NCERT Solutions for Class 10 Maths Chapter 5 Exercise 5.1

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Jasmine Grover

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NCERT Solutions for Class 10 Maths Chapter 5 Arithmetic Progressions Exercise 5.1 is given in this article with a detailed explanation. Class 10 Maths Chapter 5 Exercise 5.1 has 4 questions that deal with the basic concepts involved in Arithmetic Progression. 

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Check out the solutions of Class 10 Maths NCERT solutions chapter 5 Arithmetic Progression 5.1

Read More: NCERT Solutions For Class 10 Maths Arithmetic Progressions

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Class 10 Chapter 5 Topics:

CBSE Class 10 Maths Study Guides:

CBSE X Related Questions

  • 1.
    In the given figure, \(AB \parallel EF\). If \(AB = 24\) cm, \(EF = 36\) cm and \(DA = 7\) cm, then \(AE\) equals

      • \(2.5\) cm
      • \(10.5\) cm
      • \(3.5\) cm
      • \(\frac{14}{3}\) cm

    • 2.
      The HCF of 960 and 432 is :

        • 48
        • 54
        • 72
        • 36

      • 3.
        In the given figure, PA and PB are tangents to a circle centred at O. If \( \angle AOB = 130^\circ \), then \( \angle APB \) is equal to :

          • \( 130^\circ \)
          • \( 50^\circ \)
          • \( 120^\circ \)
          • \( 90^\circ \)

        • 4.
          In the given figure, \(AB \parallel DE\) and \(AC \parallel DF\). Show that \(\triangle ABC \sim \triangle DEF\). If \(BC = 10\) cm, \(EB = CF = 5\) cm and \(AB = 7\) cm, then find the length DE.


            • 5.
              Find the H.C.F. and L.C.M. of 1530 and 2040.


                • 6.
                  A bag contains 25 balls. Some of them are yellow and others are green. One ball is drawn at random. If probability of getting a green ball is \(3/5\), then find the number of yellow balls.

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