Trigonometric Ratios

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Arpita Srivastava

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In mathematics, trigonometry refers to the sides and angles of a right-angle triangle. It is derived from the Greek words trigonon, which means triangle, and metron, which means measure.

  • The hypotenuse, base, and perpendicular are three sides of a right-angle triangle.
  • Hypteneuse is the largest side of the triangle.
  • Trigonometric ratios are defined as the ratio between the sides of a triangle based on the angle formed between them.
  • There are three types of ratios in trigonometry, namely, sine, cosine, and tangent ratios.
  • All the other ratios are derived from these primary ratios.
  • The trigonometric ratios are used in the fields of mechanics, geometry, and other science-related subjects.

Key Ratios: Trigonometry, Trigonometric Ratios, Right Angled Triangle, Triangle, Sine, Cosine, Tangent, Trigonometric Ratio Table, Angles


Trigonometric Ratios

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Trigonometric ratios are used to calculate the ratios of any two sides of a right-angled triangle on the basis of respective angles. The three sides of a triangle are opposite, adjacent, and hypotenuse.

  • Perpendicular is the opposite side of the right-angled triangle.
  • The base is the side of the triangle that is adjacent to the angle.
  • It is measured with respect to the positive x-axis in the anticlockwise direction.

Practical applications of trigonometric ratios include electronics, electrical engineering, astronomy, geography, oceanography, seismology, and phonetics.

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How to find Trigonometric Ratios?

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The sin, cos, tan, cot, cosec, and secs are six different type of trigonometric ratios. Consider a right angle triangle with angle C and perpendicular side as B.

Sine

Sine is defined as the ratio of perpendicular side to hypotenuse angle. Hence,

sin C = (Opposite side to ∠C)/(Hypotenuse) = AB/AC

Cosine

Cosine is defined as the ratio of the adjacent side to the hypotenuse angle is the Cos angle.

cos C = (Adjacent side to ∠C)/(Hypotenuse) = BC/AC

Tangent

Tangent is defined as the ratio of opposite side angle to the adjacent side. Hence,

tan C = (Opposite side to ∠C)/(Adjacent side to ∠C) = AB/BC

Cosec

Cosec is an inverse of sin angle.So,

cosec C= 1/sin C = (Hypotenuse)/ ( Opposite side to ∠C) = AC/AB

Sec

The sec angle is inverse of cosine. Hence,

sec C = 1/cos C = (Hypotenuse)/ (Opposite side to ∠C) = AC/BC

Cot

The inverse of tangent is cotangent. So,

cot C = 1/tan C = (Adjacent side to ∠C)/(Opposite side to ∠C)= BC/AB

  • These are the various ratios for triangle ABC.
  • Angle B is 90° and angle C and A are 60° and 30°.
  • The acute angles ratios are the same for every right-angled triangle. 
Angle and Parts of Trigonometric Ratios
Angle and Parts of Trigonometric Ratios


Trigonometric Ratios Table

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Several mathematical calculations are necessary for trigonometric ratios. The table given below shows the ratios of various angles like 0 °, 30 °, 45 °, 60 °, and 90°.

Angle 0 ° 30 ° 45 ° 60 ° 90°
Sin C 0 1/2 1/√2 √3/2 1
Cos C 1 √3/2 1/√2 1/2 0
Tan C 0 1/√3 1 √3
Cosec C 2 √2 2/√3 1
Sec C 1 2/√3 √2 2
Cot C √3 1 1/√3 0

Example of Trigonometric Ratios Table

Example: The trigonometric ratio for the above value angles are,

  • Sin 30° = ½
  • Cos 90° = 0
  • Tan 45° = 1


Trigonometry Applications

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Trigonometry is crucial branch of mathematics. Some applications of trigonometry are helpful in daily life which are as follows:

  • Trigonometry helps to calculate the height of mountains and towers.
  • The applications are used in the aviation industry and satellite systems.
  • It determine the distance between sea and shore.
  • The ratio is used to calculate the mechanical and electromagnetic waves quantities.
  • The output power of solar panels is determined by the trigonometric ratio.
  • It helps with creation of map.

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Things to Remember

  • Trigonometric Ratios refers to all the values of all the trigonometric functions based on which the ratio of sides ofright-angled triangle is calculated.
  • A right triangle hypotenuse, base, and perpendicular sides are used to determine a ratio.
  • Sine (sin), cosine (cos), tangent (tan), cotangent (cot), cosecant (cosec), and secant (secs) are several trigonometric ratios
  • Mnemonics determines relationships in different trigonometric functions.
  • Pythagorean theorem, the sum-to-product and product-to-sum formulas, and DeMoivre's theorem are methods used to prove trigonometric identities. 

Sample Questions

Ques: Consider a right-angled triangle ABC. Here, AC = 5cm, BC = 3cm and AB = 4cm. Find tan θ, sin θ, and cos θ If the angle of triangle ABC is θ? (3 marks)

Ans: In the triangle ABC,

Hypotenuse, AC = 5cm

Base, BC = 3cm

Perpendicular, AB = 4cm

So, tan θ = Perpendicular/Base = 4/3

Sin θ = Perpendicular/Hypotenuse = AB/AC = 4/5 

Cos θ = Base/Hypotenuse = BC/AC = 3/5 

Hence, these are the angles for triangle ABC in respect to tan, sin, and cos. 

Ques: Consider sin θ = 12/5 and cos θ = 3/5. Find the value of tan θ? (3 marks)

Ans: The values given here are,

sin θ = 12/5

cos θ = 3/5.

So, Tan θ = Sin θ/Cos θ

= (12/5)/(3/5)

= 12/3

= 4

Hence, the value of tan θ is 4. 

Ques: How does the cos value increases from 0° to 90°? (2 marks)

Ans. According to the trigonometric table ratio, cos 0° = 1, cos 90° = 0. So, the value of θ rises from 0 to 90°. Hence, the value of cos θ lowers from 1 to 0. 

Ques: Consider a triangle ABC with right angle B. Find the value of Sin (A + C)? (3 marks)

Ans. Angle B = 90°

Angle A+B+C = 180°

So, Angle A+C+90 = 180

Angle A+C = 90°

Therefore, sin (A + C) = sin 90° = 1

Ques: Consider sin (A + B) = 1 and tan (A – B) = 1/√3. Find the values of tan A + cot B and sec A – cosec B? (4 marks)

Ans. The value given here is sin (A + B) = 1. We know that Sin 90°=1. So,

 Sin (A + B) = Sin 90°

 (A + B) = 90° - Equation 1

Here, tan (A – B) = 1/√3. Hence,

tan (A – B) = tan 30°

(A – B) = 30° - Equation 2

From the equation 1 and 2, we depict that, A = 60° and B= 30°. So,

tan A + cot B = tan 60° + cot 30°

= √3+ √3 = 2√3

Also, sec A – cosec B = sec 60° - cosec 30°

= 2-2 = 0

Ques: A building is at a distance of 180 feet from point A on the ground. Find the height of the building if tan θ = 4/9? (2 marks)

Ans: The triangle formed is a right-angled triangle. Now apply the trigonometric ratio of tan⁡θ to calculate the height of the building.

tan θ = Perpendicular/Base

4/9 = Height/180 ft

Height = (4 × 180/9) = 80 ft

Ques: Consider sin θ = 18/5 and cos θ = 6/5. Find the value of tan θ? (3 marks)

Ans: The values given here are,

sin θ = 18/5

cos θ = 6/5.

So, Tan θ = Sin θ/Cos θ

= (18/5)/(6/5)

= 18/6

= 3

Hence, the value of tan θ is 3

Ques: In a right-angled triangle ABC, which is right-angled at B, we have AB = 8, and BC = 6. Then find sin A and tan A, cos C and cot C? (5 marks)

Ans: AC2=((AB)2 +(BC)2 )

=((6)2 +82 )

=(36 + 64 ) 

=100

=10

When we consider the t-ratios of∠A we have

Base AB = 8

Perpendicular BC = 6

Hypotenuse AC = 10

sinA= Perpendicular/Hypotenuse= 6/10

tanA= Perpendicular/Base= 6/8

When we consider t-ratios of ∠C, we have

Base BC = 6

Perpendicular AB = 8

Hypotenuse AC = 10

cosC = Base/Hypotenuse = 6/10

cotC = Base/Perpendicular = 6/8

Ques: Reema sees a bird sitting on the branch of a tree at an angle of elevation of 30°. Find the height at which the bird is sitting if Riya is standing 60 miles away from the tree? (3 marks)

Ans. Let us assume a right triangle ABC in which A is the position of the bird, B is the tree touching the ground, and C is the position of Anjali.

Thus,

  • BC = 60 miles
  • Angle C = 30°
  • AB = x miles

Tan C = Opposite Side/Adjacent Side

tan(30°) = x/60

x = 60 × tan(30°)

x = 60 × 0.57 = 34.2

Ques: A building is at a distance of 450 feet from point A on the ground. Find the height of the building if tan θ = 3/5? (2 marks)

Ans: The triangle formed is a right-angled triangle. Now apply the trigonometric ratio of tan⁡θ to calculate the height of the building.

tan θ = Perpendicular/Base

3/5 = Height/450 ft

Height = (3 × 450/5) = 270 ft

Ques: Consider sin θ = 22/5 and cos θ = 11/5. Find the value of tan θ? (3 marks)

Ans: The values given here are,

sin θ = 22/5

cos θ = 11/5.

So, Tan θ = Sin θ/Cos θ

= (22/5)/(11/5)

= 2

Hence, the value of tan θ is 2

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CBSE X Related Questions

  • 1.
    A chord of a circle, of radius 14 cm, subtends an angle of $60^\circ$ at the centre. Find the area of the smaller sector and perimeter of the smaller segment.


      • 2.
        PQ and PR are two tangents to a circle with centre O and radius 5 cm. AB is another tangent to the circle at C which lies on OP. If OP = 13 cm, then find the length AB and PA.


          • 3.
            In the given figure, point D divides the side BC of $\Delta ABC$ in the ratio $1 : 2$. Find length AD.


              • 4.
                If the zeroes of a polynomial p(x) are $-3$ and 8, then p(x) equals

                  • $x^2 + 5x - 4$
                  • $(x + 3) (-x + 8)$
                  • $a(x^2 + 5x - 24)$
                  • $x^2 - 24$

                • 5.
                  Prove that: $\frac{\tan \theta}{1 - \cot \theta} + \frac{\cot \theta}{1 - \tan \theta} = 1 + \tan \theta + \cot \theta$


                    • 6.
                      In the given figure, $AB \parallel DE$ and $AC \parallel DF$. Show that $\Delta ABC \sim \Delta DEF$. If $BC = 10\text{ cm}$, $EB = CF = 5\text{ cm}$ and $AB = 7\text{ cm}$, then find the length $DE$.

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