NCERT Solutions for Class 9 Maths Chapter 6 Exercise 6.2 Solutions

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NCERT Solutions for Class 9 Maths Chapter 6 Lines and Angles Exercise 6.2 Solutions are based on alternate interior angles, alternate exterior angles, corresponding angles, Interior angles on the same side of the transversal and more.

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Check out NCERT Solutions for Class 9 Maths Chapter 6 Exercise 6.2 Solutions

Exercise Solutions of Class 9 Maths Chapter 6 Lines and Angles

Also check other Exercise Solutions of Class 9 Maths Chapter 6 Lines and Angles

Also Check:

Important Chapter Related Topics
Pairs of Angles	Parallel Lines and a Transversal	Collinear Points
Vertex	Linear Pair Axiom	Transversal
Corresponding Angles Axiom	Alternate Angles	Properties of Parallel Lines
Angle Formula	Obtuse Angle	Class 9 Maths Chapter 6 Lines and Angles MCQs
Adjacent Angles Vertical	Linear Pair of Angles	Intersecting Lines and Non Intersecting Lines

Also check:

Math Study Guides
Maths Important Formulas	Maths MCQs	Comparison Articles in Maths
Difference Between Topics in Maths	Math Study Material	Algebra
Trigonometry	Number Systems	Mensuration
Math Formula	NCERT Solutions for Class 9 Maths	Geometry

CBSE X Related Questions

1.
Arc $PQ$ subtends an angle $\theta$ at the centre of the circle with radius $6.3 \text{ cm}$. If $\text{Arc } PQ = 11 \text{ cm}$, then the value of $\theta$ is
- $10^{\circ}$
- $60^{\circ}$
- $45^{\circ}$
- $100^{\circ}$
View Solution
2.
For an acute angle $\theta$, if $\sin \theta = \frac{1}{9}$, then value of $\frac{9 \csc \theta + 1}{9 \csc \theta - 1}$ is
- $0$
- $\frac{80}{81}$
- $1$
- $\frac{82}{80}$
View Solution
3.
The graph of a quadratic polynomial f(x) passes through (5,0), (0, -1) and (-2, 0). The two factors of the polynomial are
- $(x + 2), (x - 5)$
- $(x + 5), (x - 2)$
- $(x + 1), (x - 5)$
- $(x - 1), (x + 2)$
View Solution
4.
The value of $\left(\frac{1}{2} \tan^2 45^\circ - \cos^2 60^\circ\right)$ is :
- $0$
- $-\frac{1}{2}$
- $\frac{1}{4}$
- $-\frac{1}{4}$
View Solution
5.
Which of the following graphs represents a polynomial with both zeroes being positive?
View Solution
6.
If the zeroes of the polynomial $p(x) = 2x^2 - 7x + 6$ are $\alpha$ and $\beta$, then the value of $\frac{1}{\alpha} + \frac{1}{\beta}$ is
- $\frac{7}{2}$
- $\frac{6}{7}$
- $\frac{-7}{6}$
- $\frac{7}{6}$
View Solution

View All

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You can also check

NCERT Solutions for Class 9 Maths Chapter 6 Exercise 6.2 Solutions

Exercise Solutions of Class 9 Maths Chapter 6 Lines and Angles

CBSE X Related Questions

1.
Arc \(PQ\) subtends an angle \(\theta\) at the centre of the circle with radius \(6.3 \text{ cm}\). If \(\text{Arc } PQ = 11 \text{ cm}\), then the value of \(\theta\) is

2.
For an acute angle \(\theta\), if \(\sin \theta = \frac{1}{9}\), then value of \(\frac{9 \csc \theta + 1}{9 \csc \theta - 1}\) is

3.
The graph of a quadratic polynomial f(x) passes through (5,0), (0, -1) and (-2, 0). The two factors of the polynomial are

4.
The value of $\left(\frac{1}{2} \tan^2 45^\circ - \cos^2 60^\circ\right)$ is :

5.
Which of the following graphs represents a polynomial with both zeroes being positive?

6.
If the zeroes of the polynomial \(p(x) = 2x^2 - 7x + 6\) are \(\alpha\) and \(\beta\), then the value of \(\frac{1}{\alpha} + \frac{1}{\beta}\) is

Similar Mathematics Concepts

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NCERT Solutions for Class 9 Maths Chapter 6 Exercise 6.2 Solutions

Exercise Solutions of Class 9 Maths Chapter 6 Lines and Angles

CBSE X Related Questions

1.Arc \(PQ\) subtends an angle \(\theta\) at the centre of the circle with radius \(6.3 \text{ cm}\). If \(\text{Arc } PQ = 11 \text{ cm}\), then the value of \(\theta\) is

2.For an acute angle \(\theta\), if \(\sin \theta = \frac{1}{9}\), then value of \(\frac{9 \csc \theta + 1}{9 \csc \theta - 1}\) is

3.The graph of a quadratic polynomial f(x) passes through (5,0), (0, -1) and (-2, 0). The two factors of the polynomial are

4.The value of $\left(\frac{1}{2} \tan^2 45^\circ - \cos^2 60^\circ\right)$ is :

5.Which of the following graphs represents a polynomial with both zeroes being positive?

6.If the zeroes of the polynomial \(p(x) = 2x^2 - 7x + 6\) are \(\alpha\) and \(\beta\), then the value of \(\frac{1}{\alpha} + \frac{1}{\beta}\) is

Similar Mathematics Concepts

Comments

SUBSCRIBE TO OUR NEWS LETTER

1.
Arc \(PQ\) subtends an angle \(\theta\) at the centre of the circle with radius \(6.3 \text{ cm}\). If \(\text{Arc } PQ = 11 \text{ cm}\), then the value of \(\theta\) is

2.
For an acute angle \(\theta\), if \(\sin \theta = \frac{1}{9}\), then value of \(\frac{9 \csc \theta + 1}{9 \csc \theta - 1}\) is

3.
The graph of a quadratic polynomial f(x) passes through (5,0), (0, -1) and (-2, 0). The two factors of the polynomial are

4.
The value of $\left(\frac{1}{2} \tan^2 45^\circ - \cos^2 60^\circ\right)$ is :

5.
Which of the following graphs represents a polynomial with both zeroes being positive?

6.
If the zeroes of the polynomial \(p(x) = 2x^2 - 7x + 6\) are \(\alpha\) and \(\beta\), then the value of \(\frac{1}{\alpha} + \frac{1}{\beta}\) is