ$ in 0.2 s. The value of emf induced in the loop will be:

4.A ray of light MN is incident normally on the face corresponding with side AB of a prism with an isosceles right-angled triangular base ABC. Trace the path of the ray as it passes through the prism when the refractive index of the prism material is (i) $\sqrt{2}$, and (ii) $\sqrt{3}$.

Similar Physics Concepts

Comments

SUBSCRIBE TO OUR NEWS LETTER

1.
Find the ratio $\dfrac{\lambda_\alpha}{\lambda_p}$ of the de Broglie wavelength $\lambda_\alpha$ associated with an alpha particle to the de Broglie wavelength $\lambda_p$ associated with a proton if both are moving with the same velocity.

2.
A square loop of side 0.50 m is placed in a uniform magnetic field of 0.4 T perpendicular to the plane of the loop. The loop is rotated through an angle of $60^\circ$ in 0.2 s. The value of emf induced in the loop will be:

4.
A ray of light MN is incident normally on the face corresponding with side AB of a prism with an isosceles right-angled triangular base ABC. Trace the path of the ray as it passes through the prism when the refractive index of the prism material is (i) $\sqrt{2}$, and (ii) $\sqrt{3}$.