NCERT Solutions for Class 10 Maths Chapter 2 Polynomials Exercise 2.1

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NCERT Solutions for Class 10 Maths Chapter 2 Polynomials Exercise 2.1 is given in this article with a step by step explanation. Chapter 2 Polynomials Exercise 2.1 covers different cases of the geometrical meaning of the zeroes of a polynomial. The exercise has 1 question with 6 cases and includes finding the zeroes of a polynomial through the graphical method.

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Class 10 Chapter 2 Polynomials Topics:

Degree of Polynomial	Parabola Graph	Polynomials Formula
Polynomials Important Questions	Polynomials Revision Notes	Cubic Polynomial
Roots of Polynomials	Vietas Formula	Difference between zeroes and coefficients

CBSE Class 10 Maths Study Guides:

Calculus	Math Formula	Math MCQs
Difference between in Maths	Math Study Notes	NCERT Solutions for Class 10 Maths
Mensuration	Arithmetic	Trigonometry

CBSE X Related Questions

1.
In the figure given above, $\triangle ABC \sim \triangle XYZ$, then find the values of $x$ and $y$.
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2.
The graph of $y = f(x)$ is given. The number of zeroes of $f(x)$ is :
- 0
- 1
- 3
- 2
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3.
If the quadratic equation $9x^2 + 8kx + 16 = 0$ has real and equal roots, then the value of k is
- 3
- –3
- –4
- $\pm 3$
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4.
If the zeroes of a polynomial p(x) are $-3$ and 8, then p(x) equals
- $x^2 + 5x - 4$
- $(x + 3) (-x + 8)$
- $a(x^2 + 5x - 24)$
- $x^2 - 24$
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5.
Assertion (A) : H.C.F. $(36 m^{2}, 18 m) = 18 m$, where $m$ is a prime number.
Reason (R) : H.C.F. of two numbers is always less than or equal to the smaller number.
- Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of the Assertion (A).
- Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of the Assertion (A).
- Assertion (A) is true, but Reason (R) is false.
- Assertion (A) is false, but Reason (R) is true.
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6.
If the pair of linear equations : $ a_1x + b_1y + c_1 = 0 $ and $ a_2x + b_2y + c_2 = 0 $ is consistent and dependent, then
- $ \frac{a_1}{a_2} \neq \frac{b_1}{b_2} $
- $ \frac{a_1}{a_2} = \frac{b_1}{b_2} = \frac{c_1}{c_2} $
- $ \frac{a_1}{a_2} = \frac{b_1}{b_2} \neq \frac{c_1}{c_2} $
- $ \frac{a_1}{a_2} = \frac{b_1}{b_2} = \frac{c_1}{c_2} $
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