NCERT Solutions for Class 10 Maths Chapter 5 Exercise 5.4

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Jasmine Grover

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NCERT Solutions for Class 10 Maths Chapter 5 Arithmetic Progressions Exercise 5.4 deals with the concepts such as finding the sum of the first n terms of an AP. Class 10 Maths Chapter 5 covers important topics such as the arithmetic progression formula.

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Check out the solutions of Class 10 Maths NCERT solutions chapter 5 Arithmetic Progression 5.4

Read More: NCERT Solutions For Class 10 Maths Arithmetic Progressions

Check out other exercise solutions of Class 10 Maths Chapter 5

Class 10 Chapter 5 Topics:

CBSE Class 10 Maths Study Guides:

CBSE X Related Questions

  • 1.
    If \(PQ\) and \(PR\) are tangents to the circle with centre \(O\) and radius \(4 \text{ cm}\) such that \(\angle QPR = 90^{\circ}\), then the length \(OP\) is

      • \(4 \text{ cm}\)
      • \(4\sqrt{2} \text{ cm}\)
      • \(8 \text{ cm}\)
      • \(2\sqrt{2} \text{ cm}\)

    • 2.
      Mean and Median of a frequency distribution are 43 and 40 respectively. The value of mode is

        • 34
        • 43
        • 38.5
        • 41.5

      • 3.
        There are two sections A and B of Grade X. There are 28 students in Section A and 30 students in Section B. What is the minimum number of books you will acquire for the class library so that they can be distributed equally among students of Section A or Section B ?

          • 144
          • 2
          • 420
          • 272

        • 4.
          The graph of a quadratic polynomial f(x) passes through (5,0), (0, -1) and (-2, 0). The two factors of the polynomial are

            • \((x + 2), (x - 5)\)
            • \((x + 5), (x - 2)\)
            • \((x + 1), (x - 5)\)
            • \((x - 1), (x + 2)\)

          • 5.
            For an acute angle \(\theta\), if \(\sin \theta = \frac{1}{9}\), then value of \(\frac{9 \csc \theta + 1}{9 \csc \theta - 1}\) is

              • \(0\)
              • \(\frac{80}{81}\)
              • \(1\)
              • \(\frac{82}{80}\)

            • 6.
              If roots of the quadratic equation \(x^2 - k\sqrt{3}x + 2 = 0\) are real and equal, then value of k is

                • \(-2\)
                • \(\sqrt{\frac{8}{3}}\)
                • \(1\)
                • \(2\)

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