NCERT Solutions for Class 10 Maths Chapter 5 Exercise 5.4

Education Journalist | Study Abroad Lead

NCERT Solutions for Class 10 Maths Chapter 5 Arithmetic Progressions Exercise 5.4 deals with the concepts such as finding the sum of the first n terms of an AP. Class 10 Maths Chapter 5 covers important topics such as the arithmetic progression formula.

Download PDF: NCERT Solutions for Class 10 Maths Chapter 5 Exercise 5.4

Check out the solutions of Class 10 Maths NCERT solutions chapter 5 Arithmetic Progression 5.4

Check out other exercise solutions of Class 10 Maths Chapter 5

Class 10 Chapter 5 Topics:

Fundamental Theorem of Arithmetic	Arithmetic Sequence Formula	Arithmetic Progression Revision Notes
Nature of Roots	Discriminant Formula	Quadratic Interpolation Formula

CBSE Class 10 Maths Study Guides:

NCERT Solutions for Class 10 Maths	Difference between in Maths	Math MCQs
Number System	Geometry	Class 10 Notes
Mensuration	Calculus	Arithmetic
Math Study Notes	Trigonometry	Math Formula

CBSE X Related Questions

1.
D is the mid-point of side BC of \(\triangle ABC\). CE and BF intersect at O, a point on AD. AD is produced to G such that \(OD = DG\). Prove that OBGC is a parallelogram.
View Solution
2.
In the given figure, \(AB \parallel DE\) and \(AC \parallel DF\). Show that \(\triangle ABC \sim \triangle DEF\). If \(BC = 10\) cm, \(EB = CF = 5\) cm and \(AB = 7\) cm, then find the length DE.
View Solution
3.
If \(PQ\) and \(PR\) are tangents to the circle with centre \(O\) and radius \(4 \text{ cm}\) such that \(\angle QPR = 90^{\circ}\), then the length \(OP\) is
- \(4 \text{ cm}\)
- \(4\sqrt{2} \text{ cm}\)
- \(8 \text{ cm}\)
- \(2\sqrt{2} \text{ cm}\)
View Solution
4.
In the given figure, PA and PB are tangents to a circle centred at O. If \( \angle AOB = 130^\circ \), then \( \angle APB \) is equal to :
- \( 130^\circ \)
- \( 50^\circ \)
- \( 120^\circ \)
- \( 90^\circ \)
View Solution
5.
The HCF of 960 and 432 is :
- 48
- 54
- 72
- 36
View Solution
6.
Find the greatest number less than 10,000 which is exactly divisible by 48, 60 and 65.
View Solution

View All

Similar Mathematics Concepts

Arithmetic Progressions: Properties, Formulas and Solved Examples

Algebraic Operations on Complex Numbers: Arithmetic Operations

Arithmetic Progression: Properties, Formulas & Examples

NCERT Solutions for class 10 Mathematics Chapter 5: Arithmetic Progressions

MCQs On Arithmetic Progression

Arithmetic Geometric Sequence: Formula & Sum of Terms

NCERT Solutions for Class 10 Maths Chapter 5 Exercise 5.1

NCERT Solutions for Class 10 Maths Chapter 5 Exercise 5.2

NCERT Solutions for Class 10 Maths Chapter 5 Exercise 5.3

Arithmetic Mean: Formula, Properties and Advantages

CBSE X Syllabus

Mathematics Preparation Guides

Arithmetic Progressions: Properties, Formulas and Solved Examples

Distance Formula and Derivation of Coordinate Geometry

Probability- A Theoretical Approach: An Overview and Examples

Area of Circle: Area Formula, Derivation with Solved Examples

Mode of Grouped Data

Pythagoras Theorem: Formula, Theorem, Proof and Examples

Nature of Roots of Quadratic Equation

Probability: Concepts, Problems and Solved Examples

Trigonometry: Ratios, Identities & Trigonometric Table

Heights and Distances: Applications in Trigonometry

Real Numbers: Euclid’s Division Lemma, Properties & Sets

Surface Areas and Volumes Revision Notes

Circles: Definition, Properties, Parts, Theorems

Constructions Revision Notes

Pair of Linear Equations In Two Variables Important Questions

Circles Revision Notes: Theorems of Tangent to the Circle

Statistics Important Questions

Mathematics NCERT Solutions

Euclid's Division Lemma: Proof, Finding HCF & Examples

Area of a Sector: Definition, Formulae and Solved Examples

Real Numbers: Definition, Properties and Examples

Events in Probability: Definition, Types, Examples

Relation Between HCF and LCM: Definition, Methods and Formulas

Geometric Probability: Formula, Illustration, Model

Algebra Formula: Important Formulas in Algebra & Solved Examples

Angle of Depression: Definition, Formula and Solved Examples

Cyclic Quadrilateral: Properties, Theorems and Formulas

Polynomial Notation: Types, Remainder Theorem, Linear and Quadratic Equation

You can also check

NCERT Solutions for Class 10 Maths Chapter 5 Exercise 5.4

CBSE X Related Questions

1.
D is the mid-point of side BC of \(\triangle ABC\). CE and BF intersect at O, a point on AD. AD is produced to G such that \(OD = DG\). Prove that OBGC is a parallelogram.

2.
In the given figure, \(AB \parallel DE\) and \(AC \parallel DF\). Show that \(\triangle ABC \sim \triangle DEF\). If \(BC = 10\) cm, \(EB = CF = 5\) cm and \(AB = 7\) cm, then find the length DE.

3.
If \(PQ\) and \(PR\) are tangents to the circle with centre \(O\) and radius \(4 \text{ cm}\) such that \(\angle QPR = 90^{\circ}\), then the length \(OP\) is

4.
In the given figure, PA and PB are tangents to a circle centred at O. If \( \angle AOB = 130^\circ \), then \( \angle APB \) is equal to :

5.
The HCF of 960 and 432 is :

6.
Find the greatest number less than 10,000 which is exactly divisible by 48, 60 and 65.

Similar Mathematics Concepts

Comments

SUBSCRIBE TO OUR NEWS LETTER

NCERT Solutions for Class 10 Maths Chapter 5 Exercise 5.4

CBSE X Related Questions

1.D is the mid-point of side BC of \(\triangle ABC\). CE and BF intersect at O, a point on AD. AD is produced to G such that \(OD = DG\). Prove that OBGC is a parallelogram.

2.In the given figure, \(AB \parallel DE\) and \(AC \parallel DF\). Show that \(\triangle ABC \sim \triangle DEF\). If \(BC = 10\) cm, \(EB = CF = 5\) cm and \(AB = 7\) cm, then find the length DE.

3.If \(PQ\) and \(PR\) are tangents to the circle with centre \(O\) and radius \(4 \text{ cm}\) such that \(\angle QPR = 90^{\circ}\), then the length \(OP\) is

4.In the given figure, PA and PB are tangents to a circle centred at O. If \( \angle AOB = 130^\circ \), then \( \angle APB \) is equal to :

5.The HCF of 960 and 432 is :

6.Find the greatest number less than 10,000 which is exactly divisible by 48, 60 and 65.

Similar Mathematics Concepts

Comments

SUBSCRIBE TO OUR NEWS LETTER

1.
D is the mid-point of side BC of \(\triangle ABC\). CE and BF intersect at O, a point on AD. AD is produced to G such that \(OD = DG\). Prove that OBGC is a parallelogram.

2.
In the given figure, \(AB \parallel DE\) and \(AC \parallel DF\). Show that \(\triangle ABC \sim \triangle DEF\). If \(BC = 10\) cm, \(EB = CF = 5\) cm and \(AB = 7\) cm, then find the length DE.

3.
If \(PQ\) and \(PR\) are tangents to the circle with centre \(O\) and radius \(4 \text{ cm}\) such that \(\angle QPR = 90^{\circ}\), then the length \(OP\) is

4.
In the given figure, PA and PB are tangents to a circle centred at O. If \( \angle AOB = 130^\circ \), then \( \angle APB \) is equal to :

5.
The HCF of 960 and 432 is :

6.
Find the greatest number less than 10,000 which is exactly divisible by 48, 60 and 65.