NCERT Solutions for Class 10 Maths Chapter 6 Triangles Exercise 6.5

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NCERT Solutions for Class 10 Maths Chapter 6 Triangles Exercise 6.5 are provided in this article. Class 10 Maths Chapter 6 Triangles is an important chapter included under the Unit Geometry of class 10 maths syllabus. Exercise 6.5 includes questions based on Pythagoras theorem.

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Check below the NCERT solutions pdf for Class 10 Maths Chapter 6 Exercise 6.5

Read Also: NCERT Solutions for Class 10 Maths Chapter 6 Triangles

Find below NCERT solutions of other exercises of class 10 maths chapter 6 Triangles:

Class 10 Chapter 6 Triangles Related Links:

Triangles Revision Notes	MCQ on Triangles	Circles
Tangent to a Circle	Important Questions on Circles	Circles Revision Notes
Triangle Theorems	Types of Triangles	Triangles Important Questions

Class 10 Maths Study Guides:

Math Study Material	Important Formulas in Maths	Difference Between in Maths
Class 10 Maths Notes	NCERT Solutions for Class 10 Maths	Mathematics Important Questions

CBSE X Related Questions

1.
Find the H.C.F. and L.C.M. of 1530 and 2040.
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2.
The HCF of 960 and 432 is :
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3.
In the figure given above, \(\triangle ABC \sim \triangle XYZ\), then find the values of \(x\) and \(y\).
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4.
In the given figure, \(AB \parallel DE\) and \(AC \parallel DF\). Show that \(\triangle ABC \sim \triangle DEF\). If \(BC = 10\) cm, \(EB = CF = 5\) cm and \(AB = 7\) cm, then find the length DE.
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5.
A bag contains 25 balls. Some of them are yellow and others are green. One ball is drawn at random. If probability of getting a green ball is \(3/5\), then find the number of yellow balls.
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D is the mid-point of side BC of \(\triangle ABC\). CE and BF intersect at O, a point on AD. AD is produced to G such that \(OD = DG\). Prove that OBGC is a parallelogram.
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