In young double slit experiment initially equal intensities are coming out of the two slits S and S now.

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Assuming that the intensity of light coming out of each slit is equal, when a phase difference is introduced between them, the resultant intensity at any point on the screen will depend on the phase difference between the two waves.

Let's consider the two waves coming out of S and S' as A and B respectively. The intensity of the combined wave can be given by:

I = I1 + I2 + 2√(I1*I2)cos(δ)

where I1 and I2 are the intensities of A and B respectively, and δ is the phase difference between them.

If the phase difference δ is a multiple of π (i.e. δ = 0, π, 2π, etc.), the cosine term becomes +1 and the resultant intensity is maximum. These points on the screen where the intensity is maximum are called interference maxima.

Now, if the phase difference between the two waves is changed, the locations of the interference maxima will also change. If the phase difference changes by π, the intensity at the interference maxima will decrease to zero. This is because the cosine term in the above equation becomes -1.

Therefore, if initially, the intensities of the two waves coming out of S and S' are equal, the interference maxima will be observed at regular intervals on the screen. But if the phase difference between them is changed, the intensity at these interference maxima will change accordingly.

In the young double slit experiment initially equal intensities are coming out of the two slits S and S now.

In the young double slit experiment initially, equal intensities are coming out of the two slits S and S now

Do check out the following:

CBSE CLASS XII Related Questions

  • 1.

    A parallel beam of monochromatic light falls normally on a single slit of width $a$ and a diffraction pattern is observed on a screen placed at distance $D$ from the slit. Explain:

    (I) the formation of maxima and minima in the diffraction pattern, and

    (II) why the maxima go on becoming weaker and weaker with its increasing number $n$.


      • 2.
        A current of \(4.0\,\text{A}\) flows through a wire of length \(1\,\text{m}\) and cross-sectional area \(1.0\,\text{mm}^2\), when a potential difference of \(2\,\text{V}\) is applied across its ends. Calculate the resistivity of the material of the wire.


          • 3.

            Find the ratio $\dfrac{\lambda_\alpha}{\lambda_p}$ of the de Broglie wavelength $\lambda_\alpha$ associated with an alpha particle to the de Broglie wavelength $\lambda_p$ associated with a proton if both are moving with the same velocity.


              • 4.
                Draw the plot of potential energy of a pair of nucleons as a function of their separation. Write two important conclusions that can be drawn from this plot.


                  • 5.

                    A ray of light MN is incident normally on the face corresponding with side AB of a prism with an isosceles right-angled triangular base ABC. Trace the path of the ray as it passes through the prism when the refractive index of the prism material is (i) $\sqrt{2}$, and (ii) $\sqrt{3}$.


                      • 6.
                        A wire of length \(L\) is bent round into (i) a square coil having \(N\) turns and (ii) a circular coil having \(N\) turns. The coil in both cases is free to turn about a vertical axis coinciding with the plane of the coil, in a uniform, horizontal magnetic field and carry the same currents. Find the ratio of the maximum value of the torque acting on the square coil to that on the circular coil.

                          CBSE CLASS XII Previous Year Papers

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