The Ampere Maxwell Law for the region having point Y is

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Question: The Ampere Maxwell Law for the region having point Y is:

In the given question, we have to write Ampere Maxwell's law for the field containing point Y. For this, we have to first apply the modified Ampere's circuital law which is expressed as:

$∮ \overrightarrow{B}.\overrightarrow{dl} = μ_0 (i_c + i_d) $------(i)

Where,

i_c is the conduction current,
i_d is the displacement current,
$\overrightarrow{B}$ is the magnetic induction at any point, and
$\overrightarrow{dl}$ is the path length.

In the given question, in the region having point Y, i_c=0, so,

$∮ \overrightarrow{B}.\overrightarrow{dl} = μ_0 i_d $

Therefore, Ampere Maxwell Law for the region having point Y is $∮ \overrightarrow{B}.\overrightarrow{dl} = μ_0 i_d $

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Topic and Chapter Related Links
Magnetic Spectrum	Faraday's Law	Magnetic Properties of Materials
Magnetisation and Magnetic Intensity	NCERT Solutions Chapter 4 Moving Charges and Magnetism	Gauss’s Law
Magnetism and matter	Magnetic Properties	Magnetic Field
Gauss law for magnetism	Farday's Law of Electromagnetic Induction	Cyclotron
Applications of Gauss’s Law	Earth’s Magnetic field	Inductance Formula

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The Ampere Maxwell Law for the region having point Y is

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1.
The number of free electrons per unit volume ($\text{m}^3$) in a wire made of copper (resistivity $1.72 \times 10^{-8}\,\Omega\,\text{m}$) is $8.5 \times 10^{28}$. Calculate the average number of collisions made by an electron in one second when an electric field is maintained in the wire.

2.
In a region, the electric potential varies as \(V = 10 - 50x\), where \(V\) is in volts and \(x\) is in meters. The electric field in the region is

4.
Two point charges -Q and Q are located at points (d, 0) and (0, d) respectively, in x-y plane. The electric field E at the origin will be:

5.
A square loop of side 0.50 m is placed in a uniform magnetic field of 0.4 T perpendicular to the plane of the loop. The loop is rotated through an angle of $60^\circ$ in 0.2 s. The value of emf induced in the loop will be:

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A ray of light MN is incident normally on the face corresponding with side AB of a prism with an isosceles right-angled triangular base ABC. Trace the path of the ray as it passes through the prism when the refractive index of the prism material is (i) $\sqrt{2}$, and (ii) $\sqrt{3}$.

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The Ampere Maxwell Law for the region having point Y is

CBSE CLASS XII Related Questions

1.The number of free electrons per unit volume ($\text{m}^3$) in a wire made of copper (resistivity $1.72 \times 10^{-8}\,\Omega\,\text{m}$) is $8.5 \times 10^{28}$. Calculate the average number of collisions made by an electron in one second when an electric field is maintained in the wire.

2.In a region, the electric potential varies as \(V = 10 - 50x\), where \(V\) is in volts and \(x\) is in meters. The electric field in the region is

4.Two point charges -Q and Q are located at points (d, 0) and (0, d) respectively, in x-y plane. The electric field E at the origin will be:

5.A square loop of side 0.50 m is placed in a uniform magnetic field of 0.4 T perpendicular to the plane of the loop. The loop is rotated through an angle of $60^\circ$ in 0.2 s. The value of emf induced in the loop will be:

6.A ray of light MN is incident normally on the face corresponding with side AB of a prism with an isosceles right-angled triangular base ABC. Trace the path of the ray as it passes through the prism when the refractive index of the prism material is (i) $\sqrt{2}$, and (ii) $\sqrt{3}$.

Similar Physics Concepts

Comments

SUBSCRIBE TO OUR NEWS LETTER

1.
The number of free electrons per unit volume ($\text{m}^3$) in a wire made of copper (resistivity $1.72 \times 10^{-8}\,\Omega\,\text{m}$) is $8.5 \times 10^{28}$. Calculate the average number of collisions made by an electron in one second when an electric field is maintained in the wire.

2.
In a region, the electric potential varies as \(V = 10 - 50x\), where \(V\) is in volts and \(x\) is in meters. The electric field in the region is

4.
Two point charges -Q and Q are located at points (d, 0) and (0, d) respectively, in x-y plane. The electric field E at the origin will be:

5.
A square loop of side 0.50 m is placed in a uniform magnetic field of 0.4 T perpendicular to the plane of the loop. The loop is rotated through an angle of $60^\circ$ in 0.2 s. The value of emf induced in the loop will be:

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A ray of light MN is incident normally on the face corresponding with side AB of a prism with an isosceles right-angled triangular base ABC. Trace the path of the ray as it passes through the prism when the refractive index of the prism material is (i) $\sqrt{2}$, and (ii) $\sqrt{3}$.