Unit of Power: Conversion, SI and Other units of Power

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Jasmine Grover

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The unit of Power is represented as Watt. In physics, power is referred to as the time rate of doing work or delivering energy, which is expressed as the amount of work done W (energy transferred), divided by the time interval t. A certain amount of work can be done either by a low-powered motor for a long time or by a high-powered motor in a short time. 

  • The unit of power is the watt (symbol: W).
  • One watt is the amount of power required to do one joule of work in one second.
  • If a device uses one watt of power, it consumes energy at a rate of one joule per second.

Key Terms:  Power, Energy transfer, Unit of Power, Horsepower, CGS system, Energy, Joules, Work Done


What is Power? 

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Power is the rate at which energy is transferred or converted or the rate of doing work. Technically it is the amount of work done per unit of time. The SI unit of power is Watt (W) which is joules per second (J/s). Sometimes the power of motor vehicles and other machines is expressed in terms of Horsepower (hp), which is approximately equal to 745.7 watts.

  • Power can also be related to other things or situations, for example, the power that helps various things move around.
  • Power can also be described as the product of a specific force on an object and its velocity.
  • It is a scalar quantity, which means that it gives us a quantity or amount of energy consumed per unit of time but with no indication of direction.

Power

Power

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Power Formula

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Power is referred to as the rate at which work is done upon an object. It is a time-based quantity that is related to how fast a job is done. The formula for power is as below:

Power = Work/time

P = W / t


SI Unit of Power

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The SI Unit of power is Watt (W). One joule of energy transferred in a second is equal to 1 watt. 

1 Watt = 1 J/s = 1 kg-m2/s3

As the metric system is divided into base units and derived units, when we convert joules into base units we get ( kg-m2/s2 ). It is used to find out the conversion of watts into base units.

  • Watt is named after James Watt, who was an 18th-century inventor who had invented and patented many important instruments by his name.
  • Before Watt became the SI unit of power, Horsepower was used as a unit of power. But the horsepower is a very large unit, so to find a smaller unit of power, the unit watt was introduced.
  • 1 Horsepower = 735.499 Watt
  • The relation between units of Power:1 kW = 1000W, 1 MW = 1000000W and 1GW = 1000000000W
  • In the MKS system, the unit of power is: kgm2s-3
  • In the CGS system, the unit of power is erg per second.
  • As power is needed to be measured in different areas of science and engineering. So to make things simpler there are many submultiples and multipliers of Watt.

Other Units of Power

ts of power Although the watt is the standard unit of power, other units are commonly used in various applications. Some of these units include horsepower, kilowatt, and megawatt.

  • Horsepower is a unit of power commonly used in the automotive industry to describe the power output of engines. One horsepower is equal to 746 watts.
  • Kilowatt is a unit of power commonly used in electrical applications. One kilowatt is equal to 1000 watts.
  • Megawatt is a unit of power commonly used in power plants and other large-scale applications. One megawatt is equal to one million watts.

Also Read: Electrical Power Formula


Submultiples of Watt

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Here are some important submultiples of Watt-

Name of the unit of Power Symbol Value
Deciwatt dW 10-1W
centiwatt cW 10-2W
milliwatt mW 10-3W
microwatt µW 10-6W
nanowatt nW 10-9W
picowatt pW 10-12W
Femtowatt fW 10-15W
attowatt aW 10-18W
zeptowatt zW 10-21W
Yoctowatt yW 10-24W

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Multipliers of Watt

Here are the multipliers of Watts-

Names  Symbol  Value
Decawatt daW 101 W
Hectowatt hW 102 W
Kilowatt kW 103 W
Megawatt MW 106 W
Gigawatt GW 109 W
Terawatt TW 1012 W
Petawatt PW 1015 W
Exwatt EW 1018 W
Zettawatt ZW 1021 W
Yottawatt YW 1024 W

Units of Power in Other Systems and their Equivalent in Watts

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Here is the relation of the Units of Power with other systems and their equivalent in Watts-

Unit  Equivalent in Watt
Horsepower (Hp) 746 W
British Thermal Unit (BTU) 1 Watt = 9.47 * 10-4 BTU
Foot Pounds 1 Watt = 0.737 foot-pounds
Calories per second 1 Watt = 0.24 calories per second

Also Read: Unit of Light


How to Measure Variable Power?

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To measure variable power 3 methods are used: 

  1. Instantaneous Power – This is the power measured at a given instance of time. For calculating such power high-level mathematical instruments are needed to be used.
  2. Average power – When power is measured for a long period of time, the average of it can find out. The average of power can find out by adding the power of different points of time and then dividing the sum with time.
  3. Peak Power – The maximum amount of instantaneous power a machine or system can reach, over a long period of time is called peak power. Peak power is much higher than average power and is maintained for a very short period of time to avoid any damage.

Uses of the Unit of Power

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Here are the important uses of the Unit of Power-

  1. Unit of power can be used in other electrical measurements. Electrical measurements are usually done with the unit- Horses and 1 Watts is equal to 0.74549 Horses.
  2. While Voltage is usually measured with the unit of volts, we can solve other equations related to this with the unit of power because 1 Watt is equal to 1 volt.
  3. Measuring amperes can also be done with the measurement of power because 1 watt is equal to 0.001335 amperes.

Also Read: 


Things to Remember

  • Power is the rate at which energy is transferred or Converted or the rate of doing work. 
  • SI Unit of power is Watt; 1 Watt = 1 J/s = 1 kg -m2/s3
  • 1 watt is equal to 1 joule of work done in 1 second. 
  • Watt is named after the famous inventor James Watt.
  • Watt is a scalar quantity, which means it doesn’t contain direction.
  • The formula for power is Power = Work / time; P = W / t.
  • Other units of power, such as horsepower, kilowatt, and megawatt, are commonly used in various applications. 
  • In the MKS system, the unit of power is kgm2s-3
  • In the CGS system, the unit of power is erg per second.

Sample Questions

Ques: State the relation between the units of power. (1 mark)

Ans: 1 kW = 1000W, 1 MW = 1000000W and 1GW = 1000000000W.

Ques: How big is Watt as compared to Joule? (1 mark)

Ans: Joule is very small as compared to Watt. Joule is the 3600th part of a watt-hour.

Ques: What is the biggest multiple of Watt? (1 mark)

Ans: The biggest multiplier of watts is yottawatt and it is 1024 times watt.

Ques: What is Horsepower? (2 marks)

Ans: Horse Power (HP) is another unit of Power, which is largely used in mechanical engineering. It is also useful in describing the output of automobiles, motorbikes, aeroplanes, etc.

Ques: Explain in depth why there are so many multiples and submultiples of Watt. (3 marks)

Ans: The application of the concept of power is everywhere from atomic science to rocket science, from drones to fighter jets, so when some concept is applied to so many differing areas you can not standardize the same unit for every area of use. To facilitate research watt is selected as a unit of power, which is a unit quantity of power, and to facilitate usability many micro and macro units are also defined in terms of a watt. 

Ques: What is the unit of power used in electric physics? (2 marks)

Ans: In electro physics, the power is equal to the voltage multiplied by charge and divided by time. 

P = V.Q/T

Where 

V = voltage , SI unit = Volt 

Q = Charge , SI unit = Coulomb 

T = Time , SI unit = second 

So the unit of power in electro physics will be v.c/s.

Ques:  A 60-watt bulb is switched on 24 hours per day and there is another 60-watt bulb that is turned on for only 12 hours. Calculate the energy consumed by both bulbs in one day. (4 marks)

Ans: For the first 12 hours, both bulbs A and B are turned on, thus,

Power = 60 + 60 = 120 watts

Energy = Power x Time

= 120 x 12

= 1.44 kWh (kilowatt-hour)

Now, for the next 12 hours, only bulb A would remain on, therefore,

Power = 60 watts

Energy = 60 x 12 = 0.72 kW h

Now,

Average Power = Total energy consumed / Total time taken

Therefore, the average power for our light bulbs will be,

= (1.44 + 0.72) / 24

= 0.092 kW

Ques: State and define the SI unit of power. (2 marks)

Ans: The SI Unit of power is Watt (W). One joule of energy transferred in a second is equal to 1 watt. 

1 Watt = 1 J/s = 1 kg -m2/s3

As the metric system is divided into base units and derived units when we convert joules into base units we get (kg -m2/s2). Which is used to find out the conversion of watts into base units.

Ques: How can varying power be measured? (3 marks)

Ans: The measurement of varying power depends on the specific context and application. In general, power is the rate at which energy is transferred or used over time, and it is often measured in watts (W).

If you want to measure the power of a fluctuating electrical signal, you can use an oscilloscope or a power meter that is designed to measure AC (alternating current) power. These devices can give you a real-time reading of the instantaneous power of the signal.

If you want to measure the power output of a machine that operates over a range of speeds or loads, you may need to use a dynamometer or a similar device that can measure torque and rotational speed. From these measurements, you can calculate the mechanical power output of the machine.

In some cases, you may need to measure the power consumption of a device or system, which can be done using a wattmeter or similar device. This can help you determine how much energy is being used over a given period of time.

Overall, the specific method for measuring varying power will depend on the type of power being measured and the specific application.

Ques: What is Joule? (3 marks)

Ans: Joule refers to the SI unit of work or energy which is equal to work done by a force of 1 Newton to move the point of application, 1 m in the direction where the force is acting. 1 Joule is equivalent to 3600th of a watt-hour and is approximately the amount of energy required to lift an apple against the Earth’s gravity by a distance of 1 m.


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CBSE CLASS XII Related Questions

  • 1.
    If both the number of protons and the neutrons are conserved in each nuclear reaction, in what way is mass converted into energy (or vice versa) in a nuclear reaction? Explain.


      • 2.
        Assertion (A) : All atoms have a net magnetic moment. Reason (R) : A current loop does not always behave as a magnetic dipole.

          • Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of the Assertion (A).
          • Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of the Assertion (A).
          • Assertion (A) is true, but Reason (R) is false.
          • Both Assertion (A) and Reason (R) are false.

        • 3.
          The figure shows three point charges kept at the vertices of triangle ABC. The net electric field, due to this system of charges, at the midpoint M of base BC will be:

            • \( \frac{q}{4 \pi \epsilon_0 l^2} \) pointing along MA
            • \( \frac{q}{\pi \epsilon_0 l^2} \) pointing along AM
            • \( \frac{q}{2 \pi \epsilon_0 l^2} \) pointing along AM
            • Zero

          • 4.
            Four independent waves are expressed as \[ (i)\; y_1=A_1\sin\omega t, \] \[ (ii)\; y_2=A_2\sin 2\omega t, \] \[ (iii)\; y_3=A_3\cos\omega t, \] \[ (iv)\; y_4=A_4\sin\left(\omega t+\frac{\pi}{3}\right) \] The interference between two of these waves is possible in

              • (i) and (iii) only
              • (iii) and (iv) only
              • (i), (iii) and (iv) only
              • All of them

            • 5.
              A long solenoid of length \( L \) and radius \( r_1 \) having \( N_1 \) turns is surrounded symmetrically by a coil of radius \( r_2 \, (r_2>r_1) \) having \( N_2 \) turns (\( N_2 \ll N_1 \)) around its mid-point. Derive an expression for the mutual inductance of solenoid and coil. Is \( M_{12} = M_{21} \) valid in this case?


                • 6.
                  If Bohr’s quantization postulate (angular momentum \( = \frac{nh}{2\pi} \)) is a basic law of nature, it should be equally valid for the case of planetary motion also. Why, then, do we never speak of quantization of orbits of planets around the Sun? Explain.

                    CBSE CLASS XII Previous Year Papers

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