NCERT Solutions for Class 10 Maths Chapter 2 Polynomials Exercise 2.1

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Jasmine Grover

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NCERT Solutions for Class 10 Maths Chapter 2 Polynomials Exercise 2.1 is given in this article with a step by step explanation. Chapter 2 Polynomials Exercise 2.1 covers different cases of the geometrical meaning of the zeroes of a polynomial. The exercise has 1 question with 6 cases and includes finding the zeroes of a polynomial through the graphical method.

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Class 10 Chapter 2 Polynomials Topics:

CBSE Class 10 Maths Study Guides:

CBSE X Related Questions

  • 1.
    PQ and PR are two tangents to a circle with centre O and radius 5 cm. AB is another tangent to the circle at C which lies on OP. If \(OP = 13\) cm, then find the length AB and PA.


      • 2.
        In the given figure, \(AB \parallel DE\) and \(AC \parallel DF\). Show that \(\triangle ABC \sim \triangle DEF\). If \(BC = 10\) cm, \(EB = CF = 5\) cm and \(AB = 7\) cm, then find the length DE.


          • 3.
            A circle centered at (2, 1) passes through the points A(5, 6) and B(-3, K). Find the value(s) of K. Hence find length of chord AB.


              • 4.
                In the figure given above, \(\triangle ABC \sim \triangle XYZ\), then find the values of \(x\) and \(y\).


                  • 5.
                    The HCF of 960 and 432 is :

                      • 48
                      • 54
                      • 72
                      • 36

                    • 6.
                      If \(\alpha, \beta\) are the zeroes of the polynomial \(p(x) = x^2 - 3x - 1\), then find the value of \(\frac{1}{\alpha} + \frac{1}{\beta}\).

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