NCERT Solutions for class 10 Mathematics Chapter 5: Arithmetic Progressions

NCERT Solutions for Class 10 Mathematics Chapter 5 Arithmetic Progressions are provided in this article. Some of the important topics of Arithmetic Progressions chapter includes:

Expected no of questions: 2 to 3 questions of total 5 marks

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NCERT Solutions for Class 10 Mathematics Chapter 5

NCERT Solutions for Class 10 Mathematics Chapter 5 Arithmetic Progressions is given below.

Class 10 Mathematics Chapter 5 Arithmetic Progression – Important Topics

Arithmetic Progression[AP] is a mathematical series in which the difference between any two subsequent numbers is a fixed value.

For example, the natural number sequence 1, 2, 3, 4, 5, 6,... is an AP because the difference between two consecutive terms (say 1 and 2) is equal to one (2 -1). Even when dealing with odd and even numbers, the common difference between two consecutive words will be equal to 2.

In simpler words, an arithmetic progression is a collection of integers where each term is resulted by adding a fixed number to the preceding term apart from the first term.

For eg:- 4,6,8,10,12,14,16

The general series for AP is given by,

m, m+d, m+2d, m+3d, ... m+(n-1)d

Formula for finding nth term of an AP series is given by,

an = a + (n-1)d

Formula for sum of n terms is given by,

S = n/2[2a + (n − 1) × d]

NCERT Solutions for Class 10 Chapter 5 Exercises

NCERT Solutions for Class 10 Chapter 5 Arithmetic Progressions Exercises are given below.

Maths Related Articles:

Fundamental Theorem of Arithmetic	Euclid Division Lemma	Root 2 is an irrational number
Complex numbers	Real Numbers Formula	Degree of Polynomial
Factorisation of Polynomials	Roots of Polynomials	Nature of roots

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NCERT Solutions for Class 10 Mathematics	Important Maths Formulas	Maths Study material
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CBSE X Related Questions

1.
In the given figure, \(AB \parallel EF\). If \(AB = 24\) cm, \(EF = 36\) cm and \(DA = 7\) cm, then \(AE\) equals
- \(2.5\) cm
- \(10.5\) cm
- \(3.5\) cm
- \(\frac{14}{3}\) cm
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2.
Find the H.C.F. and L.C.M. of 1530 and 2040.
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3.
The HCF of 960 and 432 is :
- 48
- 54
- 72
- 36
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4.
PQ and PR are two tangents to a circle with centre O and radius 5 cm. AB is another tangent to the circle at C which lies on OP. If \(OP = 13\) cm, then find the length AB and PA.
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5.
In the given figure, \(AB \parallel DE\) and \(AC \parallel DF\). Show that \(\triangle ABC \sim \triangle DEF\). If \(BC = 10\) cm, \(EB = CF = 5\) cm and \(AB = 7\) cm, then find the length DE.
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6.
D is the mid-point of side BC of \(\triangle ABC\). CE and BF intersect at O, a point on AD. AD is produced to G such that \(OD = DG\). Prove that OBGC is a parallelogram.
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