NCERT Solutions for Class 10 Maths Chapter 5 Exercise 5.3

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Jasmine Grover

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NCERT Solutions for Class 10 Maths Chapter 5 Arithmetic Progressions Exercise 5.3 is given in this article with a detailed step by step explanation. Class 10 Maths Chapter 5 Exercise 5.3 has questions related to finding the sum of the first n terms of an AP.

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Check out the solutions of Class 10 Maths NCERT solutions chapter 5 Arithmetic Progression 5.3

Read More: NCERT Solutions For Class 10 Maths Arithmetic Progressions

Check out other exercise solutions of Class 10 Maths Chapter 5

Class 10 Chapter 5 Topics:

CBSE Class 10 Maths Study Guides:

CBSE X Related Questions

  • 1.
    Find the H.C.F. and L.C.M. of 1530 and 2040.


      • 2.
        In the given figure, \(AB \parallel EF\). If \(AB = 24\) cm, \(EF = 36\) cm and \(DA = 7\) cm, then \(AE\) equals

          • \(2.5\) cm
          • \(10.5\) cm
          • \(3.5\) cm
          • \(\frac{14}{3}\) cm

        • 3.
          In the given figure, PA and PB are tangents to a circle centred at O. If \( \angle AOB = 130^\circ \), then \( \angle APB \) is equal to :

            • \( 130^\circ \)
            • \( 50^\circ \)
            • \( 120^\circ \)
            • \( 90^\circ \)

          • 4.
            The HCF of 960 and 432 is :

              • 48
              • 54
              • 72
              • 36

            • 5.
              In the given figure, \(AB \parallel DE\) and \(AC \parallel DF\). Show that \(\triangle ABC \sim \triangle DEF\). If \(BC = 10\) cm, \(EB = CF = 5\) cm and \(AB = 7\) cm, then find the length DE.


                • 6.
                  In a class test, the sum of Anamika's marks obtained in Maths and Science is 30. Had she got 2 marks more in Maths and 3 marks less in Science, the product of the marks would have been 210. Find the marks she got in the two subjects.

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