NCERT Solutions For Class 12 Physics Chapter 8: Electromagnetic Waves

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NCERT Solutions for Class 12 Physics Chapter 8 Electromagnetic Waves are provided in this article. The waves that are produced when an electric field comes into contact with a magnetic field are known as Electromagnetic Waves or EM waves. The concept of EM waves can also be understood by visualizing the waves in which there are sinusoidal variations of vectors of the magnetic and electric field which are perpendicular to each other and also at right angles to the wave propagation direction.

Unit 5 - Electromagnetic Waves along with Unit 6 - Optics has a weightage of 18 marks in the CBSE Class 12 Physics Examination. The NCERT Solutions for Class 12 Physics Chapter 8 covers concepts of displacement current, electromagnetic spectrum, Maxwell Equations, etc.

Download PDF: NCERT Solutions for Class 12 Physics Chapter 8


NCERT Solutions for Class 12 Physics Chapter 8

The NCERT solutions for class 12 physics chapter 8: Electromagnetic waves are given below:

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CBSE Class 12 Physics Chapter 8 Important Topics

  • Electromagnetic Waves are the waves produced when an electric field comes in contact with a magnetic field.

The direction of the propagation of EM waves is given by a vector cross product of the electric and magnetic fields as

\(\overrightarrow E \times \overrightarrow B\)

  • Equation of Speed of EM Wave: The relation between the speed of light, permittivity constant, and permeability constant is as follows:
\(c = {1 \over \mu_0 \epsilon_0}\)
  • The wavelength for the various spectrum of light is as follows - 
    • Radio Waves > 0.1 m
    • Microwave - 0.1m to 1 mm
    • Infrared waves - 1 mm to 700 nm
    • Visible light - 700 nm to 400 nm
    • Ultraviolet - 400 nm to 1nm
    • X-rays - 1nm to 10-3 nm
    • Gamma rays < 10-3 nm

According to their wavelength or frequency, EM waves can be classified as Electromagnetic Spectrum that ranges from 400 nm to 700 nm.

  • Applications of Electromagnetic Waves: Electromagnetic Waves play an important role in communication technology.
The infrared radiations are used in the security cameras for night vision. UV rays can be helped to detect forged banknotes.

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CBSE CLASS XII Related Questions

  • 1.

    Find the ratio $\dfrac{\lambda_\alpha}{\lambda_p}$ of the de Broglie wavelength $\lambda_\alpha$ associated with an alpha particle to the de Broglie wavelength $\lambda_p$ associated with a proton if both are moving with the same velocity.


      • 2.
        A wire of length \(L\) is bent round into (i) a square coil having \(N\) turns and (ii) a circular coil having \(N\) turns. The coil in both cases is free to turn about a vertical axis coinciding with the plane of the coil, in a uniform, horizontal magnetic field and carry the same currents. Find the ratio of the maximum value of the torque acting on the square coil to that on the circular coil.


          • 3.

            A parallel beam of monochromatic light falls normally on a single slit of width $a$ and a diffraction pattern is observed on a screen placed at distance $D$ from the slit. Explain:

            (I) the formation of maxima and minima in the diffraction pattern, and

            (II) why the maxima go on becoming weaker and weaker with its increasing number $n$.


              • 4.

                Consider a cylindrical conductor of length $l$ and area of cross-section $A$. Current $I$ is maintained in the conductor and electrons drift with velocity $\vec{v}_d$ ($|\vec{v}_d| = \frac{e|\vec{E}|}{m}\tau$), (where symbols have their usual meanings). Show that the conductivity $\sigma$ of the material of the conductor is given by

                $$\sigma = \frac{ne^2}{m}\tau.$$


                  • 5.
                    A current of \(4.0\,\text{A}\) flows through a wire of length \(1\,\text{m}\) and cross-sectional area \(1.0\,\text{mm}^2\), when a potential difference of \(2\,\text{V}\) is applied across its ends. Calculate the resistivity of the material of the wire.


                      • 6.
                        The resistance of a metal wire at \(20^\circ\text{C}\) is \(1.05\,\Omega\) and at \(100^\circ\text{C}\) is \(1.38\,\Omega\). Determine the temperature coefficient of resistivity of this metal.

                          CBSE CLASS XII Previous Year Papers

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