NCERT Solutions for Class 10 Maths Chapter 6 Triangles Exercise 6.1

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Jasmine Grover

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NCERT Solutions for Class 10 Maths Chapter 6 Triangles Exercise 6.1 is provided in this article. Class 10 Maths Chapter 6 Triangles cover important concepts like the similarity of triangles, congruence of triangles and Pythagoras theorem. Chapter 6 Triangles Exercise 6.1 mainly includes questions based on the concept of similarity between two figures. 

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CBSE X Related Questions

  • 1.
    The value of \(p\) for which roots of the quadratic equation \(x^{2} - px + 6 = 0\) are rational, is

      • \(1\)
      • \(-5\)
      • \(25\)
      • \(\sqrt{5}\)

    • 2.
      Assertion (A) : H.C.F. \((36 m^{2}, 18 m) = 18 m\), where \(m\) is a prime number.
      Reason (R) : H.C.F. of two numbers is always less than or equal to the smaller number.

        • Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of the Assertion (A).
        • Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of the Assertion (A).
        • Assertion (A) is true, but Reason (R) is false.
        • Assertion (A) is false, but Reason (R) is true.

      • 3.
        The graph of \(y = f(x)\) is given. The number of zeroes of \(f(x)\) is :

          • 0
          • 1
          • 3
          • 2

        • 4.
          A circle centered at (2, 1) passes through the points A(5, 6) and B(-3, K). Find the value(s) of K. Hence find length of chord AB.


            • 5.
              If the pair of linear equations : \( a_1x + b_1y + c_1 = 0 \) and \( a_2x + b_2y + c_2 = 0 \) is consistent and dependent, then

                • \( \frac{a_1}{a_2} \neq \frac{b_1}{b_2} \)
                • \( \frac{a_1}{a_2} = \frac{b_1}{b_2} = \frac{c_1}{c_2} \)
                • \( \frac{a_1}{a_2} = \frac{b_1}{b_2} \neq \frac{c_1}{c_2} \)
                • \( \frac{a_1}{a_2} = \frac{b_1}{b_2} = \frac{c_1}{c_2} \)

              • 6.
                PQ and PR are two tangents to a circle with centre O and radius 5 cm. AB is another tangent to the circle at C which lies on OP. If \(OP = 13\) cm, then find the length AB and PA.

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