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Valence bond theory (VBT) of coordination compound, is based on the assumption that electron pairs are donated to form a metal-ligand bond. Linus Pauling developed the theory
- This donating of electrons forms the coordinate bond between the ligand and the metal.
- This theory explains the filling of the atomic orbitals with the electrons.
- The earlier system by Lewis although describe the configuration of the molecule but fails to explain the chemical bond.
- On the other hand, the VSEPR theory was restricted to only certain molecules, therefor there was a need for a new theory.
| Table of Content |
Key Terms: Valence Bond Theory, electrons, atomic orbitals, VSEPR theory, coordinate bond.
Valence Bond Theory
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According to the Valence Bond Theory:
- The electrons are present in the atomic orbitals and not in the molecular orbitals.
- When these atomic orbitals overlap, they result in the formation of chemical bonds. There is a localization of electrons in the bond region, due to the overlap.
- The origin of the bond is covalent when it comes to metallic bonding. The electron pair bond between the atoms shows resonance.
Also Read: Quantum Mechanical Model of Atom
Postulates of Valence Bond Theory
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The postulates of valence bond theory are as follows:
- A formation of a covalent bond is observed when there is an overlap between the valence orbitals of two different atoms.
- There is an increase in the electron density, which results in the stability of the molecules.
- The nature of the covalent bond is directional and parallel to the atomic orbitals that are overlapping.
- There are many unpaired electrons, which results in the formation of multiple bonds.
- On the other hand, the paired electrons, do not take part in the formation of chemical bonds.
- There is a difference in the way, the atomic orbitals overlap in sigma and pi bonds.
- The pi bonds are formed on a sideways overlapping and along the axis overlapping results in a sigma bond.
Features of Valence Bond Theory
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The features of the Valence Bond Theory of Coordination Compounds are as follows:
- The vacant orbitals like s,p, and d orbitals are made available by the central atom. This is equal to the coordination number and forms the covalent coordination bond with the ligand.
- The vacant orbitals form hybrid orbitals, by hybridization and forming equivalent bonding orbitals. All these hybrid orbitals have the same energy, definite directional properties, and also the same geometry.
- The bond in the metal complexes is formed when the lone pairs of the filled ligand orbitals overlap with the vacant hybrid orbitals of the central atoms. This forms a covalent bond.
- Ligands have at least one orbital with a lone pair. The ligands are classified as weak ligands (F⁻) and strong ligands (CN⁻).
- The tendency of a strong ligand is to form a pair with the d orbitals of the central atom, which cannot be done by a weak ligand.
- If the complex has an unpaired electron, it is paramagnetic. If the complex has all the electrons paired then it is diamagnetic.
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Hybridization and Geometry
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The geometry and hybridization depend on the coordination number. It is as given below:
| Coordination Number | Types of hybridization | Geometry |
|---|---|---|
| 2 | sp | Linear |
| 3 | sp2 | Triangular planar |
| 4 | sp3 | Tetrahedral |
| 4 | sp2d | Square Planar |
| 4 | sd3 | Tetrahedral |
| 5 | dsp3 | Trigonal bipyramidal |
| 5 | dsp3 | Square pyramidal |
| 6 | d2sp3 | Octahedral |
| 6 | sp3d2 | Octahedral |
Limitation of Valence Bond Theory
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Even though some limitations of Lewis dot structure and VSEPR theory were out-ruled by VBT. It has some limitations as mentioned follows:
- The nature of the ligand cannot be explained.
- The color and electronic spectra of the complexes were not explained by VBT.
- It cannot give an explanation as to why the pairing of electrons takes place in the presence of strong ligands.
- The reaction rate and the mechanism of the reaction are left untouched by VBT.
Also Read: Energy level Diagram
Things to Remember
- Valence Bond theory suggests that the electrons are present in the atomic orbitals.
- There is an overlapping between the atomic orbitals that result in the formation of the chemical bond.
- The density of electrons increases at the site of overlap.
- Sigma bonds show along the axis overlap and a pi bond shows sideways overlap.
- There are two types of ligands, strong and weak. Only strong ligands can form bonds with d orbitals.
- VBT cannot explain the nature of the ligand.
- Complexes with unpaired electrons are paramagnetic and electrons with paired electrons are diamagnetic.
Previous Year Questions
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Sample Questions
Ques: What are the applications of Valence Bond Theory? (2 marks)
Ans: Valence Bond Theory is applicable to coordination compounds. It explains how electrons from the d- axis turn into an unhybridized d orbital. VBT helps in explaining the formation of covalent bonds for most of the complexes. It gives the idea of a more robust linkage. It helps in understanding the hybridization and geometry of the complex forms.
Ques: Compare molecular orbital theory with Valence Bond Theory. (3 marks)
Ans:
| Valence Bond Theory | Molecular Orbital Theory |
|---|---|
| The Valence bond theory is used to explain the chemical bonding in a given molecule. | MOT explains chemical bonding using hypothetical molecular orbitals. |
| It explains the hybrid orbitals | It explains bonding and anti-bonding molecular orbitals |
| It does not explain anything related to molecular orbitals. | This theory is based on molecular orbitals |
| It elaborates on the hybridization of the molecular orbitals. | Does not explain the hybridization of the orbitals. |
Ques: How many sigma and pi bonds are present in HCN? (1 mark)
Ans: H–C≡N is the structure. By looking at the structure we can make out that there are 2 sigma bonds and 2 pi bonds. 2 pi bonds suggest that there is a triple bond.
Ques: What is the orientation of the sigma and pi bond? (1 mark)
Ans: A sigma bonds show along the axis overlap and a pi bond shows sideways overlap.
Ques: Explain an example of an octahedral complex. (3 marks)
Ans: [Co(CN)6]3- ion
- In the given complex, the oxidation state of cobalt is +3.
- The electronic configuration for the valence shell of Co3+ is 3d6.
- CN is a strong ligand, thus capable of causing pairing in 3d-electrons.
- All 3d -electrons are paired and occupy three of the five 3d orbitals.
- The vacant 3d orbitals will combine with the 4s and 4p orbitals and thus form d2sp3 hybrid orbitals.
Ques: What is the hybridization and geometry of [CoCl4]2-? (1 mark)
Ans: The hybridization is sp3 and the geometry is tetrahedral.
Ques: What is hybridization? (2 marks)
Ans: the combining of the atomic orbitals that results in the production of a new orbital of different energies and shapes is called hybridization. All the hybrid orbitals have the same energies and shape.
Ques: What is the hybridization of [NiCl]2- ? (3 marks)
Ans: In [NiCl4]2-
- The oxidation state of Ni is +2.
- The electronic configuration of the valence shell is 3d8.
- As Cl is a weak ligand, no pairing of electrons can occur in the 3d orbitals.
- In this no 3d orbitals are vacant.
- Therefore, the vacant orbitals of 4s and 4p get combined and give four sp³ hybrid orbitals.
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