NCERT Solutions for Class 10 Maths Chapter 2 Polynomials Exercise 2.2

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NCERT Solutions for Class 10 Maths Chapter 2 Polynomials Exercise 2.2 covers different cases of the relationship between Zeroes and Coefficients of a Polynomial. The exercise has 2 questions with 6 cases each.

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Check out the solutions of Class 10 Maths NCERT solutions chapter 2 Polynomials Exercise 2.2

Read More: NCERT Solutions For Class 10 Maths Polynomials

Check out other exercise solutions of Class 10 Maths Chapter 2 Polynomials

Class 10 Chapter 2 Polynomials Topics:

Degree of Polynomial	Zeroes of a Polynomial	Polynomials Formula
Vietas Formula	Roots of Polynomials	Cubic Polynomial
Polynomials Revision Notes	Polynomials Important Questions	Parabola Graph

CBSE Class 10 Maths Study Guides:

Math Study Notes	Difference between in Maths	Math MCQs
Calculus	Math Formula	Mensuration
NCERT Solutions for Class 10 Maths	Arithmetic	Trigonometry

CBSE X Related Questions

1.
Assertion (A) : H.C.F. \((36 m^{2}, 18 m) = 18 m\), where \(m\) is a prime number.
Reason (R) : H.C.F. of two numbers is always less than or equal to the smaller number.
- Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of the Assertion (A).
- Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of the Assertion (A).
- Assertion (A) is true, but Reason (R) is false.
- Assertion (A) is false, but Reason (R) is true.
View Solution
2.
The graph of \(y = f(x)\) is given. The number of zeroes of \(f(x)\) is :
- 0
- 1
- 3
- 2
View Solution
3.
The first term of an AP is $p$ and the common difference is $q$, then its 10th term is :
- $q - 9p$
- $p - 9q$
- $p + 9q$
- $2p + 9q$
View Solution
4.
PQ and PR are two tangents to a circle with centre O and radius 5 cm. AB is another tangent to the circle at C which lies on OP. If OP = 13 cm, then find the length AB and PA.
View Solution
5.
Prove that :
\(\frac{\tan \theta}{1 - \cot \theta} + \frac{\cot \theta}{1 - \tan \theta} = 1 + \tan \theta + \cot \theta\).
View Solution
6.
If the zeroes of a polynomial p(x) are $-3$ and 8, then p(x) equals
- $x^2 + 5x - 4$
- $(x + 3) (-x + 8)$
- $a(x^2 + 5x - 24)$
- $x^2 - 24$
View Solution

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Polynomials: Definition, Types and Examples

Polynomials Important Questions

Roots of Polynomials: Definition, Formula & Solution

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