NCERT Solutions for Class 10 Maths Chapter 6 Triangles Exercise 6.1

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NCERT Solutions for Class 10 Maths Chapter 6 Triangles Exercise 6.1 is provided in this article. Class 10 Maths Chapter 6 Triangles cover important concepts like the similarity of triangles, congruence of triangles and Pythagoras theorem. Chapter 6 Triangles Exercise 6.1 mainly includes questions based on the concept of similarity between two figures.

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Check out NCERT solutions of other exercises of class 10 maths chapter 6 Triangles:

Class 10 Chapter 6 Triangles Related Links:

Triangle Theorems	Types of Triangles	Triangles Important Questions
Triangles Revision Notes	MCQ on Triangles	Circles
Tangent to a Circle	Important Questions on Circles	Circles Revision Notes

Class 10 Maths Study Guides:

Math Study Material	Important Formulas in Maths	Difference Between in Maths
Class 10 Maths Notes	NCERT Solutions for Class 10 Maths	Mathematics Important Questions

CBSE X Related Questions

1.
If $PQ$ and $PR$ are tangents to the circle with centre $O$ and radius $4 \text{ cm}$ such that $\angle QPR = 90^{\circ}$, then the length $OP$ is
- $4 \text{ cm}$
- $4\sqrt{2} \text{ cm}$
- $8 \text{ cm}$
- $2\sqrt{2} \text{ cm}$
View Solution
2.
If the zeroes of the polynomial $p(x) = 2x^2 - 7x + 6$ are $\alpha$ and $\beta$, then the value of $\frac{1}{\alpha} + \frac{1}{\beta}$ is
- $\frac{7}{2}$
- $\frac{6}{7}$
- $\frac{-7}{6}$
- $\frac{7}{6}$
View Solution
3.
In an A.P., if $a_{14} - a_8 = 24$, then the common difference of the A.P. is
- $6$
- $4$
- $\pm 4$
- $3$
View Solution
4.
Assertion (A) : H.C.F. $(36 m^{2}, 18 m) = 18 m$, where $m$ is a prime number.
Reason (R) : H.C.F. of two numbers is always less than or equal to the smaller number.
- Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of the Assertion (A).
- Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of the Assertion (A).
- Assertion (A) is true, but Reason (R) is false.
- Assertion (A) is false, but Reason (R) is true.
View Solution
5.
Mean and Median of a frequency distribution are 43 and 40 respectively. The value of mode is
- 34
- 43
- 38.5
- 41.5
View Solution
6.
There are two sections A and B of Grade X. There are 28 students in Section A and 30 students in Section B. What is the minimum number of books you will acquire for the class library so that they can be distributed equally among students of Section A or Section B ?
- 144
- 2
- 420
- 272
View Solution

View All

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NCERT Solutions for Class 10 Maths Chapter 6 Triangles Exercise 6.1

CBSE X Related Questions

1.
If \(PQ\) and \(PR\) are tangents to the circle with centre \(O\) and radius \(4 \text{ cm}\) such that \(\angle QPR = 90^{\circ}\), then the length \(OP\) is

2.
If the zeroes of the polynomial \(p(x) = 2x^2 - 7x + 6\) are \(\alpha\) and \(\beta\), then the value of \(\frac{1}{\alpha} + \frac{1}{\beta}\) is

3.
In an A.P., if $a_{14} - a_8 = 24$, then the common difference of the A.P. is

4.
Assertion (A) : H.C.F. \((36 m^{2}, 18 m) = 18 m\), where \(m\) is a prime number.
Reason (R) : H.C.F. of two numbers is always less than or equal to the smaller number.

5.
Mean and Median of a frequency distribution are 43 and 40 respectively. The value of mode is

6.
There are two sections A and B of Grade X. There are 28 students in Section A and 30 students in Section B. What is the minimum number of books you will acquire for the class library so that they can be distributed equally among students of Section A or Section B ?

Similar Mathematics Concepts

Comments

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NCERT Solutions for Class 10 Maths Chapter 6 Triangles Exercise 6.1

CBSE X Related Questions

1.If \(PQ\) and \(PR\) are tangents to the circle with centre \(O\) and radius \(4 \text{ cm}\) such that \(\angle QPR = 90^{\circ}\), then the length \(OP\) is

2.If the zeroes of the polynomial \(p(x) = 2x^2 - 7x + 6\) are \(\alpha\) and \(\beta\), then the value of \(\frac{1}{\alpha} + \frac{1}{\beta}\) is

3.In an A.P., if $a_{14} - a_8 = 24$, then the common difference of the A.P. is

4.Assertion (A) : H.C.F. \((36 m^{2}, 18 m) = 18 m\), where \(m\) is a prime number. Reason (R) : H.C.F. of two numbers is always less than or equal to the smaller number.

5.Mean and Median of a frequency distribution are 43 and 40 respectively. The value of mode is

6.There are two sections A and B of Grade X. There are 28 students in Section A and 30 students in Section B. What is the minimum number of books you will acquire for the class library so that they can be distributed equally among students of Section A or Section B ?

Similar Mathematics Concepts

Comments

SUBSCRIBE TO OUR NEWS LETTER

1.
If \(PQ\) and \(PR\) are tangents to the circle with centre \(O\) and radius \(4 \text{ cm}\) such that \(\angle QPR = 90^{\circ}\), then the length \(OP\) is

2.
If the zeroes of the polynomial \(p(x) = 2x^2 - 7x + 6\) are \(\alpha\) and \(\beta\), then the value of \(\frac{1}{\alpha} + \frac{1}{\beta}\) is

3.
In an A.P., if $a_{14} - a_8 = 24$, then the common difference of the A.P. is

4.
Assertion (A) : H.C.F. \((36 m^{2}, 18 m) = 18 m\), where \(m\) is a prime number.
Reason (R) : H.C.F. of two numbers is always less than or equal to the smaller number.

5.
Mean and Median of a frequency distribution are 43 and 40 respectively. The value of mode is

6.
There are two sections A and B of Grade X. There are 28 students in Section A and 30 students in Section B. What is the minimum number of books you will acquire for the class library so that they can be distributed equally among students of Section A or Section B ?