NCERT Solutions for Class 9 Maths Chapter 6 Exercise 6.2 Solutions

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NCERT Solutions for Class 9 Maths Chapter 6 Lines and Angles Exercise 6.2 Solutions are based on alternate interior angles, alternate exterior angles, corresponding angles, Interior angles on the same side of the transversal and more.

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CBSE X Related Questions

  • 1.
    If \(PQ\) and \(PR\) are tangents to the circle with centre \(O\) and radius \(4 \text{ cm}\) such that \(\angle QPR = 90^{\circ}\), then the length \(OP\) is

      • \(4 \text{ cm}\)
      • \(4\sqrt{2} \text{ cm}\)
      • \(8 \text{ cm}\)
      • \(2\sqrt{2} \text{ cm}\)

    • 2.
      It is given that \(\triangle ABC \sim \triangle EDF\). Which of the following is not true?

        • \(\frac{\text{Perimeter of } \triangle ABC}{\text{Perimeter of } \triangle EDF} = \frac{AB}{ED}\)
        • \(\frac{AB}{ED} = \frac{AC}{EF}\)
        • \(\angle A = \angle D, \angle C = \angle F\)
        • \(\frac{AB + BC}{AC} = \frac{ED + DF}{EF}\)

      • 3.
        Arc \(PQ\) subtends an angle \(\theta\) at the centre of the circle with radius \(6.3 \text{ cm}\). If \(\text{Arc } PQ = 11 \text{ cm}\), then the value of \(\theta\) is

          • \(10^{\circ}\)
          • \(60^{\circ}\)
          • \(45^{\circ}\)
          • \(100^{\circ}\)

        • 4.
          In an A.P., if $a_{14} - a_8 = 24$, then the common difference of the A.P. is

            • $6$
            • $4$
            • $\pm 4$
            • $3$

          • 5.
            For an acute angle \(\theta\), if \(\sin \theta = \frac{1}{9}\), then value of \(\frac{9 \csc \theta + 1}{9 \csc \theta - 1}\) is

              • \(0\)
              • \(\frac{80}{81}\)
              • \(1\)
              • \(\frac{82}{80}\)

            • 6.
              The value of k for which sum of the zeroes of the polynomial \(p(x) = 3x^2 - kx + 6\) is 2, is

                • 2
                • \(-6\)
                • \(-2\)
                • 6

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