NCERT Solutions for Class 10 Maths Chapter 6 Triangles Exercise 6.6 (Optional)

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NCERT Solutions for Class 10 Maths Chapter 6 Triangles Exercise 6.6 are provided in this article. Class 10 Maths Chapter 6 Triangles is included under the Unit Geometry of class 10 maths syllabus. This chapter contains a total of 6 exercises. Exercise 6.6 is an optional exercise which includes questions based on different concepts covered in the chapter.

Download PDF: NCERT Solutions for Class 10 Maths Chapter 6 Triangles Exercise 6.6 (Optional)


Check below the NCERT solutions pdf for Class 10 Maths Chapter 6 Exercise 6.6 (Optional)

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Find below NCERT solutions of other exercises of class 10 maths chapter 6 Triangles:

Class 10 Chapter 6 Triangles Related Links:

Class 10 Maths Study Guides:

CBSE X Related Questions

  • 1.
    In an A.P., if $a_{14} - a_8 = 24$, then the common difference of the A.P. is

      • $6$
      • $4$
      • $\pm 4$
      • $3$

    • 2.
      In the given figure, $PQ$ is tangent to the circle with centre $O$. $S$ is a point on the circle such that $\angle SQT = 55^\circ$. The $m\angle QPS$ is

        • $55^\circ$
        • $20^\circ$
        • $35^\circ$
        • $70^\circ$

      • 3.
        If the zeroes of the polynomial \(p(x) = 2x^2 - 7x + 6\) are \(\alpha\) and \(\beta\), then the value of \(\frac{1}{\alpha} + \frac{1}{\beta}\) is

          • \(\frac{7}{2}\)
          • \(\frac{6}{7}\)
          • \(\frac{-7}{6}\)
          • \(\frac{7}{6}\)

        • 4.
          There are two sections A and B of Grade X. There are 28 students in Section A and 30 students in Section B. What is the minimum number of books you will acquire for the class library so that they can be distributed equally among students of Section A or Section B ?

            • 144
            • 2
            • 420
            • 272

          • 5.
            For an acute angle \(\theta\), if \(\sin \theta = \frac{1}{9}\), then value of \(\frac{9 \csc \theta + 1}{9 \csc \theta - 1}\) is

              • \(0\)
              • \(\frac{80}{81}\)
              • \(1\)
              • \(\frac{82}{80}\)

            • 6.
              Mean and Median of a frequency distribution are 43 and 40 respectively. The value of mode is

                • 34
                • 43
                • 38.5
                • 41.5

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