NCERT Solutions for Class 10 Maths Chapter 6 Triangles Exercise 6.5

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Jasmine Grover

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NCERT Solutions for Class 10 Maths Chapter 6 Triangles Exercise 6.5 are provided in this article. Class 10 Maths Chapter 6 Triangles is an important chapter included under the Unit Geometry of class 10 maths syllabus. Exercise 6.5 includes questions based on Pythagoras theorem.

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Check below the NCERT solutions pdf for Class 10 Maths Chapter 6 Exercise 6.5

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Find below NCERT solutions of other exercises of class 10 maths chapter 6 Triangles:


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CBSE X Related Questions

  • 1.
    D is the mid-point of side BC of \(\triangle ABC\). CE and BF intersect at O, a point on AD. AD is produced to G such that \(OD = DG\). Prove that OBGC is a parallelogram.


      • 2.
        The graph of \(y = f(x)\) is given. The number of zeroes of \(f(x)\) is :

          • 0
          • 1
          • 3
          • 2

        • 3.
          A bag contains 25 balls. Some of them are yellow and others are green. One ball is drawn at random. If probability of getting a green ball is \(3/5\), then find the number of yellow balls.


            • 4.
              The HCF of 960 and 432 is :

                • 48
                • 54
                • 72
                • 36

              • 5.
                \(ABCD\) is a parallelogram such that \(AF = 7 \text{ cm}\), \(FB = 3 \text{ cm}\) and \(EF = 4 \text{ cm}\), length \(FD\) equals

                  • \(\frac{21}{4} \text{ cm}\)
                  • \(\frac{28}{3} \text{ cm}\)
                  • \(\frac{12}{7} \text{ cm}\)
                  • \(5.5 \text{ cm}\)

                • 6.
                  The value of \(p\) for which roots of the quadratic equation \(x^{2} - px + 6 = 0\) are rational, is

                    • \(1\)
                    • \(-5\)
                    • \(25\)
                    • \(\sqrt{5}\)

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