NCERT Solutions for Class 10 Maths Chapter 2 Polynomials Exercise 2.1

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Jasmine Grover

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NCERT Solutions for Class 10 Maths Chapter 2 Polynomials Exercise 2.1 is given in this article with a step by step explanation. Chapter 2 Polynomials Exercise 2.1 covers different cases of the geometrical meaning of the zeroes of a polynomial. The exercise has 1 question with 6 cases and includes finding the zeroes of a polynomial through the graphical method.

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Class 10 Chapter 2 Polynomials Topics:

CBSE Class 10 Maths Study Guides:

CBSE X Related Questions

  • 1.
    The HCF of 960 and 432 is :

      • 48
      • 54
      • 72
      • 36

    • 2.
      PQ and PR are two tangents to a circle with centre O and radius 5 cm. AB is another tangent to the circle at C which lies on OP. If \(OP = 13\) cm, then find the length AB and PA.


        • 3.
          In the figure given above, \(\triangle ABC \sim \triangle XYZ\), then find the values of \(x\) and \(y\).


            • 4.
              In the given figure, \(AB \parallel DE\) and \(AC \parallel DF\). Show that \(\triangle ABC \sim \triangle DEF\). If \(BC = 10\) cm, \(EB = CF = 5\) cm and \(AB = 7\) cm, then find the length DE.


                • 5.
                  The graph of \(y = f(x)\) is given. The number of zeroes of \(f(x)\) is :

                    • 0
                    • 1
                    • 3
                    • 2

                  • 6.
                    The natural number 1 is :

                      • a prime number.
                      • a composite number.
                      • prime as well as composite.
                      • neither prime nor composite.

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