Valency of aluminium is

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The valency of aluminum (Al) can be calculated using the following steps:

  1. Determine the electron configuration of aluminum: The electron configuration of aluminum is [Ne] 3s2 3p1, where [Ne] represents the electron configuration of a neutral neon atom.
  2. Identify the number of electrons in the outermost shell: The outermost shell of aluminum is the third shell, and it contains three electrons (3s2 3p1).
  3. Calculate the valency: The valency of an element is the number of electrons it can gain, lose, or share to complete its outermost shell. In the case of aluminum, it has three electrons in its outermost shell, which means it needs to gain three electrons to complete its shell. Therefore, the valency of aluminum is 3.

In conclusion, the valency of aluminum is 3, as it can form three bonds with other elements in order to complete its outermost shell.

Valency of Aluminum

Valency of Aluminum

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CBSE CLASS XII Related Questions

  • 1.

    (i) Why do Zr and Hf exhibit similar properties ?

    (ii) "\( E^\circ \) for \( \mathrm{Mn^{3+}/Mn^{2+}} \) couple is more positive than that for \( \mathrm{Fe^{3+}/Fe^{2+}} \)." Justify the statement.

    [Atomic number : Mn = 25, Fe = 26]


      • 2.

        Conductivity of \( 2.5 \times 10^{-4} \) M methanoic acid solution is \( 5.25 \times 10^{-5} \) S cm\(^{-1}\).

        (a) Calculate its molar conductivity.

        (b) Calculate its degree of dissociation.

        [Given : \( \lambda^{\circ}_{(\mathrm{H^+})} = 349.5 \) S cm\(^2\) mol\(^{-1}\) and \( \lambda^{\circ}_{(\mathrm{HCOO^-})} = 50.5 \) S cm\(^2\) mol\(^{-1}\)]


          • 3.
            From the given data of \(E^{\circ}\) values, answer the following questions :
            (I) Why \(E^{\circ}_{M^{2+}/M}\) show irregular trend in the above values ?
            (II) Why is \(E^{\circ}_{Cu^{2+}/Cu}\) value exceptionally positive ?
            (III) Why \(E^{\circ}_{Mn^{2+}/Mn}\) value is highly negative ?


              • 4.
                Draw the structure of 'X' in the following reaction:


                  • 5.
                    Consider the decomposition of hydrogen peroxide \( (\mathrm{H_2O_2}) \) as per the equation given below : \[ 2\mathrm{H_2O_2} \xrightarrow[\text{Alkaline medium}]{I^-} 2\mathrm{H_2O} + \mathrm{O_2} \] The mechanism for this reaction was found to be : Step I : \( \mathrm{H_2O_2} + I^- \longrightarrow \mathrm{H_2O} + IO^- \) (slow) Step II : \( \mathrm{H_2O_2} + IO^- \longrightarrow \mathrm{H_2O} + I^- + \mathrm{O_2} \) (fast) (a) Write the rate law expression. (b) Determine the order of reaction with respect to \( \mathrm{H_2O_2} \), \( I^- \) and overall order of reaction. (c) What is the molecularity of the reaction in Step II ?


                      • 6.

                        (i) A first order reaction is 20% complete in 10 minutes. Calculate the time taken when 80% of the reaction will be completed.

                        [Given : log 5 = 0.7, log 4 = 0.6]

                        (ii) For a chemical reaction \( \mathrm{R \rightarrow P} \), variation in \( \ln[\mathrm{R}] \) vs. time (t) graph is given below :

                        (I) Predict the order of the reaction.

                        (II) Write the slope of the curve.



                          CBSE CLASS XII Previous Year Papers

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