NCERT Solutions For Chapter 14: Semiconductor Electronics

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NCERT Solutions for Class 12 Physics Chapter 14 Semiconductor Electronics: Materials, Devices and Simple Circuits are provided in the article below. A semiconductor is a material whose resistivity is between a conductor such as metallic copper and an insulator such as glass. Its resistivity falls as the temperature rises which is completely opposite to any metal. 

Class 12 Physics Chapter 14 Semiconductor Electronics belong to Unit 9 - Electronic Devices which has a weightage of 7 marks in the CBSE Board examinations. Class 12 Physics Semiconductor Electronics NCERT Solutions covers the concepts of intrinsic and extrinsic semiconductors, P-n Junction, and Rectifiers

Download PDF: NCERT Solutions for Class 12 Physics Chapter 14

NCERT Solutions for Class 12 Physics Chapter 14

NCERT Solutions For Class 12 Physics: Chapter 14 Semiconductor Electronics: Materials, Devices and Simple CircuitsNCERT Solutions For Class 12 Physics Chapter 14 Semiconductor Electronics: Materials, Devices and Simple CircuitsNCERT Solutions For Class 12 Physics Chapter 14 Semiconductor Electronics: Materials, Devices and Simple CircuitsNCERT Solutions For Class 12 Physics Chapter 14 Semiconductor Electronics: Materials, Devices and Simple CircuitsNCERT Solutions For Class 12 Physics Chapter 14 Semiconductor Electronics: Materials, Devices and Simple CircuitsNCERT Solutions For Class 12 Physics Chapter 14 Semiconductor Electronics: Materials, Devices and Simple Circuits

Class 12 Physics Chapter 14 – Topics Covered

  • Semiconductors have resistivity or conductivity in between that of metals and insulators.
ρ ~ 10-5. 106 Ωm, σ ~ 10+5 .10-6 Sm-1
  • Types of Semiconductors: There are two types of semiconductors – Elements Semiconductors and Compound Semiconductors.
(i) Elements Semiconductors are available in natural form, e.g. germanium and silicon.
(ii) Compound Semiconductors are made by compounding the metals, e.g. InP, CdS, polyaniline, GaAs, CdSe, anthracene, etc.
  • On the basis of purity, semiconductors are classified as intrinsic semiconductors and extrinsic semiconductors.
    Intrinsic Semiconductors are pure semiconductor that does not have any significant dopant species present

ne  = nh = ni 

where, ne and nh are the number densities of electrons and holes respectively and ni is the intrinsic carrier concentration.

  • Extrinsic Semiconductors are pure semiconductors that are doped with an impurity.
Extrinsic semiconductors are classified into two types: p-type semiconductors and n-type semiconductors.
  • Formation of Depletion Region in p-n junction: During the formation of a p-n junction, due to the concentration gradient across the p and n sides, the holes diffuse from the p-side to the n-side and electrons diffuse from the n-side to the p-side.

Formation of Depletion Region in p-n junction

Formation of Depletion Region in p-n junction


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CBSE CLASS XII Related Questions

  • 1.
    Photoemission of electrons occurs from a metal (\( \phi_0 = 1.96 \, \text{eV} \)) when light of frequency \( 6.4 \times 10^{14} \, \text{Hz} \) is incident on it. Calculate: Energy of a photon in the incident light, The maximum kinetic energy of the emitted electrons, and The stopping potential.


      • 2.
        Suppose a pure Si crystal has \( 5 \times 10^{28} \) atoms per \( \text{m}^3 \). It is doped with \( 5 \times 10^{22} \) atoms per \( \text{m}^3 \) of Arsenic. Calculate majority and minority carrier concentration in the doped silicon. (Given: \( n_i = 1.5 \times 10^{16} \, \text{m}^{-3} \))


          • 3.
            Write any two features of nuclear forces.


              • 4.
                The figure shows three point charges kept at the vertices of triangle ABC. The net electric field, due to this system of charges, at the midpoint M of base BC will be:

                  • \( \frac{q}{4 \pi \epsilon_0 l^2} \) pointing along MA
                  • \( \frac{q}{\pi \epsilon_0 l^2} \) pointing along AM
                  • \( \frac{q}{2 \pi \epsilon_0 l^2} \) pointing along AM
                  • Zero

                • 5.
                  Draw the number of scattered particles versus the scattering angle graph for scattering of alpha particles by a thin foil. Write two important conclusions that can be drawn from this plot.


                    • 6.
                      A long solenoid of length \( L \) and radius \( r_1 \) having \( N_1 \) turns is surrounded symmetrically by a coil of radius \( r_2 \, (r_2>r_1) \) having \( N_2 \) turns (\( N_2 \ll N_1 \)) around its mid-point. Derive an expression for the mutual inductance of solenoid and coil. Is \( M_{12} = M_{21} \) valid in this case?

                        CBSE CLASS XII Previous Year Papers

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