Relation Between Focal Length and Radius of Curvature

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The relation between focal length and radius of curvature is one of the most important concepts in optics

  • It describes how the shape of a spherical mirror affects the way light rays are reflected. 
  • This knowledge can be used to design optical instruments, such as telescopes, microscopes, and cameras.
  • A spherical mirror is a reflecting surface that is part of a hollow sphere. 
  • It can be either concave or convex, depending on whether the reflecting surface is curved inwards or outwards.
  • A part of a hollow sphere having an outer part coated and the inner part as a reflecting surface is called a Concave mirror.
  • A part of a hollow sphere having an inner part coated and the outer part as a reflecting surface is known as a Convex mirror.
  • The focal length of a spherical mirror is the distance between the pole and the principal focus.
  • The radius of the sphere of which the spherical mirror forms a part is called the radius of curvature of the spherical mirror.

The relation between focal length and radius of curvature of a mirror is given by the formula

f = \(\frac{R}{2}\)

Where

  • f is the focal length
  • R is the radius of curvature.

Key Terms: Convex mirror, Concave mirror, Focal length, Radius of curvature, Spherical mirrors, Light, Reflecting surfaces, Plane mirror, Laws of reflection


Spherical Mirror

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A spherical mirror is a reflecting surface that has the shape of a piece cut out of a hollow sphere. Spherical mirrors are of two types

  • Concave mirror: Concave spherical mirrors are converging mirrors, which means they converge parallel beams of light into a single point. This is because the light rays are reflected off the curved surface of the mirror and towards the center of curvature.
  • Convex mirror: Convex spherical mirrors are diverging mirrors, which means they diverge parallel beams of incident light. This is because the light rays are reflected off the curved surface of the mirror and away from the center of curvature.

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Focal Length and Radius of Curvature of Spherical Mirrors

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The focal length of a spherical mirror is the distance between the pole of the mirror and the principal focus. 

  • The principal focus is the point on the principal axis of the mirror where all parallel rays of light incident on the mirror converge after reflection.
  • It is denoted by ‘f’.
  • Since focal length is a measure of distance, its SI unit is meter (m).
  • The focal length of a concave mirror is taken as “Negative”.
  • The focal length of a convex mirror is taken as “Positive”.
  • The focal length of a plane mirror is taken as “Infinity”.

The radius of curvature of a spherical mirror is defined as the radius of the sphere of which the spherical mirror forms a part.

  • It is denoted by “R”.
  • Since the radius of curvature is a measure of distance, its SI unit is meter (m).
  • The radius of curvature of a concave mirror is taken as “Negative”.
  • The radius of curvature of a convex mirror is taken as “Positive”.
  • The radius of curvature of a plane mirror is taken as “Infinity”.

Relation Between Focal Length and Radius of Curvature Formula

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The relation between the focal length and radius of curvature of a mirror is given by the formula

f = \(\frac{R}{2}\)

Where

  • f is the focal length of the spherical mirror
  • R is the radius of curvature of the spherical mirror.

Derivation of Relation Between Focal Length and Radius of Curvature of a Concave Mirror

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Let a ray OA incident on a concave mirror at point A. After reflection, the ray passes through the focus (F). CA is normal to the mirror at A.

Concave mirror

Concave Mirror

According to the law of reflection,

∠i = ∠r = θ

Where

Also, ∠ACF = ∠OAC = θ (alternate angle)

∠AFP is the external angle of △ACF, therefore

∠AFP = ∠ACF + ∠CAF

⇒ ∠AFP = θ + θ = 2θ

From △ANC, tanθ = AN/NC

Since θ is very small, therefore tanθ ≅ θ, Hence

θ = AN/NC …(i)

From △ANF, tan2θ = AN/NF

⇒ 2θ = AN/NF …(ii)

From equation (i) and (ii), we get

2(AN/NC) = AN/NF

⇒ NC = 2 NF

As the aperture of the mirror is small, point N lies very close to P. Therefore

NF = PF and NC = PC

Thus PC = 2 PF

Using the sign convention,

  • PC = – R (Radius of curvature of the concave mirror)
  • PF = – f (Focal length of the concave mirror)

On substituting the values, we get

-R = – 2f

⇒ f = R/2


Derivation of Relation Between Focal Length and Radius of Curvature of a Convex Mirror

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Let a ray of light OA incident on a convex mirror at point A, after reflection, the rays go along AB which meets the principal axis at the focus F when produced backward.

Convex mirror

Convex Mirror

According to the law of reflection,

∠i = ∠r = θ

Where

  • ∠i is the angle of incidence
  • ∠r is the angle of reflection

Also, ∠CAF = ∠BAN’ = θ (vertically opposite angle)

Ans, ∠PCA = ∠OAN’ = θ (corresponding angle)

∠AFP is the external angle of △ACF, therefore

∠AFP = ∠PCA + ∠CAF

⇒ ∠AFP = θ + θ = 2θ

From △ANC, tanθ = AN/NC

Since θ is very small, therefore tanθ ≅ θ, Hence

θ = AN/NC …(i)

From △ANF, tan2θ = AN/NF

⇒ 2θ = AN/NF …(ii)

From equation (i) and (ii), we get

2(AN/NC) = AN/NF

⇒ NC = 2 NF

As the aperture of the mirror is small, point N lies very close to P. Therefore

NF = PF and NC = PC

Thus PC = 2 PF

Using the sign convention,

  • PC = R (Radius of curvature of the convex mirror)
  • PF = f (Focal length of the convex mirror)

On substituting the values, we get

R = 2f

⇒ f = R/2


Solved Examples

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Ques. A concave mirror has a focal length of 20 cm. Calculate its radius of curvature.

Ans. A concave mirror is a spherical mirror in which the reflecting surface bulges inwards.

The focal length of a concave mirror is half its radius of curvature i.e.

f = R/2

Where

  • f is the focal length of the concave mirror
  • R is the radius of curvature of the concave mirror.

Given, the focal length of the concave mirror, f = 20 cm

Therefore, the radius of curvature, R = 2f = 2 x 20 = 40 cm

Ques. A convex mirror has a radius of curvature of 60 cm. Calculate its focal length.

Ans. A convex mirror is a spherical mirror in which the reflecting surface bulges outward.

The radius of curvature of the convex mirror is related to its focal length as

f = R/2

Where

  • f is the focal length of the convex mirror
  • R is the radius of curvature of the convex mirror.

Given, the radius of curvature of the convex mirror, R = 60 cm

Therefore, the focal length, f = R/2 = 60/2 = 30 cm


Things to Remember

  • A spherical mirror is a reflecting surface that is formed by a part of a hollow sphere.
  • The radius of curvature of a spherical mirror is the distance between the pole of the mirror and the center of curvature.
  • The distance between the pole and the principal focus of the spherical mirror is called the focal length of the spherical mirror.
  • The relationship between the focal length and radius of curvature of a spherical mirror is given by f = R/2.
  • The relation f = R/2 is valid for both concave and convex mirrors.
  • The focal length and radius of curvature of a plane mirror is infinity.
  • The focal length of a mirror does not change when immersed in a liquid.

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Sample Questions

Ques. What is a spherical mirror? (2 Marks)

Ans. A spherical mirror is a reflecting surface that is formed by a part of a hollow sphere. These are of two types

  • Concave mirror
  • Convex mirror

Ques. Define the radius of curvature of a spherical mirror. (2 Marks)

Ans. The radius of curvature of a spherical mirror is the radius of the sphere of which the mirror is a part. It is the distance between the pole of the mirror and the center of curvature. The center of curvature is the point on the principal axis of the mirror where all parallel rays of light incident on the mirror converge after reflection.

Ques. A concave mirror has a radius of curvature of 40 cm. At what distance the pole of the mirror a parallel beam of light would be focussed after reflection? (5 Marks)

Ans. Given the radius of curvature of the concave mirror, R = – 40 cm

Using relation f = R/2, 

Where f is the focal length and R is the radius of curvature of the concave mirror.

We have

Focal length, f = (-40)/2 = – 20 cm

Since the rays of light incident on the concave mirror are parallel, therefore the object distance is taken as infinity. i.e. u = -∞

Now using relation 1/f = 1/u + 1/v, we have

1/v = 1/f - 1/u

On substituting the values, we get

1/v = 1/(-20) - 1/(-∞)

⇒ v = -20 cm

Hence the image formed at the focus of the mirror.

Ques. What is the reflection of light? (2 Marks)

Ans. The phenomenon of bouncing back of light in the same medium when the light falls on a surface is known as the reflection of light.

The surface that reflects the light is known as the reflecting surface.

Ques. Define Light. (2 Marks)

Ans. Light is a form of energy that induces the sensation of sight in our eyes and makes us able to see various things present in our surroundings.

It is the visible part of the electromagnetic spectrum consisting of various colors of wavelength ranging from 400 nm to 780 nm.

Ques. An object is placed (i) 10 cm (ii) 5 cm in front of a concave mirror of radius of curvature 15 cm. Compare the position, nature, and magnification of the image in each case. (5 Marks)

Ans. Given that the radius of curvature of the concave mirror is, R = - 15 cm.

Therefore, its focal length will be, f = -15/2 cm

Case (i): When the object is placed 10 cm in front of the concave mirror, i.e. u = - 10 cm

Using the mirror formula for spherical mirrors, we have

1/f = 1/u + 1/v

Where v is the distance of the image from the mirror.

On substituting the values, we get

-2/15 = -1/10 + 1/v

⇒ 1/v = -2/15 + 1/10

⇒ v = -30 cm

Now magnification is given by

m = -v/u = - (-30/-10) = -3

Hence, the image is on the same side as the object, and the image is real, inverted, and magnified.

Case (ii): When the object is placed 5 cm in front of the concave mirror, i.e. u = - 5 cm

Using the mirror formula for spherical mirrors, we have

1/f = 1/u + 1/v

Where v is the distance of the image from the mirror.

On substituting the values, we get

-2/15 = -1/5 + 1/v

⇒ 1/v = -2/15 + 1/5

⇒ v = 15 cm

Now magnification is given by

m = -v/u = - (15/-5) = 3

Hence, the image formed behind the mirror, and is virtual, erect, and magnified.

Ques. A concave mirror is held in water. What should be the change in the focal length of the mirror? (1 Mark)
(a) Doubled
(b) Remains the same
(c) Increases exponentially
(d) Halved

Ans. The correct answer is b. Remains the same

Explanation: The focal length of a concave mirror is independent of the medium. As a result, even after holding the mirror in water, the focal length will remain constant.

Ques. A square of side 4.0 cm is placed 20 cm away from the concave mirror of radius of curvature 30 cm. Calculate the area enclosed by the image of the square. (5 Marks)

Ans. Given

  • The height of the square, h = 4 cm
  • Distance of the square from the concave mirror, u = -20 cm
  • The radius of curvature of the mirror, R = -30 cm

The focal length of the mirror is given by

f = R/2 = -30/2 = -15 cm

From the mirror formula for spherical mirrors, we have

1/f = 1/u + 1/v

Where v is the image distance.

On substituting the values, we get

-1/15 = -1/20 + 1/v

⇒ 1/v = -1/15 + 1/20

⇒ v = -60 cm

Now magnification is given by

m = -v/u = - (-60/-20) = -3

Here the negative sign shows that the image is real.

Also. magnification is given by

m = height of the image(h’) / height of the object(h)

On substituting the values, we get

-3 = h’/4

⇒ h’ = -12 cm

Hence, the area of the image is 12 x 12 = 144 cm2

Ques. Two concave mirrors have the same focal length but the aperture of one is larger than that of the other. Which mirror forms the sharper image and why? (1 Mark)
(a) Convex
(b) Plane
(c) Concave
(d) Prism

Ans. The correct answer is c. Concave

Explanation: Because it is free from spherical aberration, the concave mirror with a smaller aperture produces a sharper image. Even though both have the same focal length, the change in aperture affects image formation.

Ques. Which of the following causes refraction of light? (1 Mark)
(a) Change in the speed of light from one medium to another
(b) Change in viscosity of light from one medium to another
(c) Change in the density of light from one medium to another
(d) Change in direction of light from one medium to another

Ans. The correct answer is a. Change in the speed of light from one medium to another

Explanation: Light travels at different speeds depending on the medium. Light bends or refracts due to the change in speed of light when it travels from one medium to another.

Ques. Derive the relationship between the speed of an object and the speed of the image formed by a spherical mirror. (3 Marks)

Ans. The mirror formula for a spherical mirror is given by

1/u + 1/v = 1/f …(i)

Where

  • f is the focal length of the spherical mirror
  • u is the distance of the object from the mirror
  • v is the distance of the image from the mirror

On differentiating the above equation with respect to time, we get

-1/u2 du/dt - 1/v2 dv/dt = 0

The differentiation of focal length (f) with respect to time is zero because the focal length of the spherical mirror is constant.

⇒ 1/v2 dv/dt = 1/u2 du/dt

⇒ dv/dt = -v2/u2 du/dt

Here

  • dv/dt = vi i.e. the speed of the image, and
  • du/dt = v0 i.e. the speed of the object

On substituting, we get

vi = -(u/v)2 v0

From equation (i), we get v = uf/(u-f), Hence

The speed of the image is given by

vi = – \([\frac{f}{u – f}]^2v_0\)

Ques. What is the focal length of a spherical mirror? (1 Mark)

Ans. The distance between the pole and the principal focus of the spherical mirror is called the focal length of the spherical mirror.

Ques. What is the mirror formula for a spherical mirror? (2 Marks)

Ans. The mirror equation, commonly referred to as the mirror formula, describes the relationship between the object's distance from the mirror, the focal length of the mirror, and the image's distance from the mirror.

The mirror formula for a spherical mirror is given by

1/u + 1/v = 1/f

Where

  • f is the focal length of the spherical mirror
  • u is the distance of the object from the mirror
  • v is the distance of the image from the mirror

Ques. Define sign convention rules for spherical mirrors. (3 Marks)

Ans. The sign convention rules used for spherical mirrors are

  • All the distances are measured from the pole of a spherical mirror.
  • Distances measured in the direction of the incident light are taken as positive, whereas the distances measured in the direction opposite to that of the incident light are taken as negative.
  • The upward distances perpendicular to the principal axis are taken as positive while the downward distances perpendicular to the principal axis are taken as negative.

Ques. What are the uses of spherical mirrors? (3 Marks)

Ans. Spherical mirrors are classified into two types: convex and concave mirrors.

Convex Mirror Applications

  • Vehicle mirrors as rear-view mirrors.
  • Reflectors for street lights.
  • Used in a magnifying glass.
  • As security mirrors.
  • Convex mirrors are used in the making of a sunglass lens.
  • A telescope uses convex mirrors.

Concave Mirror Applications

  • Headlights
  • Solar furnaces
  • Dental mirrors
  • Shaving mirrors
  • Astronomical telescopes
  • Satellite dishes
  • Ophthalmoscope
  • Head mirrors

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