NCERT Solutions for Class 10 Maths Chapter 6 Triangles Exercise 6.1

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Jasmine Grover

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NCERT Solutions for Class 10 Maths Chapter 6 Triangles Exercise 6.1 is provided in this article. Class 10 Maths Chapter 6 Triangles cover important concepts like the similarity of triangles, congruence of triangles and Pythagoras theorem. Chapter 6 Triangles Exercise 6.1 mainly includes questions based on the concept of similarity between two figures. 

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CBSE X Related Questions

  • 1.
    If \( \alpha, \beta \) are the zeroes of the quadratic polynomial \( px^2 + qx + r \), then find the value of \( \alpha^3\beta + \beta^3\alpha \).


      • 2.
        If the quadratic equation \(9x^2 + 8kx + 16 = 0\) has real and equal roots, then the value of k is

          • 3
          • –3
          • –4
          • \(\pm 3\)

        • 3.
          If \(PQ\) and \(PR\) are tangents to the circle with centre \(O\) and radius \(4 \text{ cm}\) such that \(\angle QPR = 90^{\circ}\), then the length \(OP\) is

            • \(4 \text{ cm}\)
            • \(4\sqrt{2} \text{ cm}\)
            • \(8 \text{ cm}\)
            • \(2\sqrt{2} \text{ cm}\)

          • 4.
            The graph of \(y = f(x)\) is given. The number of zeroes of \(f(x)\) is :

              • 0
              • 1
              • 3
              • 2

            • 5.
              \(ABCD\) is a parallelogram such that \(AF = 7 \text{ cm}\), \(FB = 3 \text{ cm}\) and \(EF = 4 \text{ cm}\), length \(FD\) equals

                • \(\frac{21}{4} \text{ cm}\)
                • \(\frac{28}{3} \text{ cm}\)
                • \(\frac{12}{7} \text{ cm}\)
                • \(5.5 \text{ cm}\)

              • 6.
                D is the mid-point of side BC of \(\triangle ABC\). CE and BF intersect at O, a point on AD. AD is produced to G such that \(OD = DG\). Prove that OBGC is a parallelogram.

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