NCERT Solutions For Class 10 Maths Chapter 14: Statistics

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NCERT Solutions for class 10 Maths Chapter 14 Statistics are provided in the article below. Some of the important topics of Statistics chapter include:

Expected no of questions: 2 to 3 questions of total 5 marks

Download PDF: NCERT Solutions for Class 10 Mathematics Chapter 14 pdf

NCERT Solutions for Class 10 Mathematics Chapter 14

NCERT Solutions for Class 10 Maths Chapter 14 Statistics is given below.

NCERT Solution class 10 mathematics chapter 14 statistics

Class 10 Mathematics Chapter 14 Statistics – Important Topics

Study of collection, presentation, organisation and analysis of data is known as Statistics.

Important formulas in Statistics include:

Mean x = ∑x / n

Median [if n is odd] = (n+1 /2)

Median [if n is even] = [(n/2)th + (n+1 /2)] / 2

Standard Deviation σ = √∑ni=1(xi-μμ)² /n

Variance σ² = ∑ni=1(xi-μμ)² /n

Average of a given set of numbers is known as the mean.
Middle Value in a given set of data is known as median.
Most Occurring item in a given set of data is known as mode.
A measure which gives an approximate idea about data is known as variance. It is used to calculate standard deviation of a data set.
We can find how far a value is from the mean by the help of Standard Deviation. It can be found by taking the square root of Variance.

NCERT Solutions for Class 10 Maths Chapter 14 Exercises

NCERT Solutions for Class 10 Mathematics Chapter 14 Statistics Exercises are given below.

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CBSE X Related Questions

1.
A kite is flying at a height of $60 \text{ m}$ above the ground level. Ravi, standing at the roof of the house is holding the string straight and observes the angle of elevation of kite as $30^{\circ}$. From the bottom of the same building, the angle of elevation of kite is $45^{\circ}$. Find the length of the string and height of roof from the ground. (Use $\sqrt{3} = 1.73$)
View Solution
2.
$ABCD$ is a parallelogram such that $AF = 7 \text{ cm}$, $FB = 3 \text{ cm}$ and $EF = 4 \text{ cm}$, length $FD$ equals
- $\frac{21}{4} \text{ cm}$
- $\frac{28}{3} \text{ cm}$
- $\frac{12}{7} \text{ cm}$
- $5.5 \text{ cm}$
View Solution
3.
A chord of a circle, of radius 14 cm, subtends an angle of $60^\circ$ at the centre. Find the area of the smaller sector and perimeter of the smaller segment.
View Solution
4.
The first term of an AP is $p$ and the common difference is $q$, then its 10th term is :
- $q - 9p$
- $p - 9q$
- $p + 9q$
- $2p + 9q$
View Solution
5.
Assertion (A) : H.C.F. $(36 m^{2}, 18 m) = 18 m$, where $m$ is a prime number.
Reason (R) : H.C.F. of two numbers is always less than or equal to the smaller number.
- Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of the Assertion (A).
- Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of the Assertion (A).
- Assertion (A) is true, but Reason (R) is false.
- Assertion (A) is false, but Reason (R) is true.
View Solution
6.
PQ and PR are two tangents to a circle with centre O and radius 5 cm. AB is another tangent to the circle at C which lies on OP. If $OP = 13$ cm, then find the length AB and PA.
View Solution

View All

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NCERT Solutions For Class 10 Maths Chapter 14: Statistics

Download PDF: NCERT Solutions for Class 10 Mathematics Chapter 14 pdf

NCERT Solutions for Class 10 Mathematics Chapter 14

Class 10 Mathematics Chapter 14 Statistics – Important Topics

NCERT Solutions for Class 10 Maths Chapter 14 Exercises

CBSE X Related Questions

2.
\(ABCD\) is a parallelogram such that \(AF = 7 \text{ cm}\), \(FB = 3 \text{ cm}\) and \(EF = 4 \text{ cm}\), length \(FD\) equals

3.
A chord of a circle, of radius 14 cm, subtends an angle of $60^\circ$ at the centre. Find the area of the smaller sector and perimeter of the smaller segment.

4.
The first term of an AP is $p$ and the common difference is $q$, then its 10th term is :

5.
Assertion (A) : H.C.F. \((36 m^{2}, 18 m) = 18 m\), where \(m\) is a prime number.
Reason (R) : H.C.F. of two numbers is always less than or equal to the smaller number.

6.
PQ and PR are two tangents to a circle with centre O and radius 5 cm. AB is another tangent to the circle at C which lies on OP. If \(OP = 13\) cm, then find the length AB and PA.

Similar Mathematics Concepts

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NCERT Solutions For Class 10 Maths Chapter 14: Statistics

Download PDF: NCERT Solutions for Class 10 Mathematics Chapter 14 pdf

NCERT Solutions for Class 10 Mathematics Chapter 14

Class 10 Mathematics Chapter 14 Statistics – Important Topics

NCERT Solutions for Class 10 Maths Chapter 14 Exercises

CBSE X Related Questions

2.\(ABCD\) is a parallelogram such that \(AF = 7 \text{ cm}\), \(FB = 3 \text{ cm}\) and \(EF = 4 \text{ cm}\), length \(FD\) equals

3.A chord of a circle, of radius 14 cm, subtends an angle of $60^\circ$ at the centre. Find the area of the smaller sector and perimeter of the smaller segment.

4.The first term of an AP is $p$ and the common difference is $q$, then its 10th term is :

5.Assertion (A) : H.C.F. \((36 m^{2}, 18 m) = 18 m\), where \(m\) is a prime number. Reason (R) : H.C.F. of two numbers is always less than or equal to the smaller number.

6.PQ and PR are two tangents to a circle with centre O and radius 5 cm. AB is another tangent to the circle at C which lies on OP. If \(OP = 13\) cm, then find the length AB and PA.

Similar Mathematics Concepts

Comments

SUBSCRIBE TO OUR NEWS LETTER

2.
\(ABCD\) is a parallelogram such that \(AF = 7 \text{ cm}\), \(FB = 3 \text{ cm}\) and \(EF = 4 \text{ cm}\), length \(FD\) equals

3.
A chord of a circle, of radius 14 cm, subtends an angle of $60^\circ$ at the centre. Find the area of the smaller sector and perimeter of the smaller segment.

4.
The first term of an AP is $p$ and the common difference is $q$, then its 10th term is :

5.
Assertion (A) : H.C.F. \((36 m^{2}, 18 m) = 18 m\), where \(m\) is a prime number.
Reason (R) : H.C.F. of two numbers is always less than or equal to the smaller number.

6.
PQ and PR are two tangents to a circle with centre O and radius 5 cm. AB is another tangent to the circle at C which lies on OP. If \(OP = 13\) cm, then find the length AB and PA.