If there are N nuclear particles in a nucleus of radius R then the number of nuclear particles in radius 3R will be?

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Jasmine Grover

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The number of nuclear particles in a nucleus is proportional to the volume of the nucleus. The volume of a sphere is given by:

V = (4/3)πr3

where r is the radius of the sphere.

If we assume that the nuclear particles are evenly distributed throughout the nucleus, then the number of nuclear particles is proportional to the volume of the nucleus. So, if there are N nuclear particles in a nucleus of radius R, then the number of nuclear particles in a nucleus of radius 3R would be proportional to the volume of the nucleus with a radius of 3R. The volume of a sphere with a radius of 3R is:

V = (4/3)π(3R)3

V = 27(4/3)πR3

So, the number of nuclear particles in a nucleus of radius 3R would be N' =

N' = N × (27(4/3)πR3)/(4/3)πR3

Simplifying, we get:

N' = 27N

Therefore, the number of nuclear particles in a nucleus of radius 3R would be 27 times the number of nuclear particles in a nucleus of radius R, assuming that the particles are evenly distributed throughout the nucleus.

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