NCERT Solutions for Class 10 Maths Chapter 5 Exercise 5.1

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NCERT Solutions for Class 10 Maths Chapter 5 Arithmetic Progressions Exercise 5.1 is given in this article with a detailed explanation. Class 10 Maths Chapter 5 Exercise 5.1 has 4 questions that deal with the basic concepts involved in Arithmetic Progression.

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Check out the solutions of Class 10 Maths NCERT solutions chapter 5 Arithmetic Progression 5.1

Check out other exercise solutions of Class 10 Maths Chapter 5

Class 10 Chapter 5 Topics:

Fundamental Theorem of Arithmetic	Arithmetic Sequence Formula	Arithmetic Progression Revision Notes
Nature of Roots	Discriminant Formula	Quadratic Interpolation Formula
Quadratic Equations Formula	Arithmetic Progression Formula	Complex Numbers and Quadratic Equations

CBSE Class 10 Maths Study Guides:

NCERT Solutions for Class 10 Maths	Difference between in Maths	Math MCQs
Math Study Notes	Trigonometry	Math Formula
Number System	Geometry	Class 10 Notes
Mensuration	Calculus	Arithmetic

CBSE X Related Questions

1.
A kite is flying at a height of $60 \text{ m}$ above the ground level. Ravi, standing at the roof of the house is holding the string straight and observes the angle of elevation of kite as $30^{\circ}$. From the bottom of the same building, the angle of elevation of kite is $45^{\circ}$. Find the length of the string and height of roof from the ground. (Use $\sqrt{3} = 1.73$)
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2.
In the figure given above, $\triangle ABC \sim \triangle XYZ$, then find the values of $x$ and $y$.
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3.
PQ and PR are two tangents to a circle with centre O and radius 5 cm. AB is another tangent to the circle at C which lies on OP. If OP = 13 cm, then find the length AB and PA.
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4.
If the zeroes of a polynomial p(x) are $-3$ and 8, then p(x) equals
- $x^2 + 5x - 4$
- $(x + 3) (-x + 8)$
- $a(x^2 + 5x - 24)$
- $x^2 - 24$
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5.
Prove that :
$\frac{\tan \theta}{1 - \cot \theta} + \frac{\cot \theta}{1 - \tan \theta} = 1 + \tan \theta + \cot \theta$.
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6.
$ABCD$ is a parallelogram such that $AF = 7 \text{ cm}$, $FB = 3 \text{ cm}$ and $EF = 4 \text{ cm}$, length $FD$ equals
- $\frac{21}{4} \text{ cm}$
- $\frac{28}{3} \text{ cm}$
- $\frac{12}{7} \text{ cm}$
- $5.5 \text{ cm}$
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