If there are N nuclear particles in a nucleus of radius R then the number of nuclear particles in radius 3R will be?

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Jasmine Grover

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The number of nuclear particles in a nucleus is proportional to the volume of the nucleus. The volume of a sphere is given by:

V = (4/3)πr3

where r is the radius of the sphere.

If we assume that the nuclear particles are evenly distributed throughout the nucleus, then the number of nuclear particles is proportional to the volume of the nucleus. So, if there are N nuclear particles in a nucleus of radius R, then the number of nuclear particles in a nucleus of radius 3R would be proportional to the volume of the nucleus with a radius of 3R. The volume of a sphere with a radius of 3R is:

V = (4/3)π(3R)3

V = 27(4/3)πR3

So, the number of nuclear particles in a nucleus of radius 3R would be N' =

N' = N × (27(4/3)πR3)/(4/3)πR3

Simplifying, we get:

N' = 27N

Therefore, the number of nuclear particles in a nucleus of radius 3R would be 27 times the number of nuclear particles in a nucleus of radius R, assuming that the particles are evenly distributed throughout the nucleus.

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CBSE CLASS XII Related Questions

  • 1.
    A wire of length \(L\) is bent round into (i) a square coil having \(N\) turns and (ii) a circular coil having \(N\) turns. The coil in both cases is free to turn about a vertical axis coinciding with the plane of the coil, in a uniform, horizontal magnetic field and carry the same currents. Find the ratio of the maximum value of the torque acting on the square coil to that on the circular coil.


      • 2.

        The number of free electrons per unit volume ($\text{m}^3$) in a wire made of copper (resistivity $1.72 \times 10^{-8}\,\Omega\,\text{m}$) is $8.5 \times 10^{28}$. Calculate the average number of collisions made by an electron in one second when an electric field is maintained in the wire.


          • 3.
            Two point charges -Q and Q are located at points (d, 0) and (0, d) respectively, in x-y plane. The electric field E at the origin will be:

              • \(\frac{1}{4\pi\epsilon_0} \frac{\sqrt{2}Q}{d^2} (\hat{i} - \hat{j})\)
              • \(\frac{1}{4\pi\epsilon_0} \frac{\sqrt{2}Q}{d^2} (-\hat{i} - \hat{j})\)
              • \(\frac{1}{4\pi\epsilon_0} \frac{Q}{d^2} (\hat{i} - \hat{j})\)
              • \(\frac{1}{4\pi\epsilon_0} \frac{Q}{d^2} (-\hat{i} - \hat{j})\)

            • 4.

              A rectangular loop of size 5 cm $\times$ 8 cm is lying in the $x$-$y$ plane in a uniform magnetic field $\vec{B} = (2.0\ \text{T})\hat{k}$. The total magnetic flux linked with the loop is:

                • 80 Wb
                • 16 Wb
                • \(8 \times 10^{-2}\) Wb
                • \(8 \times 10^{-3}\) Wb

              • 5.

                A magnet held vertically, with its north pole down, is dropped along the axis of a closed solenoid placed vertically on a table. If the observer looks down from the top,

                  • the induced current will flow in the anticlockwise direction.
                  • the induced current will flow in the clockwise direction.
                  • no induced current will flow in the solenoid.
                  • the magnet will fall with a constant velocity.

                • 6.
                  Consider the nuclear reaction \( X \to Y + Z \). Let \( M_x \), \( M_y \), and \( M_z \) be the masses of the three nuclei X, Y, and Z respectively. Then which of the following relations hold true?

                    • \( (M_x - M_z)<M_y \)
                    • \( (M_x - M_y)<M_z \)
                    • \( M_x>(M_y + M_z) \)
                    • \( M_x<(M_y + M_z) \)
                  CBSE CLASS XII Previous Year Papers

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